Statics and Mechanics of Materials (5th Edition)
5th Edition
ISBN: 9780134382593
Author: Russell C. Hibbeler
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Textbook Question
Chapter 8.4, Problem 10P
The stress–strain diagram for an aluminum alloy specimen having an original diameter of 0.5 in. and a gage length of 2 in, is given in the figure. Determine approximately the modulus of elasticity for the material, the load on the specimen that causes yielding, and the ultimate load the specimen will support.
Probs. 8–10/11/12
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
A spring package with two springs and an external force, 200N. The short spring has a loin of 35 mm. Constantly looking for spring for short spring so that total compression is 35 mm (d). Known values: Long spring: Short spring:C=3.98 N/mm Lo=65mmLo=87.4mmF=c·fTotal compression is same for both spring. 200 = (3.98(c1) × 35) + (c₂ × 35)
200 = 139.3 + 35c₂
200 - 139.3 = 35c₂
60.7 = 35c₂
c₂ = 60.7/35
Short spring (c₂) = 1.73 N/mm
According to my study book, the correct answer is 4.82N/mm
What is wrong with the calculating?
What is the reason for this composition?
Homework: ANOVA Table for followed design
B
AB
Dr
-1
-1
1
(15.18,12)
1
-1
-1
(45.48.51)
-1
1
-1
(25,28,19)
1
1
(75.75,81)
Chapter 8 Solutions
Statics and Mechanics of Materials (5th Edition)
Ch. 8.4 - Define a homogeneous material.Ch. 8.4 - Prob. 2FPCh. 8.4 - Prob. 3FPCh. 8.4 - Prob. 4FPCh. 8.4 - Prob. 5FPCh. 8.4 - As the temperature increases the modulus of...Ch. 8.4 - Prob. 7FPCh. 8.4 - Prob. 8FPCh. 8.4 - Prob. 9FPCh. 8.4 - Prob. 10FP
Ch. 8.4 - The material for the 50-mm-long specimen has the...Ch. 8.4 - If the elongation of wire BC is 0.2 mm after the...Ch. 8.4 - A tension test was performed on a steel specimen...Ch. 8.4 - Data taken from a stressstrain test for a ceramic...Ch. 8.4 - Data taken from a stressstrain test for a ceramic...Ch. 8.4 - Prob. 4PCh. 8.4 - The stress-strain diagram for a steel alloy having...Ch. 8.4 - Prob. 6PCh. 8.4 - The rigid beam is supported by a pin at C and an...Ch. 8.4 - The rigid beam is supported by a pin at C and an...Ch. 8.4 - Prob. 9PCh. 8.4 - The stressstrain diagram for an aluminum alloy...Ch. 8.4 - The stressstrain diagram for an aluminum alloy...Ch. 8.4 - Prob. 12PCh. 8.4 - A bar having a length of 5 in. and cross-sectional...Ch. 8.4 - The rigid pipe is supported by a pin at A and an...Ch. 8.4 - The rigid pipe is supported by a pin at A and an...Ch. 8.4 - Prob. 16PCh. 8.4 - The rigid beam is supported by a pin at C and an...Ch. 8.4 - Prob. 18PCh. 8.4 - Prob. 19PCh. 8.6 - A 100 mm long rod has a diameter of 15 mm. If an...Ch. 8.6 - A solid circular rod that is 600 mm long and 20 mm...Ch. 8.6 - Prob. 15FPCh. 8.6 - Prob. 16FPCh. 8.6 - The acrylic plastic rod is 200 mm long and 15 mm...Ch. 8.6 - The plug has a diameter of 30 mm and fits within a...Ch. 8.6 - The elastic portion of the stress-strain diagram...Ch. 8.6 - The elastic portion of the stress-strain diagram...Ch. 8.6 - The brake pads for a bicycle tire arc made of...Ch. 8.6 - The lap joint is connected together using a 1.25...Ch. 8.6 - The lap joint is connected together using a 1.25...Ch. 8.6 - Prob. 27PCh. 8.6 - The shear stress-strain diagram for an alloy is...Ch. 8.6 - Prob. 29PCh. 8 - The elastic portion of the tension stress-strain...Ch. 8 - Prob. 2RPCh. 8 - Prob. 3RPCh. 8 - Prob. 4RPCh. 8 - Prob. 5RPCh. 8 - Prob. 6RPCh. 8 - The stress-strain diagram for polyethylene, which...Ch. 8 - The pipe with two rigid caps attached to its ends...Ch. 8 - Prob. 9RPCh. 8 - Prob. 10RP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- 20. [Ans. 9; 71.8 mm] A semi-elliptical laminated spring is made of 50 mm wide and 3 mm thick plates. The length between the supports is 650 mm and the width of the band is 60 mm. The spring has two full length leaves and five graduated leaves. If the spring carries a central load of 1600 N, find: 1. Maximum stress in full length and graduated leaves for an initial condition of no stress in the leaves. 