Chapter SH, Problem 24.8APP

To determine

To calculate: The number of transistors an integrated circuit contained in 2008.

Answer to Problem 24.8APP

The number of transistors an integrated circuit contained in 2008 is $\underset{\_}{25600000}$ .

Explanation of Solution

Given:

The number of transistors and other components per ${\text{mm}}^2$ on an integrated circuit doubled every two years.

Number of transistors in the integrated circuit in 1992 = $100,000$

Calculation:

Number of years between 2008 and 1992 = $2008-1992=16$

Since number of transistors doubled every two years, the number of transistors will become double for $\frac{16}{2}=8$ times.

Therefore, number of transistors the circuit contained in 2008 = $100,000\times 2^8=25600000$

Conclusion:

The number of transistors an integrated circuit contained in 2008 is $\underset{\_}{25600000}$ .