Chapter SH, Problem 19.9APP

To determine

To calculate: Energy released per gram of the mixture.

Answer to Problem 19.9APP

Amount of energy released per gram of the mixture is $\underset{\_}{47.95\text{ kJ}}$ .

Explanation of Solution

Given:

Energy released when ${\text{CH}}_4$ is burned = $50.1\text{ kJ}$

Energy released when ${\text{C}}_3{\text{H}}_8$ is burned = $\text{45}\text{.8 kJ}$

A mixture of $1.0\text{ g}$ of methane and $1.0\text{ g}$ of propane is burned.

Calculation:

Amount of energy released when a mixture of $2.0\text{ g}$ ( $1.0\text{ g}$ of methane and $1.0\text{ g}$ of propane) is burned = $50.1\text{ kJ}+45.8\text{ kJ = 95}\text{.9 kJ }$ .

Therefore, the amount of energy released per gram of the mixture = $\frac{\text{95}\text{.9 kJ }}{2}=47.95\text{ kJ}$ .

Conclusion:

The amount of energy released per gram of the mixture is $\underset{\_}{47.95\text{ kJ}}$ .