Chapter 8, Problem 8.100P

Interpretation Introduction

(a)

Interpretation:

The solution with a higher boiling point in the given pair should be determined:

0.10 M NaOH and 0.10 M glucose

Concept Introduction:

Depression in freezing point and elevation in boiling are the colligative properties. Colligative properties can be defined as properties that mainly depend on the number of particles present in the solution.

Both of these properties can be calculated with the help of $\text{Kb}$ and ${\text{K}}_{\text{f}}$ constant values. Here $\text{Kb}$ represents the Ebullioscopic constant, whereas ${\text{K}}_{\text{f}}$ represents the molal freezing point depression constant.

  $\begin{array}{l}\Delta {\text{T}}_{\text{f}}{\text{= K}}_{\text{f}}\times \text{m}\\ \Delta {\text{T}}_{\text{b}}\text{= Kb }\times \text{ m}\end{array}$

Here:

• $\Delta {\text{T}}_{\text{f}}$ and $\Delta {\text{T}}_{\text{b}}$<= Change in freezing point and boiling point of the solvent
• m = molality of solution

Interpretation Introduction

(b)

Interpretation:

The solution with a higher boiling point in the given pair should be determined:

0.20 M NaCl and 0.15 M ${\text{CaCl}}_{\text{2}}$

Concept Introduction:

Depression in freezing point and elevation in boiling are the colligative properties. Colligative properties can be defined as properties that mainly depend on the number of particles present in the solution.

Both of these properties can be calculated with the help of $\text{Kb}$ and ${\text{K}}_{\text{f}}$ constant values. Here $\text{Kb}$ represents the Ebullioscopic constant whereas ${\text{K}}_{\text{f}}$ represents the molal freezing point depression constant.

  $\begin{array}{l}\Delta {\text{T}}_{\text{f}}{\text{= K}}_{\text{f}}\times \text{m}\\ \Delta {\text{T}}_{\text{b}}\text{= Kb }\times \text{ m}\end{array}$

Here:

• $\Delta {\text{T}}_{\text{f}}$ and $\Delta {\text{T}}_{\text{b}}$= Change in freezing point and boiling point of the solvent
• m = molality of solution

Interpretation Introduction

(c)

Interpretation:

The solution with higher boiling point in the given pair should be determined:

0.10 M ${\text{Na}}_{\text{2}}\text{SO}$ and 0.10 M ${\text{Na}}_{\text{3}}{\text{PO}}_{\text{4}}$

Concept Introduction:

Depression in freezing point and elevation in boiling are the colligative properties. Colligative properties can be defined as properties that mainly depend on the number of particles present in the solution.

Both of these properties can be calculated with the help of $\text{Kb}$ and ${\text{K}}_{\text{f}}$ constant values. Here, $\text{Kb}$ represents the Ebullioscopic constant whereas ${\text{K}}_{\text{f}}$ represents the molal freezing point depression constant.

  $\begin{array}{l}\Delta {\text{T}}_{\text{f}}{\text{= K}}_{\text{f}}\times \text{m}\\ \Delta {\text{T}}_{\text{b}}\text{= Kb }\times \text{ m}\end{array}$

Here:

• $\Delta {\text{T}}_{\text{f}}$ and $\Delta {\text{T}}_{\text{b}}$= Change in freezing point and boiling point of the solvent.
• m = molality of the solution.

Interpretation Introduction

(d)

Interpretation:

The solution with higher boiling point in the given pair should be determined:

0.10 M glucose and 0.20 M glucose

Concept Introduction:

Depression in freezing point and elevation in boiling are the colligative properties. Colligative properties can be defined as properties that mainly depend on the number of particles present in the solution.

Both of these properties can be calculated with the help of $\text{Kb}$ and ${\text{K}}_{\text{f}}$ constant values. Here $\text{Kb}$ represents the Ebullioscopic constant whereas ${\text{K}}_{\text{f}}$ represents the molal freezing point depression constant.

  $\begin{array}{l}\Delta {\text{T}}_{\text{f}}{\text{= K}}_{\text{f}}\times \text{m}\\ \Delta {\text{T}}_{\text{b}}\text{= Kb }\times \text{ m}\end{array}$

Here:

• $\Delta {\text{T}}_{\text{f}}$ and $\Delta {\text{T}}_{\text{b}}$= Change in freezing point and boiling point of the solvent
• m = molality of solution