Chapter SH, Problem 14.10APP

To determine

To calculate: Volume of a gold bar.

Answer to Problem 14.10APP

Volume of the gold bar is $\underset{\_}{\text{89}{\text{.6 cm}}^3}$ .

Explanation of Solution

Given:

Weight = $17.0\text{ N}$

Density = $19.3{\text{ g/cm}}^3$

Formula used:

Density is given by,

  $D=\frac{m}{V}$

Where m is mass and V is volume.

Force is given by,

  $F=mg$

where m is mass and $g=9.8\text{ N/kg}$is acceleration due to gravity.

Calculation:

Mass is calculated as:

  $\begin{array}{l}F=mg\\ m=\frac{F}{g}\\ m=\frac{17.0\text{ N}}{9.8\text{ N/kg}}\\ m=1.73\text{ kg}\end{array}$

Volume is calculated as:

  $\begin{array}{l}D=\frac{m}{V}\\ V=\frac{m}{D}\\ V=\frac{\text{1}\text{.73}\times \text{1000 g}}{\text{19}{\text{.3 g/cm}}^3}\\ V=89.6{\text{ cm}}^3\end{array}$

Conclusion:

Volume of the gold bar is $\underset{\_}{\text{89}{\text{.6 cm}}^3}$ .