Chapter 8, Problem 94P

Interpretation Introduction

Interpretation:

The number of grams of glucose present in $5\text{ L}$ blood is to be calculated.

Concept introduction:

To convert one system of unit to another the conversion factors are written such that the unwanted units lie in the denominator and thus are cancelled out.

The conversion factor to convert $\text{L}$ to $\text{mL}$ is as follows:

  $\text{1L}=\text{1000 mL}$

The conversion factor to convert milligrams to grams is as follows:

  $\text{1 mg}={\text{10}}^{-3}\text{ g}$