(a) Interpretation: The number of milliequivalents of Na + ions in 1 L of solution is to be calculated. Concept introduction: One equivalent of an ion can be defined as the amount of charge an ion contributes when present in dissolved form. For example, one mole of Mg 2 + contributes 2 equivalent of Mg 2 + ions as the charge is + 2 . Similarly, one mole of SO 4 2 − contributes 2 equivalent of SO 4 2 − ions as the charge is − 2 . Conversion factors are utilized for the conversion of one unit into another unit.

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Answer 1

Question

Chapter 8, Problem 31P

Interpretation Introduction

(a)

Interpretation:

The number of milliequivalents of $Na+$ ions in $1 L$ of solution is to be calculated.

Concept introduction:

One equivalent of an ion can be defined as the amount of charge an ion contributes when present in dissolved form. For example, one mole of $Mg2+$ contributes 2 equivalent of $Mg2+$ ions as the charge is $+2$ . Similarly, one mole of $SO42−$ contributes 2 equivalent of $SO42−$ ions as the charge is $−2$ .

Conversion factors are utilized for the conversion of one unit into another unit.

Interpretation Introduction

(b)

Interpretation:

The number of milliequivalent of $Na+$ ions in $2 L$ of solution is to be calculated.

Concept introduction:

The concentration of an ion in solution is expressed in equivalents.

One equivalent of an ion can be defined as the amount of charge an ion contributes when present in dissolved form. For example, one mole of $Mg2+$ contributes 2 equivalent of $Mg2+$ ions as the charge is $+2$ . Similarly, one mole of $SO42−$ contributes 2 equivalent of $SO42−$ ions as the charge is $−2$ .

Conversion factors are utilized for the conversion of one unit into another unit.

Interpretation Introduction

(c)

Interpretation:

The number of milliequivalent of $Na+$ ions in $440 mL$ of solution is to be calculated.

Concept introduction:

The concentration of an ion in solution is expressed in equivalents.

One equivalent of an ion can be defined as amount of charge an ion contributes when present in dissolved form. For example, one mole of $Mg2+$ contributes 2 equivalent of $Mg2+$ ions as the charge is $+2$ .

The conversion factor to convert $mL$ to $L$ is given as follows:

$1 mL=10−3 L$

Conversion factors are utilized for the conversion of one unit into another unit.

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Answer 2

Question

Chapter 8, Problem 31P

Interpretation Introduction

(a)

Interpretation:

The number of milliequivalents of $Na+$ ions in $1 L$ of solution is to be calculated.

Concept introduction:

One equivalent of an ion can be defined as the amount of charge an ion contributes when present in dissolved form. For example, one mole of $Mg2+$ contributes 2 equivalent of $Mg2+$ ions as the charge is $+2$ . Similarly, one mole of $SO42−$ contributes 2 equivalent of $SO42−$ ions as the charge is $−2$ .

Conversion factors are utilized for the conversion of one unit into another unit.

Interpretation Introduction

(b)

Interpretation:

The number of milliequivalent of $Na+$ ions in $2 L$ of solution is to be calculated.

Concept introduction:

The concentration of an ion in solution is expressed in equivalents.

One equivalent of an ion can be defined as the amount of charge an ion contributes when present in dissolved form. For example, one mole of $Mg2+$ contributes 2 equivalent of $Mg2+$ ions as the charge is $+2$ . Similarly, one mole of $SO42−$ contributes 2 equivalent of $SO42−$ ions as the charge is $−2$ .

Conversion factors are utilized for the conversion of one unit into another unit.

Interpretation Introduction

(c)

Interpretation:

The number of milliequivalent of $Na+$ ions in $440 mL$ of solution is to be calculated.

Concept introduction:

The concentration of an ion in solution is expressed in equivalents.

One equivalent of an ion can be defined as amount of charge an ion contributes when present in dissolved form. For example, one mole of $Mg2+$ contributes 2 equivalent of $Mg2+$ ions as the charge is $+2$ .

The conversion factor to convert $mL$ to $L$ is given as follows:

$1 mL=10−3 L$

Conversion factors are utilized for the conversion of one unit into another unit.

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Answer 3

Question

Chapter 8, Problem 31P

Interpretation Introduction

(a)

Interpretation:

The number of milliequivalents of $Na+$ ions in $1 L$ of solution is to be calculated.

Concept introduction:

One equivalent of an ion can be defined as the amount of charge an ion contributes when present in dissolved form. For example, one mole of $Mg2+$ contributes 2 equivalent of $Mg2+$ ions as the charge is $+2$ . Similarly, one mole of $SO42−$ contributes 2 equivalent of $SO42−$ ions as the charge is $−2$ .

Conversion factors are utilized for the conversion of one unit into another unit.

