The band gap in the Aluminium antimonide solid state laser for wavelength of 730 nm has to be calculated. Concept introduction: According to Band theory of solids, the energy levels of a substance are imagined as “bands”. There are two types of bands – valence band and conduction band. Low lying bands are valence band and conduction band where the conduction takes place, lies above the valence band. The energy gap between the valence band and conduction band is called “band gap”. The energy gap can be represented by Planck’s equation, E = hν where ν = c λ E = energy h = Planck's constant ν = frequency c = velocity of light λ = wavelength
The band gap in the Aluminium antimonide solid state laser for wavelength of 730 nm has to be calculated. Concept introduction: According to Band theory of solids, the energy levels of a substance are imagined as “bands”. There are two types of bands – valence band and conduction band. Low lying bands are valence band and conduction band where the conduction takes place, lies above the valence band. The energy gap between the valence band and conduction band is called “band gap”. The energy gap can be represented by Planck’s equation, E = hν where ν = c λ E = energy h = Planck's constant ν = frequency c = velocity of light λ = wavelength
Solution Summary: The author explains that the band gap in the Aluminium antimonide solid state laser for wavelength of 730 nm has to be calculated.
The band gap in the Aluminium antimonide solid state laser for wavelength of 730 nm has to be calculated.
Concept introduction:
According to Band theory of solids, the energy levels of a substance are imagined as “bands”. There are two types of bands – valence band and conduction band. Low lying bands are valence band and conduction band where the conduction takes place, lies above the valence band. The energy gap between the valence band and conduction band is called “band gap”. The energy gap can be represented by Planck’s equation,
Identify the structure of the PTH derivative generated after two rounds of Edman degradation.
Use the data below from an electron impact mass spectrum of a pure compound to deduce its structure. Draw your structure in the
drawing window.
Data selected from the NIST
WebBook,
https://webbook.nist.gov/chemistry/
m/z
Relative intensity
31
0.5
30
26
29
22
28
100
27
33
26
23
15
4
• You do not have to consider stereochemistry.
You do not have to explicitly draw H atoms.
• In cases where there is more than one answer, just draw one.
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Write the molecular formula for a compound with the possible elements C, H, N and O that exhibits a molecular ion at M+ = 98.1106.
Exact Masses of the Most Abundant Isotope of
Selected Elements
Isotope Natural abundance (%) Exact mass
1H
99.985
1.008
12C
98.90
12.000
14N
99.63
14.003
160
99.76
15.995
Molecular formula
(In the order CHNO, with no subscripts)
Chapter 9 Solutions
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