Nonlinear Dynamics and Chaos
Nonlinear Dynamics and Chaos
2nd Edition
ISBN: 9780813349107
Author: Steven H. Strogatz
Publisher: PERSEUS D
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Chapter 8.7, Problem 12E
Interpretation Introduction

Interpretation:

To show that all the characteristic multipliers equal +1, by calculating the linearized Poincare map, for the system of N identical oscillators, θ˙i=f(θi)+KNj=1Nf(θj),for i=1,......, N, where K>0, f(θ)>0, and f(θ) is smooth and - periodic for all θ so that the in-phase solution is periodic.

Concept Introduction:

  • ➢ If a system of the form x*=f(x) has an infinitesimal perturbation such that x*+v0 is in surface of section S, after the first return to S,

    x*+v1=P(x*+v0)=P(x*)[DP(x*)]v0+O(||v0||2)

    where an (n-1)×(n-1) matrix [DP(x*)] is known as a linearized Poincare map.

  • ➢ The in-phase solution is given by θ1(t)=θ2(t)=......θN(t)=θ*(t), where θ*(t) is a common waveform.

  • ➢ If all perturbation remains the same after one cycle, then the corresponding system has all characteristic multipliers equal +1.

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For the Big-M tableau (of a maximization LP and row0 at bottom and M=1000), Z Ꮖ 1 x2 x3 81 82 83 e4 a4 RHS 0 7 0 0 1 0 4 3 -3 20 0 -4.5 0 0 0 1 -8 -2.5 2.5 6 0 7 0 1 0 0 8 3 -3 4 0 -1 50 1 0 0 0-2 -1 1 4 0000 0 30 970 200 If the original value of c₁ is increased by 60, what is the updated value of c₁ (meaning keeping the same set for BV. -10? Having made that change, what is the new optimal value for ž?
Here is the optimal tableau for a standard Max problem. zx1 x2 x3 24 81 82 83 rhs 1 0 5 3 0 6 0 1 .3 7.5 0 - .1 .2 0 0 28 360 0 -8 522 0 2700 0 6 12 1 60 0 0 -1/15-3 1 1/15 -1/10 0 2 Using that the dual solution y = CBy B-1 and finding B = (B-¹)-¹ we find the original CBV and rhs b. The allowable increase for b₂ is If b₂ is increased by 3 then, using Dual Theorem, the new value for * is If c₂ is increased by 10, then the new value for optimal > is i.e. if no change to BV, then just a change to profit on selling product 2. The original coefficients c₁ = =☐ a and c4 = 5 If c4 is changed to 512, then (first adjusting other columns of row0 by adding Delta times row belonging to x4 or using B-matrix method to update row0) the new optimal value, after doing more simplex algorithm, for > is
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