a) Explanation Write an expression for the mass balance for a tank which acts as a system. m in − m out = Δ m system m e = m 1 − m 2 (I) Here, mass of air entering to the supply line is m in ( m i ) , the mass of air leaving the system is m o u t , change in mass of a system is Δ m system , and final mass is m out ( m 2 ) . Write the expression for the energy balance equation for closed system. E ˙ i n − E ˙ o u t = Δ E ˙ s y s t e m (II) Here, rate of net energy transfer in to the control volume is E ˙ i n , rate of net energy transfer exit from the control volume is E ˙ o u t and rate of change in internal energy of system is Δ E ˙ s y s t e m . Substitute 0 for Δ E ˙ s y s t e m in Equation (II). E ˙ i n − E ˙ o u t = 0 E ˙ i n = E ˙ o u t Q ˙ i n = m ˙ e h e + m ˙ 2 u 2 − m ˙ 1 u 1 (III) Here, mass flow rate at exit is m ˙ e , mass flow rate at entry 2 is m ˙ 2 , mass flow rate at final is m ˙ 2 , internal energy at exit is u e , internal energy at 2 is u 2 and internal energy at final is u 3 . Write the expression for the initial mass flow rate. m 1 = ν v 1 (IV) Here, volume of the tank is ν and specific volume of the water at initial state is v 1 . Write the relation between the initial and final mass of the tank. m 2 = 1 2 m 1 = m e (V) Here, mass of the exit is m e . Write the expression for final mass flow rate. m 2 = ν v 2 (VI) Here, specific volume of the water at final state is v 2 . Write the expression to calculate the vapor quality at state 3 x 3 . v 2 = v f + x 2 ( v g − v f ) (VII) Here, final specific volume of liquid is v f , quality of the steam is x 2 , saturated liquid is v f , and saturated vapor is v f . Write the expression for the internal energy. u 2 = u f + x 2 u f g (VIII) Here, saturated liquid internal energy is u f , and vapor mixture internal energy is v f g . Write the expression to calculate the final entropy. s 2 = s f + x 2 s f g (IX) Here, saturated liquid entropy is s f , and vapor mixture entropy is s f g . Conclusion: Refer to Table A-4, “Saturated water-Temperature table”, obtain the following properties at the temperature of 170 ° C . v 1 = v f = 0 .001114 m 3 / kg u 1 = u f = 718 .20 kJ / kg u f g = 1857.5 kJ / kg s 1 = s f = 2 .0417 kJ / kg ⋅ K Refer to Table A-4, “Saturated water-Temperature table”, obtain the following properties at the temperature of 170 ° C . h e = h f = 719.08 kJ / kg s e = s f = 2 b) To determine The reversible work and exergy destruction during the process

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ISBN: 8220102809444

Author: CENGEL

Publisher: YUZU

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Chapter 8.8, Problem 74P

To determine

The amount of heat transfer in the process

To determine

The reversible work and exergy destruction during the process

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Chapter 8.8, Problem 73P

Chapter 8.8, Problem 75P

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EBK THERMODYNAMICS: AN ENGINEERING APPR

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