(a) Explanation Using the ideal gas isentropic relations, calculate the exit temperature of the air ( T 2 ) . T 2 = T 1 ( P 2 P 1 ) k − 1 k (I) Here, inlet temperature of the air is T 1 , inlet pressure of the air is P 1 , exit pressure of the air is P 2 and heat ratio is k . From the steady-flow isentropic compression process, calculate work input to the compressor ( w comp,in ) . w comp,in = k R T 1 k − 1 [ ( P 2 P 1 ) k − 1 k − 1 ] (II) Here, gas constant of air is R . Conclusion: Refer Table A-1, "Molar mass, gas constant, and critical-point properties", select the gas constant of air. R = 0 .287 kJ / kg ⋅ K Refer Table A-2, " Ideal-gas specific heats of various common gases", select the constant pressure specific heat and specific heat ratio of air. c p = 1 .005 kJ / kg ⋅ K k = 1 .4 Substitute 300 K for T 1 , 100 kPa for P 1 , 800 kPa for P 2 and 1.4 for k in Equation (I). T 2 = ( 300 K ) ( 800 kPa 100 kPa ) 1.4 − 1 1 (b) To determine The exergy of the air at the exit of the compressor. (c) To determine The exergy of the compressed air after it gets cooled.

8th Edition

ISBN: 8220102809444

Author: CENGEL

Publisher: YUZU

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Chapter 8.8, Problem 73P

(a)

To determine

The work input to the compressor.

(b)

To determine

The exergy of the air at the exit of the compressor.

(c)

To determine

The exergy of the compressed air after it gets cooled.

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Chapter 8.8, Problem 72P

Chapter 8.8, Problem 74P

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The work input to the compressor.

Solution Summary: The author explains how to calculate the gas constant of air using the ideal gas isentropic relations.

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The work input to the compressor.

The exergy of the air at the exit of the compressor.

The exergy of the compressed air after it gets cooled.

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Chapter 8 Solutions