Given an optically active alcohol, A has the molecular formula C 11 H 16 O. It does not adsorb any hydrogen during catalytic reduction in the presence of Pd. It gets dehydrated when treated with dilute sulphuric acid to yield an optically inactive alkene , B (C 11 H 14 ). The alkene B yields propanol, CH 3 CH 2 CHO and a ketone, C (C 8 H 8 O). The number of degrees of unsaturation in A is to be calculated. A, B and C are to be identified and the reactions are to be written. Concept introduction: The degree of unsaturation in a compound can be calculated by considering the molecular formula of the compound and its parent hydrocarbon. Any compound with a chiral centre will be optically active. Alcohols undergo dehydration when warmed with dilute sulphuric acid. During ozonolysis the double bond is cleaved to yield carbonyl compounds. If the doubly bonded carbon is disubstituted then ketones are produced and if the doubly bonded carbon is monoisubstituted then aldehydes are produced. To calculate: The number of degrees of unsaturation in compound A. To identify: The structures of compounds A, B and C. To write: The reactions given.

Question

Solve for x, where M is molar and s is seconds. x = (9.0 × 10³ M−². s¯¹) (0.26 M)³ Enter the answer. Include units. Use the exponent key above the answer box to indicate any exponent on your units. ▸ View Available Hint(s) ΜΑ 0 ? Units Value

Answer 1

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 8.SE, Problem 72AP

Interpretation Introduction

Interpretation:

Given an optically active alcohol, A has the molecular formula C₁₁H₁₆O. It does not adsorb any hydrogen during catalytic reduction in the presence of Pd. It gets dehydrated when treated with dilute sulphuric acid to yield an optically inactive alkene, B (C₁₁H₁₄). The alkene B yields propanol, CH₃CH₂CHO and a ketone, C (C₈H₈O). The number of degrees of unsaturation in A is to be calculated. A, B and C are to be identified and the reactions are to be written.

Concept introduction:

The degree of unsaturation in a compound can be calculated by considering the molecular formula of the compound and its parent hydrocarbon. Any compound with a chiral centre will be optically active. Alcohols undergo dehydration when warmed with dilute sulphuric acid. During ozonolysis the double bond is cleaved to yield carbonyl compounds. If the doubly bonded carbon is disubstituted then ketones are produced and if the doubly bonded carbon is monoisubstituted then aldehydes are produced.

To calculate:

The number of degrees of unsaturation in compound A.

To identify:

The structures of compounds A, B and C.

To write:

The reactions given.

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Solve for x, where M is molar and s is seconds. x = (9.0 × 10³ M−². s¯¹) (0.26 M)³ Enter the answer. Include units. Use the exponent key above the answer box to indicate any exponent on your units. ▸ View Available Hint(s) ΜΑ 0 ? Units Value

Learning Goal: This question reviews the format for writing an element's written symbol. Recall that written symbols have a particular format. Written symbols use a form like this: 35 Cl 17 In this form the mass number, 35, is a stacked superscript. The atomic number, 17, is a stacked subscript. "CI" is the chemical symbol for the element chlorine. A general way to show this form is: It is also correct to write symbols by leaving off the atomic number, as in the following form: atomic number mass number Symbol 35 Cl or mass number Symbol This is because if you write the element symbol, such as Cl, you know the atomic number is 17 from that symbol. Remember that the atomic number, or number of protons in the nucleus, is what defines the element. Thus, if 17 protons are in the nucleus, the element can only be chlorine. Sometimes you will only see 35 C1, where the atomic number is not written. Watch this video to review the format for written symbols. In the following table each column…

need help please and thanks dont understand only need help with C-F Learning Goal: As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT. The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7). Part A - Difference in binding free eenergies Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol. The margin of error is 2%. Part B - Compare difference in free energy to the thermal…

Answer 2

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 8.SE, Problem 72AP

Interpretation Introduction

Interpretation:

Given an optically active alcohol, A has the molecular formula C₁₁H₁₆O. It does not adsorb any hydrogen during catalytic reduction in the presence of Pd. It gets dehydrated when treated with dilute sulphuric acid to yield an optically inactive alkene, B (C₁₁H₁₄). The alkene B yields propanol, CH₃CH₂CHO and a ketone, C (C₈H₈O). The number of degrees of unsaturation in A is to be calculated. A, B and C are to be identified and the reactions are to be written.

Concept introduction:

The degree of unsaturation in a compound can be calculated by considering the molecular formula of the compound and its parent hydrocarbon. Any compound with a chiral centre will be optically active. Alcohols undergo dehydration when warmed with dilute sulphuric acid. During ozonolysis the double bond is cleaved to yield carbonyl compounds. If the doubly bonded carbon is disubstituted then ketones are produced and if the doubly bonded carbon is monoisubstituted then aldehydes are produced.

To calculate:

The number of degrees of unsaturation in compound A.

To identify:

The structures of compounds A, B and C.

To write:

The reactions given.

Expert Solution & Answer

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See solution

Check out sample textbook solution

Answer 3

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 8.SE, Problem 72AP

Interpretation Introduction

Interpretation:

Given an optically active alcohol, A has the molecular formula C₁₁H₁₆O. It does not adsorb any hydrogen during catalytic reduction in the presence of Pd. It gets dehydrated when treated with dilute sulphuric acid to yield an optically inactive alkene, B (C₁₁H₁₄). The alkene B yields propanol, CH₃CH₂CHO and a ketone, C (C₈H₈O). The number of degrees of unsaturation in A is to be calculated. A, B and C are to be identified and the reactions are to be written.

Concept introduction:

The degree of unsaturation in a compound can be calculated by considering the molecular formula of the compound and its parent hydrocarbon. Any compound with a chiral centre will be optically active. Alcohols undergo dehydration when warmed with dilute sulphuric acid. During ozonolysis the double bond is cleaved to yield carbonyl compounds. If the doubly bonded carbon is disubstituted then ketones are produced and if the doubly bonded carbon is monoisubstituted then aldehydes are produced.

To calculate:

The number of degrees of unsaturation in compound A.

To identify:

The structures of compounds A, B and C.

To write:

The reactions given.

Expert Solution & Answer

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Answer 4

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 8.SE, Problem 72AP

Interpretation Introduction