The wavelength of the light emitted by Aluminium phosphide diode has to be calculated. Concept introduction: According to Band theory of solids, the energy levels of a substance are imagined as “bands”. There are two types of bands – valence band and conduction band. Low lying bands are valence band and conduction band where the conduction takes place, lies above the valence band. The energy gap between the valence band and conduction band is called “band gap”. The energy gap can be represented by Planck’s equation, E = hν where ν = c λ E = energy h = Planck's constant ν = frequency c = velocity of light λ = wavelength
The wavelength of the light emitted by Aluminium phosphide diode has to be calculated. Concept introduction: According to Band theory of solids, the energy levels of a substance are imagined as “bands”. There are two types of bands – valence band and conduction band. Low lying bands are valence band and conduction band where the conduction takes place, lies above the valence band. The energy gap between the valence band and conduction band is called “band gap”. The energy gap can be represented by Planck’s equation, E = hν where ν = c λ E = energy h = Planck's constant ν = frequency c = velocity of light λ = wavelength
Solution Summary: The author explains that the wavelength of the light emitted by Aluminium phosphide diode has to be calculated. The energy gap between the valence band and conduction band is represented by Planck’s equation
The wavelength of the light emitted by Aluminium phosphide diode has to be calculated.
Concept introduction:
According to Band theory of solids, the energy levels of a substance are imagined as “bands”. There are two types of bands – valence band and conduction band. Low lying bands are valence band and conduction band where the conduction takes place, lies above the valence band. The energy gap between the valence band and conduction band is called “band gap”. The energy gap can be represented by Planck’s equation,
Sketch, qualitatively, the potential energy curves of the N-N bond of N2H4, N2 and N3- graph. Explain why the energy at the minimum of each curve is not the same.
(a) Show that the lattice energies are inversely proportional to the distance between ions in MX (M = alkali metal, X = halide ions) by plotting the lattice energies of KF, KCl, and KI against the internuclear distances, dMX. The lattice energies of KF, KCl, and KI are 826, 717, and 645 kJ/mol, respectively. Does the correlation obtained correlate well? You will need to use a standard graphing program to construct the graph (such as a spreadsheet program). It will generate an equation for the line and calculate a correlation coefficient. (b) Estimate the lattice energy of KBr from your graph. (c) Find an experimental value for the lattice energy of KBr in the literature, and compare this value with the one calculated in (b). Do they agree?
Show the curved arrow mechanism and both products for the reaction between methyl iodide and propoxide.
1st attempt
NV
H
10:
H
H
1
Add the missing curved arrow notation.
H
+
See Periodic Table
Chapter 9 Solutions
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