Elementary Statistics (13th Edition)
13th Edition
ISBN: 9780134462455
Author: Mario F. Triola
Publisher: PEARSON
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Chapter 9.2, Problem 4BSC
Degrees of Freedom For Example 1 on page 431, we used df = smaller of n1 − 1 and n2 − 1, we got df = 11, and the corresponding critical values are t = ± 2.201. If we calculate df using Formula 9-1, we get df = 19.063, and the corresponding critical values are ±2.093. How is using the critical values of t = ±2.201 more “conservative” than using the critical values of ± 2.093?
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Students have asked these similar questions
Question 1:
Below is the R output of a model where the response is resting heart rate (Rest) and the
predictors are Weight (Wgt, in pounds) and Gender (0 for female and 1 for male), with an
interaction term between Weight and Gender.
Our population model is: Rest; = Bo + BiW gt; + B2Gender; + B3W gt;Gender; + e
Im (formula
Rest
Wgt + Gender + Wgt Gender)
!!
Coefficients:
Estimate Std. Error t value Pr (>It|)
(Intercept) 70.25970
5.67488 12.381
<2e-16 ***
Wgt
-0.01948
0.03138 -0.621
0.535
Gender
16.19178
9.97017
1.624
0.106
Wgt:Gender -0.10178
0.06803 -1.496
0.136
Residual standard error: 9.78 on 228 degrees of freedom
Multiple R-squared: 0.04625, Adjusted R-squared: 0.0337
F-statistic: 3.685 on 3 and 228 DF, p-value: 0.01274
(5)Find x if.
i. e* = 3,
ii. Inx
%3D
iv. 32-x = 27,
v. 8x+1
32.
%3D
i need the answer quickly
Chapter 9 Solutions
Elementary Statistics (13th Edition)
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