Initial concentration of glucose solution in millilitres should be identified. Concept introduction: The amount of the solute in the new diluted solution is equal to the amount of the solute in the solution before dilution. i.e. V 1 C 1 =V 2 C 2 concentrated = diluted solution solution This is the dilution expression. Given: Final volume of glucose solution : 500 mL Final concentartion of glucose solution : 5 .0% (m/v) Initial concentration of glucose solution : 25% (m/v)

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Answer 1

Question

Chapter 9.5, Problem 9.69QAP

Interpretation Introduction

Interpretation:

Initial concentration of glucose solution in millilitres should be identified.

Concept introduction:

The amount of the solute in the new diluted solution is equal to the amount of the solute in the solution before dilution.

i.e.

$V_{1} C_{1} {=V}_{2} C_{2}$

concentrated = diluted

solution solution

This is the dilution expression.

Given:

$\begin{array}{l} Final volume of glucose solution : 500 mL \\ Final concentartion of glucose solution : 5 .0% (m/v) \\ Initial concentration of glucose solution : 25% (m/v) \end{array}$

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Answer 2

Question

Chapter 9.5, Problem 9.69QAP

Interpretation Introduction

Interpretation:

Initial concentration of glucose solution in millilitres should be identified.

Concept introduction:

The amount of the solute in the new diluted solution is equal to the amount of the solute in the solution before dilution.

i.e.

$V_{1} C_{1} {=V}_{2} C_{2}$

concentrated = diluted

solution solution

This is the dilution expression.

Given:

$\begin{array}{l} Final volume of glucose solution : 500 mL \\ Final concentartion of glucose solution : 5 .0% (m/v) \\ Initial concentration of glucose solution : 25% (m/v) \end{array}$

Expert Solution & Answer

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Check out a sample textbook solution

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Answer 3

Question

Chapter 9.5, Problem 9.69QAP

Interpretation Introduction

Interpretation:

Initial concentration of glucose solution in millilitres should be identified.

Concept introduction:

The amount of the solute in the new diluted solution is equal to the amount of the solute in the solution before dilution.

i.e.

$V_{1} C_{1} {=V}_{2} C_{2}$

concentrated = diluted

solution solution

This is the dilution expression.

Given:

$\begin{array}{l} Final volume of glucose solution : 500 mL \\ Final concentartion of glucose solution : 5 .0% (m/v) \\ Initial concentration of glucose solution : 25% (m/v) \end{array}$

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 9.5, Problem 9.69QAP

Interpretation Introduction

Interpretation:

Initial concentration of glucose solution in millilitres should be identified.

Concept introduction:

The amount of the solute in the new diluted solution is equal to the amount of the solute in the solution before dilution.

i.e.

$V_{1} C_{1} {=V}_{2} C_{2}$

concentrated = diluted

solution solution

This is the dilution expression.

Given:

$\begin{array}{l} Final volume of glucose solution : 500 mL \\ Final concentartion of glucose solution : 5 .0% (m/v) \\ Initial concentration of glucose solution : 25% (m/v) \end{array}$

Expert Solution & Answer

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Answer 5

Chapter 9.5, Problem 9.69QAP

Interpretation Introduction

Interpretation:

Initial concentration of glucose solution in millilitres should be identified.

Concept introduction:

The amount of the solute in the new diluted solution is equal to the amount of the solute in the solution before dilution.

i.e.

$V_{1} C_{1} {=V}_{2} C_{2}$

concentrated = diluted

solution solution

This is the dilution expression.

Given:

$\begin{array}{l} Final volume of glucose solution : 500 mL \\ Final concentartion of glucose solution : 5 .0% (m/v) \\ Initial concentration of glucose solution : 25% (m/v) \end{array}$

Answer 6

Chapter 9.5, Problem 9.69QAP

Interpretation Introduction

Interpretation:

Initial concentration of glucose solution in millilitres should be identified.

Concept introduction:

The amount of the solute in the new diluted solution is equal to the amount of the solute in the solution before dilution.

i.e.

$V_{1} C_{1} {=V}_{2} C_{2}$

concentrated = diluted

solution solution

This is the dilution expression.

Given:

$\begin{array}{l} Final volume of glucose solution : 500 mL \\ Final concentartion of glucose solution : 5 .0% (m/v) \\ Initial concentration of glucose solution : 25% (m/v) \end{array}$

Answer 7

Chapter 9.5, Problem 9.69QAP

Interpretation Introduction

Interpretation:

Initial concentration of glucose solution in millilitres should be identified.

Concept introduction:

The amount of the solute in the new diluted solution is equal to the amount of the solute in the solution before dilution.

i.e.

$V_{1} C_{1} {=V}_{2} C_{2}$

concentrated = diluted

solution solution

This is the dilution expression.

Given:

$\begin{array}{l} Final volume of glucose solution : 500 mL \\ Final concentartion of glucose solution : 5 .0% (m/v) \\ Initial concentration of glucose solution : 25% (m/v) \end{array}$

Answer 8

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Answer 9

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Answer 10

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Answer 11

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