Explanation Given info: The data shows the female attractiveness ratings and male attractiveness ratings. The attractiveness ratings made by participants in a speed dating session. Each attribute rating is the sum of the ratings of five attributes such as sincerity, intelligence, fun, ambition and shared interests. Calculation: State the test hypotheses. Consider Difference = Male by female − Female by male Null hypothesis: H 0 : μ d = 0 That is, there is no difference between female attractiveness ratings and male attractiveness ratings. Alternative hypothesis: H 1 : μ d ≠ 0 That is, there is a difference between female attractiveness ratings and male attractiveness ratings. Test statistic and P-value: Software procedure: Step by step procedure to obtain test statistic and P -value using the MINITAB software: Choose Stat > Basic Statistics > Paired t . In First Sample , enter the column of “Rating of male by female” . In Second Sample , enter the column of “Rating of female by male” . Choose Options

13th Edition

ISBN: 9780134462455

Author: Mario F. Triola

Publisher: PEARSON

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Question

Chapter 9.3, Problem 12BSC

To determine

To test: The claim that there is a difference between the female attractiveness ratings and male attractiveness ratings.

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Chapter 9.3, Problem 11BSC

Chapter 9.3, Problem 13BSC

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To test: The claim that there is a difference between the female attractiveness ratings and male attractiveness ratings.

Solution Summary: The author concludes that there is no difference between the female and male attractiveness ratings.

To test: The claim that there is a difference between the female attractiveness ratings and male attractiveness ratings.

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Chapter 9 Solutions