EBK CHEMISTRY
EBK CHEMISTRY
4th Edition
ISBN: 8220102797864
Author: Burdge
Publisher: YUZU
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Chapter 9.1, Problem 1PPB
Interpretation Introduction

Interpretation:

The groups to which the terminal atoms in a ABx molecule belongs, is to determined.

Concept Introduction:

In a Lewis structure of a molecule, generally, the element with a smaller number of atoms is the central atom, and the other atoms are the terminal atoms. When more than two types of elements are present, then the less electronegative element is the central atom.

To draw a Lewis structure, first the sum of valence electrons of all the atoms is determined.

A skeleton structure is drawn, connecting all the atoms. Each bond contains of two electrons.

Then the electrons are placed on the terminal atoms as lone pairs, so as to complete their octet.

The remaining electrons are placed around the central atom as lone pairs.

If there isno valence electrons to complete the octet of the central atom, then one or more terminal atoms share a lone pair to form a double bond.

Electron domain is the bond pair and lone pair of electrons around the central atom.

According to VSEPR model, the electron domain arranges itself as far as possible to minimize repulsions between the electrons.

Molecular geometry is the spatial arrangement of bonded atoms. If no lone pairs of electrons are present, then molecular geometry is identical to the electron domain geometry.

The repulsion between the lone pair-lone pair is greater than in lone pair-bond pair, which in turn is greater than in a bond pair-bond pair.

