Chapter SH, Problem 6.3.15EP

To determine

The solution of the given equations.

Answer to Problem 6.3.15EP

  $\begin{array}{l}x=3\\ y=3\end{array}$

Explanation of Solution

Given:

The given equations are:

  $\begin{array}{l}2x-y=\mathrm{3...................}\left(1\right)\\ \frac{2}{3}x-y=-\mathrm{1................}\left(2\right)\end{array}$

Calculation:

Subtract equation 2 from equation 1,

  $\begin{array}{l}2x-y-\frac{2}{3}x+y=3-\left(-1\right)\\ \frac{4x}{3}=4\\ x=3\end{array}$

Put this in equation 1,

  $\begin{array}{l}2x-y=3\\ 2\left(3\right)-y=3\\ y=6-3\\ y=3\end{array}$