Cyclopropane ( C 3 H 6 ) has the shape of a triangle in which a C atom is bonded to two H atoms and two other C atoms at each corner. Cubane ( C 8 H 8 ) has the shape of a cube in which a C atom is bonded to one H atom and three other C atoms at each comer. (a) Draw Lewis structures of these molecules. (b) Compare the CCC angles in these molecules with those predicted for an s p 3 − hybridized C atom. (c) Would you expect these molecules to be easy to make?
Cyclopropane ( C 3 H 6 ) has the shape of a triangle in which a C atom is bonded to two H atoms and two other C atoms at each corner. Cubane ( C 8 H 8 ) has the shape of a cube in which a C atom is bonded to one H atom and three other C atoms at each comer. (a) Draw Lewis structures of these molecules. (b) Compare the CCC angles in these molecules with those predicted for an s p 3 − hybridized C atom. (c) Would you expect these molecules to be easy to make?
Solution Summary: The author explains that the Lewis structures of cyclopropane and cubane are to be drawn and their bond angles with a mathrmsp3 hybridized carbon atom
Cyclopropane
(
C
3
H
6
)
has the shape of a triangle in which a C atom is bonded to two H atoms and two other C atoms at each corner. Cubane
(
C
8
H
8
)
has the shape of a cube in which a C atom is bonded to one H atom and three other C atoms at each comer. (a) Draw Lewis structures of these molecules. (b) Compare the CCC angles in these molecules with those predicted for an
s
p
3
−
hybridized C atom. (c) Would you expect these molecules to be easy to make?
1. For the four structures provided, Please answer the following questions in the table
below.
a. Please draw π molecular orbital diagram (use the polygon-and-circle method if
appropriate) and fill electrons in each molecular orbital
b. Please indicate the number of π electrons
c. Please indicate if each molecule provided is anti-aromatic, aromatic, or non-
aromatic
TT MO diagram
Number of π e-
Aromaticity Evaluation (X choose one)
Non-aromatic
Aromatic
Anti-aromatic
||
|||
+
IV
1.3 grams of pottasium iodide is placed in 100 mL of o.11 mol/L lead nitrate solution. At room temperature, lead iodide has a Ksp of 4.4x10^-9. How many moles of precipitate will form?
Q3: Circle the molecules that are optically active:
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