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Concept explainers
To Establish:The formula for lead (IV) oxide.
![Check Mark](/static/check-mark.png)
Answer to Problem 18.7APP
For lead (IV) oxide the formula is
Explanation of Solution
Introduction:
The symbol and oxidation number of the positive ion:
Lead (IV):
The symbol and oxidation number of the negative ion:
Oxygen:
First write the
Without the sign, one ion’s charge forms the subscript of the other.
The subscripts should be the lowest whole numbers that maintain the ratio of the ions:
By determining whether the compound is neutral the formula obtained can be checked. The charge on one lead (IV) ions is
Conclusion:
Forlead (IV) oxidethe formula is
Chapter SH Solutions
Glencoe Physical Science 2012 Student Edition (Glencoe Science) (McGraw-Hill Education)
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