Interpretation Introduction

(b)

Interpretation:

The number of milliequivalent of $Na+$ ions in $2 L$ of solution is to be calculated.

Concept introduction:

The concentration of an ion in solution is expressed in equivalents.

One equivalent of an ion can be defined as the amount of charge an ion contributes when present in dissolved form. For example, one mole of $Mg2+$ contributes 2 equivalent of $Mg2+$ ions as the charge is $+2$ . Similarly, one mole of $SO42−$ contributes 2 equivalent of $SO42−$ ions as the charge is $−2$ .

Conversion factors are utilized for the conversion of one unit into another unit.

Interpretation Introduction

(c)

Interpretation:

The number of milliequivalent of $Na+$ ions in $440 mL$ of solution is to be calculated.

Concept introduction:

The concentration of an ion in solution is expressed in equivalents.

One equivalent of an ion can be defined as amount of charge an ion contributes when present in dissolved form. For example, one mole of $Mg2+$ contributes 2 equivalent of $Mg2+$ ions as the charge is $+2$ .

The conversion factor to convert $mL$ to $L$ is given as follows:

$1 mL=10−3 L$

Conversion factors are utilized for the conversion of one unit into another unit.

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Answer 4

Question

Chapter 8, Problem 31P

Interpretation Introduction

(a)

Interpretation:

The number of milliequivalents of $Na+$ ions in $1 L$ of solution is to be calculated.

Concept introduction:

One equivalent of an ion can be defined as the amount of charge an ion contributes when present in dissolved form. For example, one mole of $Mg2+$ contributes 2 equivalent of $Mg2+$ ions as the charge is $+2$ . Similarly, one mole of $SO42−$ contributes 2 equivalent of $SO42−$ ions as the charge is $−2$ .

Conversion factors are utilized for the conversion of one unit into another unit.

Interpretation Introduction

(b)

Interpretation:

The number of milliequivalent of $Na+$ ions in $2 L$ of solution is to be calculated.

Concept introduction:

The concentration of an ion in solution is expressed in equivalents.

One equivalent of an ion can be defined as the amount of charge an ion contributes when present in dissolved form. For example, one mole of $Mg2+$ contributes 2 equivalent of $Mg2+$ ions as the charge is $+2$ . Similarly, one mole of $SO42−$ contributes 2 equivalent of $SO42−$ ions as the charge is $−2$ .

Conversion factors are utilized for the conversion of one unit into another unit.

Interpretation Introduction

(c)

Interpretation:

The number of milliequivalent of $Na+$ ions in $440 mL$ of solution is to be calculated.

Concept introduction:

The concentration of an ion in solution is expressed in equivalents.

One equivalent of an ion can be defined as amount of charge an ion contributes when present in dissolved form. For example, one mole of $Mg2+$ contributes 2 equivalent of $Mg2+$ ions as the charge is $+2$ .

The conversion factor to convert $mL$ to $L$ is given as follows:

$1 mL=10−3 L$

Conversion factors are utilized for the conversion of one unit into another unit.

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Answer 5

Chapter 8, Problem 31P

Interpretation Introduction

(a)

Interpretation:

The number of milliequivalents of $Na+$ ions in $1 L$ of solution is to be calculated.

Concept introduction:

One equivalent of an ion can be defined as the amount of charge an ion contributes when present in dissolved form. For example, one mole of $Mg2+$ contributes 2 equivalent of $Mg2+$ ions as the charge is $+2$ . Similarly, one mole of $SO42−$ contributes 2 equivalent of $SO42−$ ions as the charge is $−2$ .

Conversion factors are utilized for the conversion of one unit into another unit.

Interpretation Introduction

(b)

Interpretation:

The number of milliequivalent of $Na+$ ions in $2 L$ of solution is to be calculated.

Concept introduction:

The concentration of an ion in solution is expressed in equivalents.

One equivalent of an ion can be defined as the amount of charge an ion contributes when present in dissolved form. For example, one mole of $Mg2+$ contributes 2 equivalent of $Mg2+$ ions as the charge is $+2$ . Similarly, one mole of $SO42−$ contributes 2 equivalent of $SO42−$ ions as the charge is $−2$ .

Conversion factors are utilized for the conversion of one unit into another unit.

Interpretation Introduction

(c)

Interpretation:

The number of milliequivalent of $Na+$ ions in $440 mL$ of solution is to be calculated.

Concept introduction:

The concentration of an ion in solution is expressed in equivalents.

One equivalent of an ion can be defined as amount of charge an ion contributes when present in dissolved form. For example, one mole of $Mg2+$ contributes 2 equivalent of $Mg2+$ ions as the charge is $+2$ .

