THERMODYNAMICS LLF W/ CONNECT ACCESS
9th Edition
ISBN: 9781264446889
Author: CENGEL
Publisher: MCG
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Chapter 9.12, Problem 103P
To determine
State the reason why the steam injection increases both power output and thermal efficiency of the gas turbine and also explain how steam can be obtained.
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1- Determine the following: 1- RSHF? 2- C.C.C in tons-ref. 3- Mass
of supply air?
Fresh
Spray chilled
water
S
air
100% RH
To 34 C db & 26 wbt
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Operation
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Exhaust
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Ti 22 C db & 50% RH
How do I solve this task
A weight for a lift is suspended using an adapter. The counterweight is held up with 4 screws. The weight F is 3200kg.
The screws have a strength class of 8.8. Safety factor 3
Which is the smallest bunch size that can be used?+_Sr/Fm =0,16Gr=0,71ơ=800·0.8=640 MPaAs=?Fmax= As·ơ·GrFs=ơs·AsFFm= Fs· GFSF =SF / FFm · FFm Fpreload =Fload / SF → Fload /3Fpreload per screw =Fload / SF → Fload /4As=Fpreload per screw /ơ·Gr → As= Fpreload per screw / 640· 0.71
The correct answer should be M12 with As=84.3mm²
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Chapter 9 Solutions
THERMODYNAMICS LLF W/ CONNECT ACCESS
Ch. 9.12 - What are the air-standard assumptions?Ch. 9.12 - What is the difference between air-standard...Ch. 9.12 - Prob. 3PCh. 9.12 - How does the thermal efficiency of an ideal cycle,...Ch. 9.12 - How are the combustion and exhaust processes...Ch. 9.12 - What does the area enclosed by the cycle represent...Ch. 9.12 - Prob. 7PCh. 9.12 - Can the mean effective pressure of an automobile...Ch. 9.12 - What is the difference between spark-ignition and...Ch. 9.12 - Prob. 10P
Ch. 9.12 - Prob. 11PCh. 9.12 - Can any ideal gas power cycle have a thermal...Ch. 9.12 - Prob. 13PCh. 9.12 - Prob. 14PCh. 9.12 - Prob. 15PCh. 9.12 - Prob. 16PCh. 9.12 - Prob. 17PCh. 9.12 - Prob. 18PCh. 9.12 - Prob. 19PCh. 9.12 - Repeat Prob. 919 using helium as the working...Ch. 9.12 - The thermal energy reservoirs of an ideal gas...Ch. 9.12 - Consider a Carnot cycle executed in a closed...Ch. 9.12 - Consider a Carnot cycle executed in a closed...Ch. 9.12 - What four processes make up the ideal Otto cycle?Ch. 9.12 - Are the processes that make up the Otto cycle...Ch. 9.12 - How do the efficiencies of the ideal Otto cycle...Ch. 9.12 - How does the thermal efficiency of an ideal Otto...Ch. 9.12 - Why are high compression ratios not used in...Ch. 9.12 - An ideal Otto cycle with a specified compression...Ch. 9.12 - Prob. 30PCh. 9.12 - Prob. 31PCh. 9.12 - Determine the mean effective pressure of an ideal...Ch. 9.12 - Reconsider Prob. 932E. Determine the rate of heat...Ch. 9.12 - An ideal Otto cycle has a compression ratio of 8....Ch. 9.12 - Prob. 36PCh. 9.12 - A spark-ignition engine has a compression ratio of...Ch. 9.12 - An ideal Otto cycle has a compression