Introduction to Chemistry, Special Edition
6th Edition
ISBN: 9781337035934
Author: Cracolice/Peters
Publisher: Cengage Learning
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Chapter 9, Problem 1PE
Interpretation Introduction
Interpretation:
The dissolving equations for the compounds barium chlorate, cobalt
Concept introduction:
The ionic compounds are highly soluble in water and dissociate into the water to give its ions. Thus, they are good conductors of electricity and are classified as electrolytes. The molecular compounds are neutral and do not dissociate into ions when dissolved in water. Very few of molecular compounds produce the ions when dissolved in water.
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Learning Goal:
This question reviews the format for writing an element's written symbol. Recall that written symbols have a particular format. Written symbols use a form like this:
35 Cl
17
In this form the mass number, 35, is a stacked superscript. The atomic number, 17, is a stacked subscript. "CI" is the chemical symbol for the element chlorine. A general way to show this form is:
It is also correct to write symbols by leaving off the atomic number, as in the following form:
atomic number
mass number Symbol
35 Cl or
mass number Symbol
This is because if you write the element symbol, such as Cl, you know the atomic number is 17 from that symbol. Remember that the atomic number, or number of protons in the nucleus, is what defines the element. Thus, if 17 protons
are in the nucleus, the element can only be chlorine. Sometimes you will only see 35 C1, where the atomic number is not written.
Watch this video to review the format for written symbols.
In the following table each column…
need help please and thanks dont understand only need help with C-F
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal…
need help please and thanks dont understand only need help with C-F
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal…
Chapter 9 Solutions
Introduction to Chemistry, Special Edition
Ch. 9 - Prob. 1ECh. 9 - Prob. 2ECh. 9 - Prob. 3ECh. 9 - Prob. 4ECh. 9 - Questions 5 through 12: Write the major species in...Ch. 9 - Prob. 6ECh. 9 - Questions 5 through 12: Write the major species in...Ch. 9 - Prob. 8ECh. 9 - Questions 5 through 12: Write the major species in...Ch. 9 - Question 5 through 12: Write the major species in...
Ch. 9 - Question 5 through 12: Write the major species in...Ch. 9 - Question 5 through 12: Write the major species in...Ch. 9 - Questions 13 through 18: For each reaction...Ch. 9 - Questions 13 through 18: For each reaction...Ch. 9 - Prob. 15ECh. 9 - Prob. 16ECh. 9 - Prob. 17ECh. 9 - Questions 13 through 18: For each reaction...Ch. 9 - Questions 19 through 24: For each pair of...Ch. 9 - Prob. 20ECh. 9 - Questions 19 through 24: For each pair of...Ch. 9 - Questions 19 through 24: For each pair of...Ch. 9 - Questions 19 through 24: For each pair of...Ch. 9 - Prob. 24ECh. 9 - Questions 25 through 28: Write the equation for...Ch. 9 - Prob. 26ECh. 9 - Prob. 27ECh. 9 - Prob. 28ECh. 9 - Questions 29 through 36: For each pair of...Ch. 9 - Prob. 30ECh. 9 - Questions 29 through 36: For each pair of...Ch. 9 - Prob. 32ECh. 9 - Questions 29 through36: For each pair of reactants...Ch. 9 - Questions 29 through36: For each pair of reactants...Ch. 9 - Questions 29 through36: For each pair of reactants...Ch. 9 - Questions 29 through 36: For each pair of...Ch. 9 - Write the net ionic equations for the...Ch. 9 - Prob. 38ECh. 9 - Questions 39 through 44: For each pair of...Ch. 9 - Prob. 40ECh. 9 - Questions 39 through 44: For each pair of...Ch. 9 - Prob. 42ECh. 9 - Questions 39 through 44: For each pair of...Ch. 9 - Prob. 44ECh. 9 - Questions 45 through 48: For each pair of...Ch. 9 - Prob. 46ECh. 9 - Questions 45 through 48: For each pair of...Ch. 9 - Prob. 48ECh. 9 - Prob. 49ECh. 9 - Prob. 50ECh. 9 - Prob. 51ECh. 9 - The remaining questions include all types of...Ch. 9 - Prob. 53ECh. 9 - Prob. 54ECh. 9 - Prob. 55ECh. 9 - Prob. 56ECh. 9 - Prob. 57ECh. 9 - Prob. 58ECh. 9 - Prob. 59ECh. 9 - The remaining questions include all types of...Ch. 9 - Prob. 61ECh. 9 - Prob. 62ECh. 9 - Prob. 63ECh. 9 - Prob. 64ECh. 9 - Prob. 65ECh. 9 - Prob. 66ECh. 9 - Prob. 67ECh. 9 - Prob. 68ECh. 9 - Prob. 69ECh. 9 - The remaining questions include all types of...Ch. 9 - Prob. 71ECh. 9 - Prob. 72ECh. 9 - The remaining questions include all types of...Ch. 9 - Prob. 74ECh. 9 - The remaining questions include all types of...Ch. 9 - Prob. 76ECh. 9 - Prob. 77ECh. 9 - Prob. 78ECh. 9 - Prob. 79ECh. 9 - Prob. 80ECh. 9 - Prob. 9.1TCCh. 9 - Write a brief description of the relationships...Ch. 9 - Write a brief description of the relationships...Ch. 9 - Prob. 3CLECh. 9 - Prob. 1PECh. 9 - Prob. 2PECh. 9 - Prob. 3PECh. 9 - Aluminum nitrate and sodium hydroxide solutions...Ch. 9 - A piece of solid zinc is dropped into hydrochloric...Ch. 9 - Chlorine gas is bubbled through a sodium bromide...Ch. 9 - Write the conventional, total ionic, and net ionic...Ch. 9 - Prob. 8PECh. 9 - Prob. 9PECh. 9 - Prob. 10PECh. 9 - Prob. 11PECh. 9 - Prob. 12PECh. 9 - Solutions of hydrobromic acid and barium hydroxide...Ch. 9 - Solutions of hydroiodic acid and sodium fluoride...Ch. 9 - Prob. 15PECh. 9 - Prob. 16PECh. 9 - A nitric acid solution is poured onto solid nickel...Ch. 9 - Prob. 18PECh. 9 - A skill you need for writing net ionic equations...Ch. 9 - Prob. 2ECECh. 9 - Prob. 3ECECh. 9 - Prob. 4ECECh. 9 - Prob. 5ECECh. 9 - Prob. 6ECECh. 9 - A skill you need for writing net ionic equations...Ch. 9 - A skill you need for writing net ionic equations...Ch. 9 - Prob. 9ECECh. 9 - Prob. 10ECECh. 9 - Prob. 11ECECh. 9 - A skill you need for writing net ionic equations...
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- Please correct answer and don't used hand raitingarrow_forwardneed help please and thanks dont understand a-b Learning Goal: As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT. The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7). Part A - Difference in binding free eenergies Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol. The margin of error is 2%. Part B - Compare difference in free energy to the thermal energy Divide the…arrow_forwardPlease correct answer and don't used hand raitingarrow_forward
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