Explanation Draw the T − s diagram for ideal Stirling engine cycle as shown in Figure (1). Write the expression of ideal gas equation for the isothermal process 3-4. P 4 = P 3 v 3 v 4 (I) Here, pressure at state 4 is P 4 , , pressure at state 3 is P 3 , volume at state 3 is v 3 and volume at state 4 is v 4 . Write the expression of ideal gas equation for the constant volume process 4-1. T 1 = T 4 ( P 1 P 4 ) (II) Here, temperature at state 4 is T 4 , and temperature at state 1 is T 1 . Write the expression of heat input to the Stirling engine cycle ( q in ) . q in = R T 1 ln v 2 v 1 (III) Here, the gas constant of air is R , volume at state 2 is v 2 and volume at state 1 is v 1 . Write the expression of heat rejected by the Stirling engine cycle ( q out ) . q out = R T 3 ln v 4 v 3 (IV) Here, volume at state 4 is v 4 and volume at state 3 is v 3 . Write the expression of net specific work done by the Stirling engine cycle ( w net ) . w net = q in − q out (V) Conclusion: From Table A-2Ea, “Ideal-gas specific heats of various common gases”, obtain the following properties for air. R = 0.06855 Btu / lbm ⋅ R c v = 0 .171 Btu / lbm ⋅ R c p = 0.240 Btu / lbm ⋅ R k = 1.4 Substitute 10 psia for P 3 and 10 for ( v 3 v 4 ) in Equation (I). P 4 = ( 10 psia ) ( 10 ) = 100 psia Substitute 100 ° F for T 4 , 600 psia for P 1 , and 100 psia for P 4 in Equation (II). T 1 = ( 100 ° F ) ( 600 psia 100 psia ) = ( 100 + 460 ) R ( 600 psia 100 psia ) = 3360 R Substitute 0

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Chapter 9.12, Problem 75P

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The specific heat added to the cycle and the net specific work.

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Chapter 9.12, Problem 74P

Chapter 9.12, Problem 76P

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The specific heat added to the cycle and the net specific work.

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