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(a)
Interpretation:
The product shown in the image (a) should be classified into solution, colloid or heterogeneous mixture.
Concept introduction:
The solution is defined as usually a homogenous mixture of two liquids whose particle size is less than
The colloids are the class of mixtures that have particles size much greater than the solutions. They can be clearly distinguished because of the presence of particles that constitute the dispersed phase of the colloidal systems and render them opaque. Butter milk is an example of colloids. There are various subcategories of colloids such as sol, foam, aerosol, emulsions. The particle size of colloids lies in the range of
The heterogeneous mixtures are essentially those mixtures that have non-uniform composition. The average particle size of heterogeneous mixture or suspension is more than
(b)
Interpretation:
The image (b) should be classified into either solution colloid or suspension on the basis of its appearance.
Concept introduction:
The solution is defined as usually a homogenous mixture of two liquids whose particle size is less than
The colloids are the class of mixtures that have particles size much greater than the solutions. They can be clearly distinguished because of the presence of particles that constitute the dispersed phase of the colloidal systems and render them opaque. Butter milk is an example of colloids. There are various subcategories of colloids such as sol, foam, aerosol, emulsions. The particle size of colloids lies in the range of
The heterogeneous mixtures are essentially those mixtures that have non-uniform composition. The average particle size of heterogeneous mixture or suspension is more than
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Chapter 8 Solutions
EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM
- Nonearrow_forwardDevise a synthesis to prepare 4-tert-butyl-2-nitrotoluene from toluene. Complete the following reaction scheme. Part 1 of 4 Step 1 Step 2 A B Draw the structure for compound B, 4-tert-butyl-2-nitrotoluene. Click and drag to start drawing a structure. 'O Х ப:arrow_forwardWhat is N hybridized? sp3 or sp2? whyarrow_forward
- Date Unknown o Hydrated Salt Lab Sec. Name Trial I Trial 2 1. Mass of fired crucible and lid (g) 2. Mass of fired crucible, lid, and hydrated sah (g) 3. Instructor's approval of flame and apparatus 4. Mass of crucible, lid, and anhydrous salt Ist mass measurement (g) 2nd mass measurement (g) 3rd mass measurement (g). Desk No. Trial 3 48.833 46.808 213.692 51.507 9.359 46,615 50.296 48.211 45.351 50.142 48.146 45.1911 50.103 48.132 45.186 5. Final mass of crucible, lid, and anhydrous salt (g) 50.180 4.13 45.243 Calculations 1. Mass of hydrated salt (g) 2. Mass of anhydrous salt (g) 2.674 2.491 2.9239 1.3479 1.2959 1.5519 3. Mass of water lost (g) 1.32791969 1.322g 4. Percent by mass of volatile water in hydrated salt (%) 49.6% 48% 216.9% 5. Average percent HO in bydrated salt (%H,O) 5. Standard deviation of %H,O Relative standard deviation of %H,O in hydrated salt (RSD) how calculations on next page. 48.17% Data Analysis, B Data Analysis, C Data Analysis, D Experiment 5 89arrow_forwardConsidering the irregular electronic configurations we discussed for certain transitionmetals, think about the possibility of silicon (Si) having a [Ne]3s 2 3p 2 configuration vs.[Ne]3s 1 3p 3. Discuss the pros and cons of both configurations. Which one does Si actuallyadopt and why?arrow_forward(5 Pts) Currently, the last element in the periodic table is number 118, oganesson (Og). Channel your inner Dimitri Mendeleev and predict element 119’s electronic configuration, atomic mass, density, and either melting or boiling point. Justify your answers.arrow_forward
- Don't used hand raiting and don't used Ai solutionarrow_forwardShow work. don't give Ai generated solutionarrow_forward21. Zn Cl₂→ ZnCl2 22. ZnCO3 ZnO CO₂ 23. Mg + Sg MgS 24. Fe + Cl₂ FeCl3 25. Ag + S8 Ag₂S 26. K S8 K₂S 27. Al HCI AlCl3 H2 28. Mg H3PO4 Mg3(PO4)2 + H₂ 29. Cu + AgNO3 Cu(NO3)2 + Ag 30. Al + Pb(NO3)2 Pb + Al(NO3)3 31. Zn + Sn(NO3)4 Zn(NO3)2 Sn 32. Cl2 + All 3 AlCl3 _ 12 33. Br2 + Cul CuBr 12 34. KBr + Pb(NO3)2 KNO3 PbBr2 These next ones have an element shared between two different compounds. The Total amount in the Reactatnt still needs to equal the total amount in the product. 35.H₂O2 ← H₂O + 0₂ 36. C₂Ho CO2 + H₂O 37. Zn + HCI → ZnCl+ H₂ 38. NH3 + _HCl → NH.C 39. Mg(OH)2 + H3PO4 → H₂O+ Mg3(PO4)2 40. NHẠOH + FeCl3 NH4Cl + Fe(OH)3arrow_forward
- Don't used hand raiting and don't used Ai solutionarrow_forwardBalance the following equations Synthesis Ca 1. Mg + Cl₂ → MgCl2Syn 2. Al + 302 -> 2A1203Com 3. P4 + 502 4. Bi + + Cl₂ 5. H2 + N2 ↑ 6. Zn + 02 7. Cu + 02 8. Sn + 9. Na 10. 11. AR Ag + Cl₂ S8 I2 ↑ ↑ ↑ ↑ Pb + 12. Al + Br₂ 13. Fe + F2 ↑ 14. Sn + 15. Sb + 16. Ca + 17. Ba + 02 ↑ ↑ ↑ P4010 Com BiCl, Syn NH3 Syn Zno Com Cu2O com SnCl4 Syn Na2S Syn Agl Syn Pbo Com AlBr, yn FeF3 Syn Sno com Sb₂Ss Syn Cao cơm Bao cơm 18. Mg + P4 -> Mg3P2 Syn 19. K + K&N Syn ZnS Syn 20. Znarrow_forwardNonearrow_forward
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