Organic Chemistry: Principles and Mechanisms (Second Edition)
Organic Chemistry: Principles and Mechanisms (Second Edition)
2nd Edition
ISBN: 9780393663556
Author: Joel Karty
Publisher: W. W. Norton & Company
bartleby

Concept explainers

Question
Book Icon
Chapter B, Problem B.1P
Interpretation Introduction

(a)

Interpretation:

The root for the given molecule is to be determined.

Concept introduction:

In case of molecules containing a C=C  or CC bond, the longest continuous carbon chain or largest ring that contains the double or triple bond is considered the root. It is possible that the longest carbon chain has more carbons than specified by the root. But the double or triple bond must be a part of the root. The root is named from the name of the analogous alkane or cycloalkane by replacing the suffix ane by ene if a double bond is present. The suffix ane is replaced by yne if a triple bond is present.

Expert Solution
Check Mark

Answer to Problem B.1P

The root for the given molecule is cyclohexene.

Explanation of Solution

The given molecule is

Organic Chemistry: Principles and Mechanisms (Second Edition), Chapter B, Problem B.1P , additional homework tip  1

In this molecule, the largest ring containing the double bond has six carbon atoms. Hence, the root is cyclohexene, as shown below.

Organic Chemistry: Principles and Mechanisms (Second Edition), Chapter B, Problem B.1P , additional homework tip  2

Conclusion

The root is determined from the longest carbon chain or the largest ring containing the double or triple bond between the carbon atoms.

Interpretation Introduction

(b)

Interpretation:

The root for the given molecule is to be determined.

Concept introduction:

In case of molecules containing a C=C  or CC bond, the longest continuous carbon chain or largest ring that contains the double or triple bond is considered the root. It is possible that the longest carbon chain has more carbons than specified by the root. But the double or triple bond must be a part of the root. The root is named from the name of the analogous alkane or cycloalkane by replacing the suffix ane by ene if a double bond is present. The suffix ane is replaced by yne if a triple bond is present.

Expert Solution
Check Mark

Answer to Problem B.1P

The root for the given molecule is ethene.

Explanation of Solution

The given molecule is

Organic Chemistry: Principles and Mechanisms (Second Edition), Chapter B, Problem B.1P , additional homework tip  3

In this molecule, the double bond is a part of the chain attached to the ring. Although the ring has more carbon atoms than the side chain, the ring does not contain a C=C  bond. Hence, the side chain containing the double bond is the root. It has two carbon atoms. Hence, the root is ethene, as shown below.

Organic Chemistry: Principles and Mechanisms (Second Edition), Chapter B, Problem B.1P , additional homework tip  4

Conclusion

The root is determined from the longest carbon chain or the largest ring containing the double or triple bond between the carbon atoms.

Interpretation Introduction

(c)

Interpretation:

The root for the given molecule is to be determined.

Concept introduction:

In case of molecules containing a C=C  or CC bond, the longest continuous carbon chain or largest ring that contains the double or triple bond is considered the root. It is possible that the longest carbon chain has more carbons than specified by the root. But the double or triple bond must be a part of the root. The root is named from the name of the analogous alkane or cycloalkane by replacing the suffix ane by ene if a double bond is present. The suffix ane is replaced by yne if a triple bond is present.

Expert Solution
Check Mark

Answer to Problem B.1P

The root for the given molecule is propyne.

Explanation of Solution

The given molecule is

Organic Chemistry: Principles and Mechanisms (Second Edition), Chapter B, Problem B.1P , additional homework tip  5

In this molecule, the triple bond is a part of the chain attached to the ring. Although the ring has more carbon atoms than the side chain, the ring does not contain a CC bond. Hence, the side chain containing the triple bond is the root. It has three carbon atoms. Hence, the root is propyne, as shown below.

Organic Chemistry: Principles and Mechanisms (Second Edition), Chapter B, Problem B.1P , additional homework tip  6

Conclusion

The root is determined from the longest carbon chain or the largest ring containing the double or triple bond between the carbon atoms.

Interpretation Introduction

(d)

Interpretation:

The root for the given molecule is to be determined.

Concept introduction:

In case of molecules containing a C=C  or CC bond, the longest continuous carbon chain or largest ring that contains the double or triple bond is considered the root. It is possible that the longest carbon chain has more carbons than specified by the root. But the double or triple bond must be a part of the root. The root is named from the name of the analogous alkane or cycloalkane by replacing the suffix ane by ene if a double bond is present. The suffix ane is replaced by yne if a triple bond is present.

Expert Solution
Check Mark

Answer to Problem B.1P

The root for the given molecule is hexene.

Explanation of Solution

The given molecule is

Organic Chemistry: Principles and Mechanisms (Second Edition), Chapter B, Problem B.1P , additional homework tip  7

In this molecule, the longest carbon chain containing the double bond has six carbon atoms. Hence, the root is hexene, as shown below.

Organic Chemistry: Principles and Mechanisms (Second Edition), Chapter B, Problem B.1P , additional homework tip  8

Conclusion

The root is determined from the longest carbon chain or the largest ring containing the double or triple bond between the carbon atoms.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
6. Match each of the lettered items in the column on the left with the most appropriate numbered item(s) in the column on the right. Some of the numbered items may be used more than once and some not at all. a. Z = 37 1. b. Mn 2. C. Pr element in period 5 and group 14 element in period 5 and group 15 d. S e. [Rn] 7s¹ f. d block metal 3. highest metallic character of all the elements 4. paramagnetic with 5 unpaired electrons 5. 4f36s2 6. isoelectronic with Ca²+ cation 7. an alkaline metal 8. an f-block element
Draw all formal charges on the structures below as is and draw 1 resonance structure that is more stable.
Part II. xiao isolated a compound TAD (Ca H 10 N₂) from tobacco and obtained its IR spectrum. Xiao proposed a chemical structure shown below: % Transmittance 4000 3500 3000 2500 2000 Wavenumber (cm-1) 1500 1000 (a) Explain why her proposed structure is inconsistent with the IR spectrum obtained (b) TAD exists as a tautomer of the structure xiao proposed. Draw the structure and explain why it is more compatible with the obtained spectrum. (C) what is the possible source for the fairly intense signal at 1621cm1
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Organic Chemistry: A Guided Inquiry
Chemistry
ISBN:9780618974122
Author:Andrei Straumanis
Publisher:Cengage Learning
Text book image
Chemistry for Today: General, Organic, and Bioche...
Chemistry
ISBN:9781305960060
Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Publisher:Cengage Learning