Direction fields A differential equation and its direction field are shown in the following figures. Sketch a graph of the solution curve that passes through the given initial conditions. 5. y ′ ( t ) = t 2 y 2 + 1 , y ( 0 ) = − 2 and y (–2) = 0.
Direction fields A differential equation and its direction field are shown in the following figures. Sketch a graph of the solution curve that passes through the given initial conditions. 5. y ′ ( t ) = t 2 y 2 + 1 , y ( 0 ) = − 2 and y (–2) = 0.
Solution Summary: The author illustrates the graph of the solution curve of a given differential equation which passes through the given initial condition.
Direction fieldsA differential equation and its direction field are shown in the following figures. Sketch a graph of the solution curve that passes through the given initial conditions.
5.
y
′
(
t
)
=
t
2
y
2
+
1
,
y
(
0
)
=
−
2
and y(–2) = 0.
With integration, one of the major concepts of calculus. Differentiation is the derivative or rate of change of a function with respect to the independent variable.
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