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Chapter 9 Solutions

EBK CHEMISTRY

Ch. 9.2 - Practice ProblemCONCEPTUALIZE Which of these...Ch. 9.2 - 9.2.1 Identify the polar molecules in the...Ch. 9.2 - Identify the nonpolar molecules in the following...Ch. 9.3 - Practice ProblemATTEMPT Use valence bond theory to...Ch. 9.3 - Practice ProblemBUILD For which molecule(s) can we...Ch. 9.3 - Practice ProblemCONCEPTUALIZE Which of these...Ch. 9.3 - Which of the following atoms, in its ground state,...Ch. 9.3 - According to valence bond theory, how many bonds...Ch. 9.4 - Practice Problem ATTEMPT Use hybrid orbital theory...Ch. 9.4 - Practice ProblemBUILD Use hybrid orbital theory to...Ch. 9.4 - Prob. 1PPCCh. 9.4 - How many orbitals does a set of s p 2 hybrid...Ch. 9.4 - How many p atomic orbitals are required to...Ch. 9.5 - Practice Problem ATTEMPT The active ingredient in...Ch. 9.5 - Practice ProblemBUILD Determine the total number...Ch. 9.5 - Practice ProblemCONCEPTUALIZE In terms of valence...Ch. 9.5 - Which of the following molecules contain one or...Ch. 9.5 - 9.5.2 From left to right, give the hybridization...Ch. 9.5 - Which of the following pairs of atomic orbitals on...Ch. 9.5 - 9.5.4 Which of the following pairs of atomic...Ch. 9.6 - Practice ProblemATTEMPT Use valence bond theory...Ch. 9.6 - Prob. 1PPBCh. 9.6 - Prob. 1PPCCh. 9.6 - Prob. 1CPCh. 9.6 - Prob. 2CPCh. 9.6 - Prob. 3CPCh. 9.6 - Prob. 4CPCh. 9.7 - Prob. 1PPACh. 9.7 - Prob. 1PPBCh. 9.7 - Prob. 1PPCCh. 9.7 - Prob. 1CPCh. 9.7 - Prob. 2CPCh. 9.7 - Prob. 3CPCh. 9.7 - Prob. 4CPCh. 9.8 - Practice ProblemATTEMPT Use a combination of...Ch. 9.8 - Practice ProblemBUILD Use a combination of valence...Ch. 9.8 - Prob. 1PPCCh. 9 - Prob. 1KSPCh. 9 - Which of the following species does not have...Ch. 9 - 9.3 Which of the following species is polar? Ch. 9 - Which of the following species is nonpolar (a) IC1...Ch. 9 - How is the geometry of a molecule defined, and why...Ch. 9 - 9.2 Sketch the shape of a linear triatomic...Ch. 9 - How many atoms are directly bonded to the central...Ch. 9 - Discuss the basic features of the VSEPR model....Ch. 9 - In the trigonal bipyramidal arrangement, why does...Ch. 9 - 9.6 Explain why the molecule is not square...Ch. 9 - Predict the geometries of the following species...Ch. 9 - Predict the geometries of the following species: (...Ch. 9 - Predict the geometry of the following molecules...Ch. 9 - Predict the geometry of the following molecules...Ch. 9 - Predict the geometry of the following ions using...Ch. 9 - 9.12 Predict the geometries of the following ions:...Ch. 9 - Describe the geometry around each of the three...Ch. 9 - 9.14 Which of the following species are...Ch. 9 - Prob. 15QPCh. 9 - The bonds in beryllium hydride ( BeH 2 ) molecules...Ch. 9 - Determine whether (a) BrF 5 and (b) BCl 3 are...Ch. 9 - Determine whether (a) OCS and (b) XeF 4 are polar.Ch. 9 - Prob. 19QPCh. 9 - Prob. 20QPCh. 9 - Prob. 21QPCh. 9 - Use valence bond theory to explain the bonding in...Ch. 9 - Prob. 23QPCh. 9 - Prob. 24QPCh. 9 - 9.25 What is the hybridization of atomic orbitals?...Ch. 9 - Prob. 26QPCh. 9 - 9.27 What is the angle between the following two...Ch. 9 - Prob. 28QPCh. 9 - Prob. 29QPCh. 9 - Prob. 30QPCh. 9 - Prob. 31QPCh. 9 - Prob. 32QPCh. 9 - Prob. 33QPCh. 9 - Prob. 34QPCh. 9 - Which of the following pairs of atomic orbitals of...Ch. 9 - Prob. 36QPCh. 9 - 9.37 Specify which hybrid orbitals are used by...Ch. 9 - The allene molecule ( H 2 C=C=CH 2 ) is linear...Ch. 9 - Prob. 39QPCh. 9 - Prob. 40QPCh. 9 - How many pi bonds and sigma bonds are there in the...Ch. 9 - Prob. 42QPCh. 9 - Benzo(a)pyrene is a potent carcinogen found in...Ch. 9 - What is molecular orbital theory? How does it...Ch. 9 - 9.45 Define the following terms: bonding molecular...Ch. 9 - Sketch the shapes of the following molecular...Ch. 9 - Explain the significance of bond order. Can bond...Ch. 9 - Explain in molecular orbital terms the changes in...Ch. 9 - 9.49 The formation of from two atoms is an...Ch. 9 - 9.50 Draw a molecular orbital energy level diagram...Ch. 9 - Prob. 51QPCh. 9 - Prob. 52QPCh. 9 - Which of these species has a longer bond, B 2 or B...Ch. 9 - Prob. 54QPCh. 9 - 9.55 Compare the Lewis and molecular orbital...Ch. 9 - Prob. 56QPCh. 9 - Prob. 57QPCh. 9 - Prob. 58QPCh. 9 - A single bond is almost always a sigma bond, and a...Ch. 9 - Prob. 60QPCh. 9 - In Chapter 8, we saw that the resonance concept is...Ch. 9 - Prob. 62QPCh. 9 - Prob. 63QPCh. 9 - Prob. 64QPCh. 9 - Nitryl fluoride ( FNO 2 ) is very reactive...Ch. 9 - Prob. 66QPCh. 9 - Prob. 67QPCh. 9 - Which of the following species is not likely to...Ch. 9 - Prob. 69APCh. 9 - Although both carbon and silicon are in Group 4A,...Ch. 9 - Predict the geometry of sulfur dichloride ( SCl 2...Ch. 9 - Antimony pentafluoride ( sbF 5 ) reacts with XeF 4...Ch. 9 - Prob. 73APCh. 9 - Prob. 74APCh. 9 - Predict the bond angles for the following...Ch. 9 - Briefly compare the VSEPR and hybridization...Ch. 9 - 9.77 Draw Lewis structures and give the other...Ch. 9 - Prob. 78APCh. 9 - Determine whether (a) PCl 5 and (b) H 2 CO (C...Ch. 9 - Prob. 80APCh. 9 - 9.81 Which of the following molecules are linear:...Ch. 9 - Prob. 82APCh. 9 - 9.83 The molecule can exist in either of the...Ch. 9 - Cyclopropane ( C 3 H 6 ) has the shape of a...Ch. 9 - Determine whether (a) CH 2 Cl 2 and (b) XeF 4 are...Ch. 9 - 9.86 Does the following molecule have a dipole...Ch. 9 - For which molecular geometries (linear, bent,...Ch. 9 - Prob. 88APCh. 9 - 9.89 Carbon suboxide is a colorless...Ch. 9 - The following molecules ( AX 4 Y 2 ) all have an...Ch. 9 - Prob. 91APCh. 9 - Write the ground-state electron configuration for...Ch. 9 - 9.93 What is the hybridization of C and of N in...Ch. 9 - The stable allotropic form of phosphorus is P 4 ,...Ch. 9 - Prob. 95APCh. 9 - Use molecular orbital theory to explain the...Ch. 9 - Carbon dioxide has a linear geometry and is...Ch. 9 - Draw three Lewis structures for compounds with the...Ch. 9 - Prob. 99APCh. 9 - Prob. 100APCh. 9 - Prob. 101APCh. 9 - Draw the Lewis structure of ketene ( C 2 H 2 O )...Ch. 9 - Prob. 103APCh. 9 - Which of the following ions possess a dipole...Ch. 9 - Prob. 105APCh. 9 - Prob. 106APCh. 9 - The compound TCDD, or...Ch. 9 - Progesterone is a hormone responsible for female...Ch. 9 - 9.109 Carbon monoxide is a poisonous compound due...Ch. 9 - Prob. 110APCh. 9 - Prob. 111APCh. 9 - Prob. 112APCh. 9 - 9.113 The compound 1,2-dichloroethane is...Ch. 9 - Consider an N 2 molecule in its first excited...Ch. 9 - Prob. 115APCh. 9 - Prob. 1SEPPCh. 9 - Prob. 2SEPPCh. 9 - These questions are not based on a descriptive...Ch. 9 - These questions are not based on a descriptive...
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