The molecular formula of the given compound is to be written. The hybridization of each carbon and oxygen atom is to be determined. The geometry of each carbon and oxygen atom is to be described. Concept introduction: Mixing of atomic orbitals to form degenerate molecular orbitals is called hybridization. Hybridization state of each atom is to be calculated from the total number of sigma bond pairs and lone pairs of that atom. If there are two electron domains on an atom, then the atom is s p hybridized. s p orbitals are formed by mixing of one s and one p . If there are three electron domains on an atom, then the atom is s p 2 hybridized. s p 2 orbitals are formed by mixing of one s and two p . If there are four electron domains on an atom, then the atom is s p 3 hybridized. s p 3 orbitals are formed by mixing of one s and three p . A single bond has a sigma bond. A double bond contains a sigma bond and a pi bond. A triple bond contains a sigma bond and two pi bonds.
The molecular formula of the given compound is to be written. The hybridization of each carbon and oxygen atom is to be determined. The geometry of each carbon and oxygen atom is to be described. Concept introduction: Mixing of atomic orbitals to form degenerate molecular orbitals is called hybridization. Hybridization state of each atom is to be calculated from the total number of sigma bond pairs and lone pairs of that atom. If there are two electron domains on an atom, then the atom is s p hybridized. s p orbitals are formed by mixing of one s and one p . If there are three electron domains on an atom, then the atom is s p 2 hybridized. s p 2 orbitals are formed by mixing of one s and two p . If there are four electron domains on an atom, then the atom is s p 3 hybridized. s p 3 orbitals are formed by mixing of one s and three p . A single bond has a sigma bond. A double bond contains a sigma bond and a pi bond. A triple bond contains a sigma bond and two pi bonds.
Solution Summary: The author explains the molecular formula of the given compound and the geometry of each carbon and oxygen atom.
Interpretation: The molecular formula of the given compound is to be written. The hybridization of each carbon and oxygen atom is to be determined. The geometry of each carbon and oxygen atom is to be described.
Concept introduction:
Mixing of atomic orbitals to form degenerate molecular orbitals is called hybridization.
Hybridization state of each atom is to be calculated from the total number of sigma bond pairs and lone pairs of that atom.
If there are two electron domains on an atom, then the atom is sp hybridized. sp orbitals are formed by mixing of one s and one p.
If there are three electron domains on an atom, then the atom is sp2 hybridized. sp2 orbitals are formed by mixing of one s and two p.
If there are four electron domains on an atom, then the atom is sp3 hybridized. sp3 orbitals are formed by mixing of one s and three p.
A single bond has a sigma bond.
A double bond contains a sigma bond and a pi bond.
A triple bond contains a sigma bond and two pi bonds.
Polymers may be composed of thousands of monomers. Draw three repeat units (trimer) of the polymer formed in this reaction. Assume there are hydrogen atoms there are hydrogen atoms on the two ends of the trimer. Ignore inorganic byproducts.
Draw a tetramer if this alternating copolymer please
Draw the monomers required to synthesize this condensation polymer.
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Quantum Molecular Orbital Theory (PChem Lecture: LCAO and gerade ungerade orbitals); Author: Prof Melko;https://www.youtube.com/watch?v=l59CGEstSGU;License: Standard YouTube License, CC-BY