The Lewis structure and geometry of Al 2 Cl 6 is to be shown, the hybridization state of aluminum in AlCl 3 and Al 2 Cl 6 is to be described, and whether the molecules AlCl 3 and Al 2 Cl 6 possess dipole moment or not is to be determined. Concept introduction: Hybrid orbital theory is based upon the formation of hybrid orbitals by the mixing of atomic orbitals. To explain bonding by hybrid orbitals, the number of electrons around the central atom is determined by drawing the Lewis structure of the molecule. The ground state orbital diagram for the central atom is drawn. Excitation of electrons to higher orbitals occurs to get the highest number of unpaired electrons. The required number of hybrid orbitals are combined to obtain the hybridization of the central atom. Electron domain is the bond pair and lone pair of electrons around the central atom.
The Lewis structure and geometry of Al 2 Cl 6 is to be shown, the hybridization state of aluminum in AlCl 3 and Al 2 Cl 6 is to be described, and whether the molecules AlCl 3 and Al 2 Cl 6 possess dipole moment or not is to be determined. Concept introduction: Hybrid orbital theory is based upon the formation of hybrid orbitals by the mixing of atomic orbitals. To explain bonding by hybrid orbitals, the number of electrons around the central atom is determined by drawing the Lewis structure of the molecule. The ground state orbital diagram for the central atom is drawn. Excitation of electrons to higher orbitals occurs to get the highest number of unpaired electrons. The required number of hybrid orbitals are combined to obtain the hybridization of the central atom. Electron domain is the bond pair and lone pair of electrons around the central atom.
Solution Summary: The author explains the Lewis structure and geometry of Al_Text2 TextCl
The Lewis structure and geometry of Al2Cl6 is to be shown, the hybridization state of aluminum in AlCl3 and Al2Cl6 is to be described, and whether the molecules AlCl3 and Al2Cl6 possess dipole moment or not is to be determined.
Concept introduction:
Hybrid orbital theory is based upon the formation of hybrid orbitals by the mixing of atomic orbitals.
To explain bonding by hybrid orbitals, the number of electrons around the central atom is determined by drawing the Lewis structure of the molecule.
The ground state orbital diagram for the central atom is drawn.
Excitation of electrons to higher orbitals occurs to get the highest number of unpaired electrons.
The required number of hybrid orbitals are combined to obtain the hybridization of the central atom.
Electron domain is the bond pair and lone pair of electrons around the central atom.
What I Have Learned
Directions: Given the following reaction and the stress applied in each
reaction, answer the question below.
A. H2(g) + Cl2(g) 2 HCl(g)
Stress applied: Decreasing the pressure
1. What is the Keq expression?
2. What will be the effect in the number of moles of HCl(g)?
3. What will be the Equilibrium Shift or the reaction?
B.
Fe3O4(s) + 4 H2(g) + heat 53 Fe(s) + 4 H₂O(g)
Stress applied: Increasing the temperature
1. What is the Keq expression?.
2. What will be the effect in the volume of water vapor collected?
3. What will be the Equilibrium Shift or the reaction?
C. 4 NH3(g) + 5 O2(g) 4 NO(g) + 6 H2O(g) + heat
Stress applied: Increasing the volume of the container
1. What is the Keq expression?.
2. What will be the effect in the amount of H₂O?
3. What will be the Equilibrium Shift or the reaction?
Consider the solubility products (Ksp values) for the following compounds:SrSO4 (Ksp = 7.6 x 10−7), BaSO4 (Ksp = 1.5 x 10−9), SrCO3 (Ksp = 7.0 x 10−10), BaCO3 (Ksp = 1.6 x 10−9)Which anion is the harder base, CO32− or SO42−? Justify your answer.
Q1:
a) Arrange the compounds in order of decreasing pKa, highest first.
ОН
ΟΗ
ῸΗ
дон
ОН
ОН
CI
Br
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Quantum Molecular Orbital Theory (PChem Lecture: LCAO and gerade ungerade orbitals); Author: Prof Melko;https://www.youtube.com/watch?v=l59CGEstSGU;License: Standard YouTube License, CC-BY