Chapter SH, Problem 19.1APP

To determine

To calculate: Mass of ${\text{Li}}_2\text{O}$ formed.

Answer to Problem 19.1APP

Mass of ${\text{Li}}_2\text{O}$ formed is 59.8 g .

Explanation of Solution

Given:

The following reaction:

  $4\text{Li}+{\text{O}}_2\to 2{\text{Li}}_2\text{O}$

Mass of Li = $\text{27}\text{.8 g}$

Mass of ${\text{O}}_2$ = $\text{32}\text{.0 g}$

Formula used:

According to law of conservation of mass,

Total mass of reactants = Total mass of products

Calculation:

So,

Mass of Li + Mass of ${\text{O}}_2$ = Mass of ${\text{Li}}_2\text{O}$

Therefore, Mass of ${\text{Li}}_2\text{O}$ = $27.8\text{ g}+\text{32 g = 59}\text{.8 g}$

Conclusion:

Mass of ${\text{Li}}_2\text{O}$ formed is 59.8 g.