L+ined sove in peaperX-P 96852Example 5.5 The turbine rotor of a ship has a mass of 30 tons, a radius of gyrationof 600 mm and rotates at 2400 rpm in a clockwise direction when viewed from aft. Theship pitches through a total angle of 15%, 7.5° above and 7.5° below the horizontal, themotion being simple harmonic and having a period of 12 sec. Determine the maximumgyroscopic couple on the holding down bolts of the turbine and the direction of yaw asthe bow rises.-20125750 x2.01

First, we need to convert the given values into SI units for consistency in calculations. The mass…

Answered: L + ined sove in peaper X-P 96852…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Q6. For a point at distance 50 m and angle 450 to the axis which of the following are correct? Consider an infinite baffled piston of radius 5 cm driven at 2 kHz in air with velocity 10 m/s. You may choose multiple options. A. k = 18.32 and J1(ka sin(q))/ka sin(q) = 0.17 B. k = 36.64 and J1(ka sin(q))/ka sin(q) = 0.40 C.k=5.83 and J1(ka sin(q))/ka sin(q) = 3.16 D. None of the above Submit E
The Wright Brothers designed an engine and propeller that would produce enough forward motion to lift a simple light airplane. The 3 meter diameter blade rotated at a constant 330 rotations per minute (RPM). How does the RPM of the tip of one blade compare to the RPM of the middle of the one blade (halfway towards the center of the propeller)? The RPM is twice as much. The RMP is the same. The RPM is half as much. The RPM is one quarter as much.
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7. A single cylinder, single acting, four stroke cycle gas engine develops 20 kW at 250 r.p.m. The work done by the gases during the expansion stroke is 3 times the work done on the gases during the compression stroke. The work done on the suction and exhaust strokes may be neglected. If the flywheel has a mass of 1.5 tonnes and has a radius of gyration of 0.6m, find the cyclic fluctuation of energy and the coefficient of fluctuation of speed.
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Answer it correctly please. State proper reason. I will rate accordingly.
A mass of 1.5 kg is suspended from a swivel point by a string of 1.2m long. The mass revolves in a horizontal circular path at 50 revs min. What is the tension in the string and what is the radius of rotation 2. A mass of 1.5 kg is suspended from a swivel point by a string of 1.2m long. The mass revolves in a horizontal circular path at 50 revs/min. What is the tension in the string and what is the radius of rotation. T-1.2M 1.5kg Transcribed Image Text: 2. A mass of 1.5 kg is suspended from a swivel point by a string of 1.2m long. The mass revolves in a horizontal circular path at 50 revs/min. What is the tension in the string and what is the radius of rotation. T- 1.2M 1.5kg
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question 2 A mass ! hangs on the end of a cord around a pulley of radius 5 and moment of inertia 6, rotating with an angular velocity ,, as shown in the figure below. The rim of the pulley is attached to a spring (with constant 7). Assume small oscillations so that the spring remains essentially horizontal and neglect friction so that the conservation of energy of the system yields: 1 2 !91 + 1 2 6,1 + 1 2 7;1 − !); = =, ?ℎABA , = 9 5 , = = CDE&/, ; = FG&H'5CA!AE/ IBD! AJ(G'GKBG(! Find the natural circular frequency of the system in terms of !, 5, 7,6, and ).
A mass of 1.5 kg is suspended from a swivel point by a string of 1.2m long. The mass revolves in a horizontal circular path at 50 revs/min. What is the tension in the string and what is the radius of rotation
Consider the dynamics of a rotating disk modeled as second-order system IÖ + b,ė +k,0 = u(t) with mass moment of inertia I = 0.025 kg/m², bearing friction br = 12 N-m/(rad/s), and torsional spring constant kr = 90 Nm/rad. The disk is driven by an oscillating torque input u(t) = P sin wt with magnitude P = 100 N-m at an input frequency of w = 10 rad/s. = • Derive an expression for the steady-state output Oss (t). Hint: first find the transfer function G(s) (s)/U(s) and then the sinusoidal transfer function G(iw) along with the gain |G(iw) and phase = LG(iw). The expression for the steady-state output in response to a sinusoidal input U(s) was derived in Lecture 18. • When is this steady-state output is achieved after the system is started from rest? Assume that transients have decayed after 4 time constants.

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