Chapter 9.5, Problem 16PPS

To determine

Find the value of c.

Answer to Problem 16PPS

  $c=\frac{289}{4}$

Explanation of Solution

Given Information: $x^2+17x+c$

Formula Used: $a^2+2ab+b^2={(a+b)}^2$

Calculation:

  $x^2+17x+c$

So, simplify and make the factor of 17

  $x^2+\left(2\times x\times \frac{17}{2}\right)+c$  (1)

As, $a^2+2ab+b^2={(a+b)}^2$

Compare equation (1) with $a^2+2ab+b^2={(a+b)}^2$

  $a=x$ and $b=\frac{17}{2}$

Put value of a and b in $a^2+2ab+b^2={(a+b)}^2$

  $x^2+\left(2\times x\times \frac{17}{2}\right)+{\left(\frac{17}{2}\right)}^2={\left(x+\frac{17}{2}\right)}^2$  (2)

Now, compare equation (1) and (2)

  $c={\left(\frac{17}{2}\right)}^2$

Hence,

  $c=\frac{289}{4}$