Chapter SH, Problem 14.8APP

To determine

To calculate: Initial pressure on a weather balloon.

Answer to Problem 14.8APP

Initial pressure of the balloon is $\underset{\_}{\text{112 kPa}}$ .

Explanation of Solution

Given:

Initial volume = $\text{850 L}$

Final pressure = $\text{56 kPa}$

Final volume = $1700\text{ L}$

Formula used:

Boyle’s law equation is given by,

  $P_{\text{i}}{V}_{\text{i}}=P_{\text{f}}{V}_{\text{f}}$

Where $P_{\text{i}}$ is initial pressure, $V_{\text{i}}$ is initial volume, $P_{\text{f}}$ is final pressure and $V_{\text{f}}$ is final volume.

Calculation:

Initial pressure is calculated as:

  $\begin{array}{l}{P}_{\text{i}}{V}_{\text{i}}=P_{\text{f}}{V}_{\text{f}}\\ P_{\text{i}}=\frac{P_{\text{f}}{V}_{\text{f}}}{V_{\text{i}}}\\ P_{\text{i}}=\frac{\left(\text{56 kPa}\right)\left(\text{1700 L}\right)}{\left(\text{850 L}\right)}\\ P_{\text{i}}=112\text{ kPa}\end{array}$

Conclusion:

Initial pressure of the balloon is $\underset{\_}{\text{112 kPa}}$ .