2. The maximum stress if the initial stress is provided to cause equal stress when loaded. [Ans. 590 MPa ; 390 MPa ; 450 MPa ; 54 mm] 3. The deflection in parts (1) and (2).arrow_forwardQ6/ A helical square section spring is set inside another, the outer spring having a free length of 35 mm greater than the inner spring. The dimensions of each spring are as follows: Mean diameter (mm) Side of square section (mm) Active turns Outer Inner Spring Spring 120 70 8 7 20 15 Determine the (1) Maximum deflection of the two springs and (2) Equivalent spring rate of the two springs after sufficient load has been applied to deflect the outer spring 60 mm. Use G = 83 GN/m².arrow_forwardQ2/ The bumper springs of a railway carriage are to be made of rectangular section wire. The ratio of the longer side of the wire to its shorter side is 1.5, and the ratio of mean diameter of spring to the longer side of wire is nearly equal to 6. Three such springs are required to bring to rest a carriage weighing 25 kN moving with a velocity of 75 m/min with a maximum deflection of 200 mm. Determine the sides of the rectangular section of the wire and the mean diameter of coils when the shorter side is parallel to the axis of the spring. The allowable shear stress is not to exceed 300 MPa and G = 84 kN/mm². Q6/ A belicalarrow_forward
- 11. A load of 2 kN is dropped axially on a close coiled helical spring, from a height of 250 mm. The spring has 20 effective turns, and it is made of 25 mm diameter wire. The spring index is 8. Find the maximum shear stress induced in the spring and the amount of compression produced. The modulus of rigidity for the material of the spring wire is 84 kN/mm². [Ans. 287 MPa; 290 mm]arrow_forwardWhat is the reason for this composition?arrow_forwardHomework: ANOVA Table for followed design B AB Dr -1 -1 1 (15.18,12) 1 -1 -1 (45.48.51) -1 1 -1 (25,28,19) 1 1 (75.75,81)arrow_forward
- S B Pin 6 mm Garrow_forwardMid-Term Exam 2024/2025 Post graduate/Applied Mechanics- Metallurgy Q1/ State the type of fault in the following case, and state the structure in which it will appear. АВСАВСВАСВАСАВСАВСarrow_forwardالثانية Babakt Momentum equation for Boundary Layer S SS -Txfriction dray Momentum equation for Boundary Layer What laws are important for resolving issues 2 How to draw. 3 What's Point about this.arrow_forward
- R αι g The system given on the left, consists of three pulleys and the depicted vertical ropes. Given: ri J₁, m1 R = 2r; απ r2, J2, m₂ m1; m2; M3 J1 J2 J3 J3, m3 a) Determine the radii 2 and 3.arrow_forwardB: Solid rotating shaft used in the boat with high speed shown in Figure. The amount of power transmitted at the greatest torque is 224 kW with 130 r.p.m. Used DE-Goodman theory to determine the shaft diameter. Take the shaft material is annealed AISI 1030, the endurance limit of 18.86 kpsi and a factor of safety 1. Which criterion is more conservative? Note: all dimensions in mm. 1 AA Motor 300 Thrust Bearing Sprocket 100 9750 เอarrow_forwardQ2: The plate material of a pressure vessel is AISI 1050 QT 205 °C. The plate is rolled to a diameter of 1.2 m. The two sides of the plate are connected via a riveted joint as shown below. If the rivet material is G10500 with HB=197 and all rivet sizes M31. Find the required rivet size when the pressure vessel is subjected to an internal pressure of 500 MPa. Take safety factor = 2. 1.2m A B' A Chope olm 10.5 0.23 hopearrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Mechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage Learning
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Cengage Learning
Material Properties 101; Author: Real Engineering;https://www.youtube.com/watch?v=BHZALtqAjeM;License: Standard YouTube License, CC-BY