ratio of 7....Ch. 9.12 - Prob. 39PCh. 9.12 - An ideal Otto cycle with air as the working fluid...Ch. 9.12 - Repeat Prob. 940E using argon as the working...Ch. 9.12 - Someone has suggested that the air-standard Otto...Ch. 9.12 - Repeat Prob. 942 when isentropic processes are...Ch. 9.12 - Prob. 44PCh. 9.12 - Prob. 45PCh. 9.12 - Prob. 46PCh. 9.12 - Prob. 47PCh. 9.12 - Prob. 48PCh. 9.12 - Prob. 49PCh. 9.12 - Prob. 50PCh. 9.12 - Prob. 51PCh. 9.12 - Prob. 52PCh. 9.12 - Prob. 53PCh. 9.12 - Prob. 54PCh. 9.12 - Prob. 55PCh. 9.12 - Prob. 56PCh. 9.12 - Prob. 57PCh. 9.12 - Repeat Prob. 957, but replace the isentropic...Ch. 9.12 - Prob. 60PCh. 9.12 - Prob. 61PCh. 9.12 - The compression ratio of an ideal dual cycle is...Ch. 9.12 - Repeat Prob. 962 using constant specific heats at...Ch. 9.12 - Prob. 65PCh. 9.12 - Prob. 66PCh. 9.12 - Prob. 67PCh. 9.12 - An air-standard cycle, called the dual cycle, with...Ch. 9.12 - Prob. 69PCh. 9.12 - Prob. 70PCh. 9.12 - Consider the ideal Otto, Stirling, and Carnot...Ch. 9.12 - Consider the ideal Diesel, Ericsson, and Carnot...Ch. 9.12 - An ideal Ericsson engine using helium as the...Ch. 9.12 - An ideal Stirling engine using helium as the...Ch. 9.12 - Prob. 75PCh. 9.12 - Prob. 76PCh. 9.12 - Prob. 77PCh. 9.12 - Prob. 78PCh. 9.12 - Prob. 79PCh. 9.12 - For fixed maximum and minimum temperatures, what...Ch. 9.12 - What is the back work ratio? What are typical back...Ch. 9.12 - Why are the back work ratios relatively high in...Ch. 9.12 - How do the inefficiencies of the turbine and the...Ch. 9.12 - A simple ideal Brayton cycle with air as the...Ch. 9.12 - A stationary gas-turbine power plant operates on a...Ch. 9.12 - A gas-turbine power plant operates on the simple...Ch. 9.12 - Prob. 87PCh. 9.12 - Prob. 88PCh. 9.12 - Repeat Prob. 988 when the isentropic efficiency of...Ch. 9.12 - Repeat Prob. 988 when the isentropic efficiency of...Ch. 9.12 - Repeat Prob. 988 when the isentropic efficiencies...Ch. 9.12 - Air is used as the working fluid in a simple ideal...Ch. 9.12 - An aircraft engine operates on a simple ideal...Ch. 9.12 - Repeat Prob. 993 for a pressure ratio of 15.Ch. 9.12 - A gas-turbine power plant operates on the simple...Ch. 9.12 - A simple ideal Brayton cycle uses argon as the...Ch. 9.12 - A gas-turbine power plant operates on a modified...Ch. 9.12 - A gas-turbine power plant operating on the simple...Ch. 9.12 - Prob. 99PCh. 9.12 - Prob. 100PCh. 9.12 - Prob. 101PCh. 9.12 - Prob. 102PCh. 9.12 - Prob. 103PCh. 9.12 - Prob. 104PCh. 9.12 - A gas turbine for an automobile is designed with a...Ch. 9.12 - Rework Prob. 9105 when the compressor isentropic...Ch. 9.12 - A gas-turbine engine operates on the ideal Brayton...Ch. 9.12 - An ideal regenerator (T3 = T5) is added to a...Ch. 9.12 - Prob. 109PCh. 9.12 - Prob. 111PCh. 9.12 - A Brayton cycle with regeneration using air as the...Ch. 9.12 - Prob. 113PCh. 9.12 - Prob. 114PCh. 9.12 - Prob. 115PCh. 9.12 - Prob. 116PCh. 9.12 - Prob. 117PCh. 9.12 - Prob. 118PCh. 9.12 - Prob. 119PCh. 9.12 - Prob. 120PCh. 9.12 - A simple ideal Brayton cycle without regeneration...Ch. 9.12 - A simple ideal Brayton cycle is modified to...Ch. 9.12 - Consider a regenerative gas-turbine power plant...Ch. 9.12 - Repeat Prob. 9123 using argon as the working...Ch. 9.12 - Consider an ideal gas-turbine cycle with two...Ch. 9.12 - Repeat Prob. 9125, assuming an efficiency of 86...Ch. 9.12 - A gas turbine operates with a regenerator and two...Ch. 9.12 - Prob. 128PCh. 9.12 - Prob. 129PCh. 9.12 - Prob. 130PCh. 9.12 - Prob. 131PCh. 9.12 - Air at 7C enters a turbojet engine at a rate of 16...Ch. 9.12 - Prob. 133PCh. 9.12 - A turbojet is flying with a velocity of 900 ft/s...Ch. 9.12 - A pure jet engine propels an aircraft at 240 m/s...Ch. 9.12 - A turbojet aircraft is flying with a velocity of...Ch. 9.12 - Prob. 137PCh. 9.12 - Prob. 138PCh. 9.12 - Reconsider Prob. 9138E. How much change would...Ch. 9.12 - Consider an aircraft powered by a turbojet engine...Ch. 9.12 - An ideal Otto cycle has a compression ratio of 8....Ch. 9.12 - An air-standard Diesel cycle has a compression...Ch. 9.12 - Prob. 144PCh. 9.12 - Prob. 145PCh. 9.12 - Prob. 146PCh. 9.12 - Prob. 147PCh. 9.12 - A Brayton cycle with regeneration using air as the...Ch. 9.12 - Prob. 150PCh. 9.12 - A gas turbine operates with a regenerator and two...Ch. 9.12 - A gas-turbine power plant operates on the...Ch. 9.12 - Prob. 153PCh. 9.12 - An air-standard cycle with variable specific heats...Ch. 9.12 - Prob. 155RPCh. 9.12 - Prob. 156RPCh. 9.12 - Prob. 157RPCh. 9.12 - Prob. 158RPCh. 9.12 - Prob. 159RPCh. 9.12 - Prob. 160RPCh. 9.12 - Prob. 161RPCh. 9.12 - Consider an engine operating on the ideal Diesel...Ch. 9.12 - Repeat Prob. 9162 using argon as the working...Ch. 9.12 - Prob. 164RPCh. 9.12 - Prob. 165RPCh. 9.12 - Prob. 166RPCh. 9.12 - Prob. 167RPCh. 9.12 - Consider an ideal Stirling cycle using air as the...Ch. 9.12 - Prob. 169RPCh. 9.12 - Consider a simple ideal Brayton cycle with air as...Ch. 9.12 - Prob. 171RPCh. 9.12 - A Brayton cycle with a pressure ratio of 15...Ch. 9.12 - Helium is used as the working fluid in a Brayton...Ch. 9.12 - Consider an ideal gas-turbine cycle with one stage...Ch. 9.12 - Prob. 176RPCh. 9.12 - Prob. 177RPCh. 9.12 - Prob. 180RPCh. 9.12 - Prob. 181RPCh. 9.12 - Prob. 182RPCh. 9.12 - For specified limits for the maximum and minimum...Ch. 9.12 - A Carnot cycle operates between the temperature...Ch. 9.12 - Prob. 194FEPCh. 9.12 - Prob. 195FEPCh. 9.12 - Helium gas in an ideal Otto cycle is compressed...Ch. 9.12 - Prob. 197FEPCh. 9.12 - Prob. 198FEPCh. 9.12 - In an ideal Brayton cycle, air is compressed from...Ch. 9.12 - In an ideal Brayton cycle, air is compressed from...Ch. 9.12 - Consider an ideal Brayton cycle executed between...Ch. 9.12 - An ideal Brayton cycle has a net work output of...Ch. 9.12 - In an ideal Brayton cycle with regeneration, argon...Ch. 9.12 - In an ideal Brayton cycle with regeneration, air...Ch. 9.12 - Consider a gas turbine that has a pressure ratio...Ch. 9.12 - An ideal gas turbine cycle with many stages of...
