The mass of ethylene glycol required to cause a freezing point depression of -10 o C is to be calculated. Concept introduction: The effect of addition of a non-volatile component to a solvent is that the freezing point of the solvent is reduced. This is called freezing point depression. The extent of freezing point depression is directly proportional to the amount of non-volatile solute added. Addition of one mole of any non-volatile solute decreases the freezing point of one kilogram of water by 1.86 o C For example Nacl dissociates to give Na + and Cl - Since there are two particles per mole of Nacl it reduces the freezing point calculated as follows: The formula to calculate number of moles from mass is given asfollows : The formula to calculate the depression in freezing point is as follows: The formula to calculate the molarity is as follows:

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Answer 1

Question

Chapter 8, Problem 8.96P

Interpretation Introduction

Interpretation:

The mass of ethylene glycol required to cause a freezing point depression of -10^oC is to be calculated.

Concept introduction:

The effect of addition of a non-volatile component to a solvent is that the freezing point of the solvent is reduced. This is called freezing point depression. The extent of freezing point depression is directly proportional to the amount of non-volatile solute added.

Addition of one mole of any non-volatile solute decreases the freezing point of one kilogram of water by 1.86^oC

For example Nacl dissociates to give Na⁺ and Cl^- Since there are two particles per mole of Nacl it reduces the freezing point calculated as follows:

The formula to calculate number of moles from mass is given asfollows:

The formula to calculate the depression in freezing point is as follows:

The formula to calculate the molarity is as follows:

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Answer 2

Question

Chapter 8, Problem 8.96P

Interpretation Introduction

Interpretation:

The mass of ethylene glycol required to cause a freezing point depression of -10^oC is to be calculated.

Concept introduction:

The effect of addition of a non-volatile component to a solvent is that the freezing point of the solvent is reduced. This is called freezing point depression. The extent of freezing point depression is directly proportional to the amount of non-volatile solute added.

Addition of one mole of any non-volatile solute decreases the freezing point of one kilogram of water by 1.86^oC

For example Nacl dissociates to give Na⁺ and Cl^- Since there are two particles per mole of Nacl it reduces the freezing point calculated as follows:

The formula to calculate number of moles from mass is given asfollows:

The formula to calculate the depression in freezing point is as follows:

The formula to calculate the molarity is as follows:

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Answer 3

Question

Chapter 8, Problem 8.96P

Interpretation Introduction

Interpretation:

The mass of ethylene glycol required to cause a freezing point depression of -10^oC is to be calculated.

Concept introduction:

The effect of addition of a non-volatile component to a solvent is that the freezing point of the solvent is reduced. This is called freezing point depression. The extent of freezing point depression is directly proportional to the amount of non-volatile solute added.

Addition of one mole of any non-volatile solute decreases the freezing point of one kilogram of water by 1.86^oC

For example Nacl dissociates to give Na⁺ and Cl^- Since there are two particles per mole of Nacl it reduces the freezing point calculated as follows:

The formula to calculate number of moles from mass is given asfollows:

The formula to calculate the depression in freezing point is as follows:

The formula to calculate the molarity is as follows:

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Answer 4

Question

Chapter 8, Problem 8.96P

Interpretation Introduction

Interpretation:

The mass of ethylene glycol required to cause a freezing point depression of -10^oC is to be calculated.

Concept introduction:

The effect of addition of a non-volatile component to a solvent is that the freezing point of the solvent is reduced. This is called freezing point depression. The extent of freezing point depression is directly proportional to the amount of non-volatile solute added.

Addition of one mole of any non-volatile solute decreases the freezing point of one kilogram of water by 1.86^oC

For example Nacl dissociates to give Na⁺ and Cl^- Since there are two particles per mole of Nacl it reduces the freezing point calculated as follows:

The formula to calculate number of moles from mass is given asfollows:

The formula to calculate the depression in freezing point is as follows:

The formula to calculate the molarity is as follows:

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Answer 5

Chapter 8, Problem 8.96P

Interpretation Introduction

Interpretation:

The mass of ethylene glycol required to cause a freezing point depression of -10^oC is to be calculated.

Concept introduction:

The effect of addition of a non-volatile component to a solvent is that the freezing point of the solvent is reduced. This is called freezing point depression. The extent of freezing point depression is directly proportional to the amount of non-volatile solute added.

Addition of one mole of any non-volatile solute decreases the freezing point of one kilogram of water by 1.86^oC

For example Nacl dissociates to give Na⁺ and Cl^- Since there are two particles per mole of Nacl it reduces the freezing point calculated as follows:

The formula to calculate number of moles from mass is given asfollows:

The formula to calculate the depression in freezing point is as follows:

The formula to calculate the molarity is as follows:

Answer 6

Chapter 8, Problem 8.96P

Interpretation Introduction

Interpretation:

The mass of ethylene glycol required to cause a freezing point depression of -10^oC is to be calculated.

Concept introduction:

The effect of addition of a non-volatile component to a solvent is that the freezing point of the solvent is reduced. This is called freezing point depression. The extent of freezing point depression is directly proportional to the amount of non-volatile solute added.

Addition of one mole of any non-volatile solute decreases the freezing point of one kilogram of water by 1.86^oC

For example Nacl dissociates to give Na⁺ and Cl^- Since there are two particles per mole of Nacl it reduces the freezing point calculated as follows:

The formula to calculate number of moles from mass is given asfollows:

The formula to calculate the depression in freezing point is as follows:

The formula to calculate the molarity is as follows:

Answer 7

Chapter 8, Problem 8.96P

Interpretation Introduction

Interpretation:

The mass of ethylene glycol required to cause a freezing point depression of -10^oC is to be calculated.

Concept introduction:

The effect of addition of a non-volatile component to a solvent is that the freezing point of the solvent is reduced. This is called freezing point depression. The extent of freezing point depression is directly proportional to the amount of non-volatile solute added.

Addition of one mole of any non-volatile solute decreases the freezing point of one kilogram of water by 1.86^oC

For example Nacl dissociates to give Na⁺ and Cl^- Since there are two particles per mole of Nacl it reduces the freezing point calculated as follows:

The formula to calculate number of moles from mass is given asfollows:

The formula to calculate the depression in freezing point is as follows:

The formula to calculate the molarity is as follows:

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 8.1 - Classify each substance as a heterogeneous...Ch. 8.1 - Classify each product as a solution, colloid, or...Ch. 8.2 - Consider the following diagrams for an aqueous...Ch. 8.2 - Classify each solution as an electrolyte or...Ch. 8.2 - Using the given number of moles, determine how...Ch. 8.2 - Prob. 8.6P Ch. 8.2 - A solution contains the following ions:...Ch. 8.2 - If a solution contains 125 mEq of Na+ per liter,...Ch. 8.3 - Which compounds are water soluble? a. NaNO3 b. CH4...Ch. 8.3 - Prob. 8.10P

Solution Summary: The author explains that the mass of ethylene glycol required to cause a freezing point depression is 333.688g.

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