Verifying general solutions Verify that the given function is a solution of the differential equation that follows it. 47. u ( t ) = C 1 t 2 + C 2 t 3 ; t 2 u ″ ( t ) − 4 t u ′ ( t ) + 6 u ( t ) = 0
Verifying general solutions Verify that the given function is a solution of the differential equation that follows it. 47. u ( t ) = C 1 t 2 + C 2 t 3 ; t 2 u ″ ( t ) − 4 t u ′ ( t ) + 6 u ( t ) = 0
Solution Summary: The author explains that the given function u(t)=C_1t
Verifying general solutionsVerify that the given function is a solution of the differential equation that follows it.
47.
u
(
t
)
=
C
1
t
2
+
C
2
t
3
;
t
2
u
″
(
t
)
−
4
t
u
′
(
t
)
+
6
u
(
t
)
=
0
With integration, one of the major concepts of calculus. Differentiation is the derivative or rate of change of a function with respect to the independent variable.
University Calculus: Early Transcendentals (4th Edition)
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