
Concept explainers
Interpretation:
Deviations from an ideal bond angle that are not possible for a
Concept introduction:
To determine the geometry, first draw a Lewis structure of the molecule.
Count the number of electron pairs or domains around the central atom. Electron domain is the bond, and lone pair of electrons are placed around the central atom.
Electron domains are the bond and lone pair of electrons around the central atom.
According to VSEPR, the electron domains repel each other, and arrange themselves as far apart as possible in space.
Molecular geometry is the spatial arrangement of bonded atoms. If no lone pairs are present, then molecular geometry is identical to the electron domain geometry.
The repulsion factor working between lone pair and lone pair is greater as compared to the lone pair–bond pair repulsion, which is further greater than the bond pair–bond pair repulsion.
To draw a Lewis structure, first, the sum of the valence electrons of all the atoms is determined. In case of a polyatomic ion, electrons are added if there is negative charge, and subtracted if there is a positive charge on the ion.
A skeleton structure is drawn connecting all the atoms and each bond contains two electrons.
Then, the electrons are placed on the terminal atoms as lone pairs, to complete their octet.
Remaining electrons are placed on central atom as lone pairs.
If there are no valence electrons to complete the octet of the central atom, then one or more terminal atoms share a lone pair to form a double bond.

Want to see the full answer?
Check out a sample textbook solution
Chapter 9 Solutions
EBK CHEMISTRY
- 2.0arrow_forwardWrite the electron configuration of an atom of the element highlighted in this outline of the Periodic Table: 1 23 4 5 6 7 He Ne Ar Kr Xe Rn Hint: you do not need to know the name or symbol of the highlighted element! ☐arrow_forwardCompare these chromatograms of three anti-psychotic drugs done by HPLC and SFC. Why is there the difference in separation time for SFC versus HPLC? Hint, use the Van Deemter plot as a guide in answering this question. Why, fundamentally, would you expect a faster separation for SFC than HPLC, in general?arrow_forward
- A certain inorganic cation has an electrophoretic mobility of 5.27 x 10-4 cm2s-1V-1. The same ion has a diffusion coefficient of 9.5 x 10-6cm2s-1. If this ion is separated from cations by CZE with a 75cm capillary, what is the expected plate count, N, at an applied voltage of 15.0kV? Under these separation conditions, the electroosmotic flow rate was 0.85mm s-1 toward the cathode. If the detector was 50.0cm from the injection end of the capillary, how long would it take in minutes for the analyte cation to reach the detector after the field was applied?arrow_forward2.arrow_forwardPlease solve for the following Electrochemistry that occursarrow_forward
- Commercial bleach contains either chlorine or oxygen as an active ingredient. A commercial oxygenated bleach is much safer to handle and less likely to ruin your clothes. It is possible to determine the amount of active ingredient in an oxygenated bleach product by performing a redox titration. The balance reaction for such a titration is: 6H+ +5H2O2 +2MnO4- à 5O2 + 2Mn2+ + 8H2O If you performed the following procedure: “First, dilute the Seventh Generation Non-Chlorine Bleach by pipetting 10 mL of bleach in a 100 mL volumetric flask and filling the flask to the mark with distilled water. Next, pipet 10 mL of the diluted bleach solution into a 250 mL Erlenmeyer flask and add 20 mL of 1.0 M H2SO4 to the flask. This solution should be titrated with 0.0100 M KMnO4 solution.” It took 18.47mL of the KMnO4 to reach the endpoint on average. What was the concentration of H2O2 in the original bleach solution in weight % assuming the density of bleach is 1g/mL?arrow_forward10.arrow_forwardProper care of pH electrodes: Why can you not store a pH electrode in distilled water? What must you instead store it in? Why?arrow_forward
- Write the electron configuration of an atom of the element highlighted in this outline of the Periodic Table: 1 23 4 569 7 He Ne Ar Kr Xe Rn Hint: you do not need to know the name or symbol of the highlighted element! §arrow_forwardIdentify the amino acids by name. Illustrate a titration curve for this tetrapeptide indicating the pKa's for each ionizable groups and identify the pI for this tetrapeptide. please helparrow_forward↓ ina xSign x Sign X labs X Intro X Cop Xa chat X My Cx Grac X Laur x Laur xash learning.com/ihub/assessment/f188d950-dd73-11e0-9572-0800200c9a66/d591b3f2-d5f7-4983-843c-0d00c1c0340b/f2b47861-07c4-4d1b-a1ee-e7db2 +949 pts /3400 K Question 16 of 34 > © Macmillan Learning Draw the major E2 reaction product formed when cis-1-chloro-2-ethylcyclohexane (shown) reacts with hydroxide ion in DMSO. H CH2CH3 H H HO- H H H Cl DMSO H H C Select Draw Templates More C H 0 2 Erasearrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning
- Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningGeneral Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage Learning





