Materials Science And Engineering Properties
1st Edition
ISBN: 9781111988609
Author: Charles Gilmore
Publisher: Cengage Learning
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Chapter 9, Problem 13CQ
To determine
The strength of crystalline areas at the temperature above the equi-cohesive temperature
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Chapter 9 Solutions
Materials Science And Engineering Properties
Ch. 9 - Prob. 1CQCh. 9 - Prob. 2CQCh. 9 - Prob. 3CQCh. 9 - Prob. 4CQCh. 9 - Prob. 5CQCh. 9 - Prob. 6CQCh. 9 - Prob. 7CQCh. 9 - Prob. 8CQCh. 9 - Prob. 9CQCh. 9 - Prob. 10CQ
Ch. 9 - Prob. 11CQCh. 9 - Prob. 12CQCh. 9 - Prob. 13CQCh. 9 - At temperatures above the equi-cohesive...Ch. 9 - Prob. 15CQCh. 9 - Prob. 16CQCh. 9 - Prob. 17CQCh. 9 - Prob. 18CQCh. 9 - Prob. 19CQCh. 9 - Prob. 20CQCh. 9 - Prob. 21CQCh. 9 - Prob. 22CQCh. 9 - Prob. 23CQCh. 9 - Prob. 24CQCh. 9 - Prob. 25CQCh. 9 - Prob. 26CQCh. 9 - Prob. 27CQCh. 9 - Prob. 28CQCh. 9 - Prob. 29CQCh. 9 - Prob. 30CQCh. 9 - Prob. 31CQCh. 9 - Prob. 32CQCh. 9 - Prob. 33CQCh. 9 - Prob. 34CQCh. 9 - Prob. 35CQCh. 9 - Prob. 1ETSQCh. 9 - Prob. 2ETSQCh. 9 - Prob. 3ETSQCh. 9 - Prob. 4ETSQCh. 9 - Prob. 5ETSQCh. 9 - Prob. 6ETSQCh. 9 - Prob. 7ETSQCh. 9 - Prob. 8ETSQCh. 9 - Prob. 9ETSQCh. 9 - Prob. 10ETSQCh. 9 - Prob. 11ETSQCh. 9 - Prob. 12ETSQCh. 9 - Prob. 9.1PCh. 9 - Prob. 9.2PCh. 9 - Prob. 9.3PCh. 9 - Prob. 9.4PCh. 9 - Prob. 9.5PCh. 9 - Prob. 9.6PCh. 9 - Prob. 9.7PCh. 9 - Prob. 9.8PCh. 9 - Prob. 9.9PCh. 9 - Prob. 9.10PCh. 9 - For silver at a tensile stress of 7 MPa and a...Ch. 9 - For germanium at a tensile stress of 410 MPa and a...Ch. 9 - Prob. 9.13PCh. 9 - Prob. 9.14PCh. 9 - Prob. 9.15PCh. 9 - Prob. 9.16PCh. 9 - Prob. 9.17PCh. 9 - Prob. 9.18PCh. 9 - Prob. 9.19PCh. 9 - Prob. 9.20PCh. 9 - Prob. 9.21PCh. 9 - Prob. 9.22P
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- An iron specimen is plastically deformed in shear by 1%, and it has u dislocation density of 1 10 14 m/ m 3 Assume that the dislocation density did not change in the 1% strain of thisspecimen, the Burger's vector (b) is a 2 [1 1 1] the slip plane is (110). the shear stress isapplied to the (110) plane, and the lattice parameter of the BCC iron is 0.286 nm. Calculate the magnitude of the Burger's vector for these dislocations in iron. Calculate the average distance moved by the mobile dislocations as a result of the 1% shear strain.arrow_forwardIn an engineering application, the material is a strip of iron with a fixed crystallographic structure subject to a tensile load during operation. The part failed (yielded) during operation and needs to be replaced with a component with better properties. You are told that two other iron strips had failed at yield stresses of 110 and 120 MPa, with grain sizes of 30 microns and 25 microns respectively. The current strip has a grain size of 20 microns. The diameter of the rod is 1 mm and the load applied is 100 N. What is the yield stress of the new part C and would you recommend it for operation? Select one: Oa. 133.5 MPa, yes O b. OC. Od Oe. 120.5 MPa, no 129.5, yes 140.5, no 123.5 MPa, yesarrow_forward3.What is a dislocation? List five more microscopic defects in bulk materials. Which of the following properties are most sensitive to dislocation structures in materials? a. Young's modulus b. Yield strength c. Conductivity d. Transparencyarrow_forward
- Explain why the experimental strength of materials are lower than their theoretical strengths. BI4 Pagrarrow_forwardi need the answer quicklyarrow_forwardA laminated [0/90/0/90]s graphite/epoxy beam is 1 mm thick, is 20 mm wide, and has 0.125 mm thick plies. The lamina properties are E1 = 180 GPa, E2 = 10 GPa, ν12 = 0.28, G12 = 7 GPa Xt = 1700 MPa, Xc = 1400 MPa, Yt = 40 MPa, Yc = 230 MPa (a) Determine the flexural modulus of the beam (b) How could the flexural modulus be improved without changing the ply materials, the number of plies, or the ply orientations? (c) Using the Maximum Stress Criterion for each ply, determine the magnitude of the maximum allowable bending moment that the beam can withstand. Which ply fails first?arrow_forward
- Which one is a linear defect in the crystalline materials? (A) external surfaces B) vacancies (c) dislocations (D) grain boundariesarrow_forwardQ7> Ductile-to-brittle transition temperature (DBTT) is a very important parameter in the design of metallic materials for engineering applications. It has been well known that most of BCC and HCP metals show the DBT phenomenon; however, there is no DBTT in FCC metals. (a) Explain the reason in terms of deformation and fracture. You must compare the BCC and FCC. (b) The ductile fracture surface consists of many dimples. Explain their formation mechanism from the concept of point defects. (c) There are two types in the brittle fracture. Explain and Compare them.arrow_forwardGiven your understanding of what initiates and controls failure in materials, which of the following will increase the failure strength or lifetime of a test piece or component and why? a. Decreasing the difference between the maximum and minimum stress values, as this effects the stress concentration factor b. Decreasing the temperature below the brittle-ductile transition temperature, to make it harder C. Polishing to reduce surface defects Od. Increasing its volume, to give a larger cross sectional area Oe. Increasing the grain size so there are less grain boundaries to initiate failurearrow_forward
- With the help of a diagram, contrast the stress-strain relationship with respect to ceramic and metalsWith the help of a diagram, contrast the stress-strain relationship with respect to ceramic and metalsarrow_forwardA copper rod is deformed using a uniaxial tensile force of 16000 N. Deformation continues until sufficient strain hardening has occurred such that the applied force is too small to allow further deformation. After deformation, the rod has a diameter of 0.01 m and a length of 1.5 m. Assume that copper follows the strain hardening lawwith K of 310 MPa and n=0.54 Please calculate the true strain after the deformation ?arrow_forward1. The most important mechanical properties of brittle materials is Tensile strength compressive strength O rigidity hardness Creeparrow_forward
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