(a) Explanation Write the expression for the mass of water. m w = ρ w ν (I) Here, density of water is ρ w and volume is ν . Write the expression for work done by the paddle wheel. W P W i n = W ˙ P W i n Δ t (II) Here, power developed by the paddle wheel is W ˙ P W i n and change in time is Δ t . Express the energy balance by taking the entire contents of the tank, water and iron block as the system. E in − E out = Δ E system W P W i n = Δ U i r o n + Δ U i w a t e r W P W i n = [ m Fe c p , Fe ( T 2 − T 1 , Fe ) ] + [ m w c p , w ( T 2 − T 1 , w ) ] (II) Here, the total energy entering the system is E in , the total energy leaving the system is E out , the change in the total energy of the system is Δ E system , net internal energy is Δ U , paddle wheel power is W ˙ P W i n , net internal energy of iron and water is Δ U Fe and Δ U w respectively, mass of iron and water is m Fe and m w respectively, specific heat at constant pressure for iron and water is c p , Fe and c p , w respectively, final and initial temperature for iron and water is T 2 , T 1 , Cu and T 1 , w respectively. Conclusion: From the Table A-3, “properties of common liquids, solids, and foods”, Obtain the density and specific heat ( c p ) of water as 997 kg / m 3 and 4.18 kJ / kg ⋅ ° C respectively. From the Table A-3, “properties of common liquids, solids, and foods”, Obtain the specific heat ( c p ) of iron as 0 (b) To determine The exergy destroyed during the process.

8th Edition

ISBN: 8220102809444

Author: CENGEL

Publisher: YUZU

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Chapter 8.8, Problem 42P

(a)

To determine

The mass of the iron block

(b)

To determine

The exergy destroyed during the process.

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Chapter 8.8, Problem 41P

Chapter 8.8, Problem 43P

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