Chapter SH, Problem 6.10APP

To determine

To calculate: Resistance of a lightbulb.

Answer to Problem 6.10APP

Resistance of the lightbulb is $\underset{\_}{240\Omega }$ .

Explanation of Solution

Given:

Voltage difference = $\text{120 V}$

Current = $\text{0}\text{.50 A}$

Formula used:

Current is given by,

  $I=\frac{V}{R}$

where V is voltage difference and R is resistance.

Calculation:

Resistance is calculated as:

  $\begin{array}{l}I=\frac{V}{R}\\ R=\frac{V}{I}\\ R=\frac{\text{120 V}}{\text{0}\text{.50 A}}\\ R=240\Omega \end{array}$

Conclusion:

Resistance of the lightbulb is $\underset{\_}{240\Omega }$ .