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- P₂ 7+1 * P₁ ART 2 P (P₁ - P₂- Zgp) 21 / Prove that :- m² a cda A₂ == * Cde actual mip Solutionarrow_forwardQ1/ Show that (actual 02/ A simple iet == Cda Cdf х Af 2/Y - Y+1/Y 2P(P1-P2-zxgxpr)arrow_forward5. Determine the transfer function of G(s) = 01(s)/T₁(s) and 02(s)/T₁ for the mechanical system shown in Figure Q5. (Hints: assume zero initial condition) T₁(t) 01(t) 102(1) Ол N1 D1 D2 No. 1790220000 N2 Figure Q5 K2arrow_forward
- A spring package with two springs and an external force, 200N. The short spring has a loin of 35 mm. Constantly looking for spring for short spring so that total compression is 35 mm (d). Known values: Long spring: Short spring:C=3.98 N/mm Lo=65mmLo=87.4mmF=c·fTotal compression is same for both spring. 200 = (3.98(c1) × 35) + (c₂ × 35) 200 = 139.3 + 35c₂ 200 - 139.3 = 35c₂ 60.7 = 35c₂ c₂ = 60.7/35 Short spring (c₂) = 1.73 N/mm According to my study book, the correct answer is 4.82N/mm What is wrong with the calculating?arrow_forwardWhat is the reason for this composition?arrow_forwardHomework: ANOVA Table for followed design B AB Dr -1 -1 1 (15.18,12) 1 -1 -1 (45.48.51) -1 1 -1 (25,28,19) 1 1 (75.75,81)arrow_forward
- 20. [Ans. 9; 71.8 mm] A semi-elliptical laminated spring is made of 50 mm wide and 3 mm thick plates. The length between the supports is 650 mm and the width of the band is 60 mm. The spring has two full length leaves and five graduated leaves. If the spring carries a central load of 1600 N, find: 1. Maximum stress in full length and graduated leaves for an initial condition of no stress in the leaves. 2. The maximum stress if the initial stress is provided to cause equal stress when loaded. [Ans. 590 MPa ; 390 MPa ; 450 MPa ; 54 mm] 3. The deflection in parts (1) and (2).arrow_forwardQ6/ A helical square section spring is set inside another, the outer spring having a free length of 35 mm greater than the inner spring. The dimensions of each spring are as follows: Mean diameter (mm) Side of square section (mm) Active turns Outer Inner Spring Spring 120 70 8 7 20 15 Determine the (1) Maximum deflection of the two springs and (2) Equivalent spring rate of the two springs after sufficient load has been applied to deflect the outer spring 60 mm. Use G = 83 GN/m².arrow_forwardQ2/ The bumper springs of a railway carriage are to be made of rectangular section wire. The ratio of the longer side of the wire to its shorter side is 1.5, and the ratio of mean diameter of spring to the longer side of wire is nearly equal to 6. Three such springs are required to bring to rest a carriage weighing 25 kN moving with a velocity of 75 m/min with a maximum deflection of 200 mm. Determine the sides of the rectangular section of the wire and the mean diameter of coils when the shorter side is parallel to the axis of the spring. The allowable shear stress is not to exceed 300 MPa and G = 84 kN/mm². Q6/ A belicalarrow_forward
- 11. A load of 2 kN is dropped axially on a close coiled helical spring, from a height of 250 mm. The spring has 20 effective turns, and it is made of 25 mm diameter wire. The spring index is 8. Find the maximum shear stress induced in the spring and the amount of compression produced. The modulus of rigidity for the material of the spring wire is 84 kN/mm². [Ans. 287 MPa; 290 mm]arrow_forwardWhat is the reason for this composition?arrow_forwardHomework: ANOVA Table for followed design B AB Dr -1 -1 1 (15.18,12) 1 -1 -1 (45.48.51) -1 1 -1 (25,28,19) 1 1 (75.75,81)arrow_forward
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