The conversion factor to convert $mL$ to $L$ is given as follows:

$1 mL=10−3 L$

Conversion factors are utilized for the conversion of one unit into another unit.

Answer 6

Chapter 8, Problem 31P

Interpretation Introduction

(a)

Interpretation:

The number of milliequivalents of $Na+$ ions in $1 L$ of solution is to be calculated.

Concept introduction:

One equivalent of an ion can be defined as the amount of charge an ion contributes when present in dissolved form. For example, one mole of $Mg2+$ contributes 2 equivalent of $Mg2+$ ions as the charge is $+2$ . Similarly, one mole of $SO42−$ contributes 2 equivalent of $SO42−$ ions as the charge is $−2$ .

Conversion factors are utilized for the conversion of one unit into another unit.

Answer 7

Chapter 8, Problem 31P

Interpretation Introduction

(a)

Interpretation:

The number of milliequivalents of $Na+$ ions in $1 L$ of solution is to be calculated.

Concept introduction:

One equivalent of an ion can be defined as the amount of charge an ion contributes when present in dissolved form. For example, one mole of $Mg2+$ contributes 2 equivalent of $Mg2+$ ions as the charge is $+2$ . Similarly, one mole of $SO42−$ contributes 2 equivalent of $SO42−$ ions as the charge is $−2$ .

Conversion factors are utilized for the conversion of one unit into another unit.

Answer 8

Interpretation Introduction

(b)

Interpretation:

The number of milliequivalent of $Na+$ ions in $2 L$ of solution is to be calculated.

Concept introduction:

The concentration of an ion in solution is expressed in equivalents.

One equivalent of an ion can be defined as the amount of charge an ion contributes when present in dissolved form. For example, one mole of $Mg2+$ contributes 2 equivalent of $Mg2+$ ions as the charge is $+2$ . Similarly, one mole of $SO42−$ contributes 2 equivalent of $SO42−$ ions as the charge is $−2$ .

Conversion factors are utilized for the conversion of one unit into another unit.

Answer 9

Interpretation Introduction

(b)

Interpretation:

The number of milliequivalent of $Na+$ ions in $2 L$ of solution is to be calculated.

Concept introduction:

The concentration of an ion in solution is expressed in equivalents.

One equivalent of an ion can be defined as the amount of charge an ion contributes when present in dissolved form. For example, one mole of $Mg2+$ contributes 2 equivalent of $Mg2+$ ions as the charge is $+2$ . Similarly, one mole of $SO42−$ contributes 2 equivalent of $SO42−$ ions as the charge is $−2$ .

Conversion factors are utilized for the conversion of one unit into another unit.

Answer 10

Interpretation Introduction

(c)

Interpretation:

The number of milliequivalent of $Na+$ ions in $440 mL$ of solution is to be calculated.

Concept introduction:

The concentration of an ion in solution is expressed in equivalents.

One equivalent of an ion can be defined as amount of charge an ion contributes when present in dissolved form. For example, one mole of $Mg2+$ contributes 2 equivalent of $Mg2+$ ions as the charge is $+2$ .

The conversion factor to convert $mL$ to $L$ is given as follows:

$1 mL=10−3 L$

Conversion factors are utilized for the conversion of one unit into another unit.

Answer 11

Interpretation Introduction

(c)

Interpretation:

The number of milliequivalent of $Na+$ ions in $440 mL$ of solution is to be calculated.

Concept introduction:

The concentration of an ion in solution is expressed in equivalents.

One equivalent of an ion can be defined as amount of charge an ion contributes when present in dissolved form. For example, one mole of $Mg2+$ contributes 2 equivalent of $Mg2+$ ions as the charge is $+2$ .

The conversion factor to convert $mL$ to $L$ is given as follows:

$1 mL=10−3 L$

Conversion factors are utilized for the conversion of one unit into another unit.

Answer 12

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Answer 13

Expert Solution & Answer

Answer 14

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Answer 15

Ch. 8.1 - Classify each substance as a heterogeneous...Ch. 8.1 - Use the appearance of each product to classify it...Ch. 8.2 - Consider the following diagrams for an aqueous...Ch. 8.2 - Classify each solution as an electrolyte or...Ch. 8.2 - Using the given number of moles, determine how...Ch. 8.2 - Prob. 8.2PP Ch. 8.2 - A solution contains the following ions:...Ch. 8.2 - If a solution contains 125 mEq of Na+ per liter,...Ch. 8.3 - Which compounds are water soluble? a. NaNO3 b. CH4...Ch. 8.3 - Prob. 8.7P

Solution Summary: The author explains the calculation of the number of milliequivalents of Na+ ions in the solution. Conversion factors are utilized for the conversion of one unit into another.

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Chapter 8 Solutions