Explanation Given information: The Tube is subjected to an axial force of 10 N. The Thickness of paper ( t ) is 1 mm. The Outer diameter of the tube ( d 0 ) is 30 mm. Calculation: Calculate the normal stress ( σ ) acting on the tube using the relation: σ = N A (1) Here, N is the axial force and A is the area of the tube. The inner diameter ( d i ) of the tube as follows: d i = d 0 − 2 t = 30 mm − 2 ( 1 mm ) = 28 mm Find the area of the tube ( A ) using the relation: A = π 4 ( d 0 2 − d i 2 ) (2) Substitute 30 mm for d 0 and 28 mm for d i in Equation (2). A = π 4 ( 30 2 − 28 2 ) = 91.1062 mm 2 Substitute 10 N for N and 91.1062 mm 2 for A in Equation (1). σ = 10 N 91.1062 mm 2 = 0.10976 MPa = 109.76 kPa Find the shear stress ( τ ) acting on the cross section: Since there is no shear force in the cross section. Therefore the value of shear stress is 0. Sketch the orientation of the element as shown in Figure 1.

9th Edition

ISBN: 9780133254426

Author: Russell C. Hibbeler

Publisher: Prentice Hall

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Chapter 9.3, Problem 9.39P

To determine

The normal stress acting perpendicular to the seam.

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Chapter 9.3, Problem 9.38P

Chapter 9.3, Problem 9.40P

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Chapter 9 Solutions

Mechanics of Materials

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