The atoms L i , N a and K has to be arranged in order of increasing positive electron affinity . Concept Introduction: Electron Affinity: It is energy change taking place when one electron is added to an atom which is neutral in its gaseous state forming an anion. Along the period, electron affinity increases from left to right expect for Group 2A, Group 8A and Group 5A. In the case of Group 2A and Group 8A elements, the subshells are completed so the electron has to be added to a subshell with higher energy. In the case of Group 5A elements, the p subshell is half–fill hence has high electron–electron repulsion. Down the group, the electron affinity values vary a little.

Question

Want to see the full answer?

Answer 1

Question

Chapter 8, Problem 8.59QP

(a)

Interpretation Introduction

Interpretation: The atoms Li, Na and K has to be arranged in order of increasing positive electron affinity.

Concept Introduction:

Electron Affinity: It is energy change taking place when one electron is added to an atom which is neutral in its gaseous state forming an anion.

Along the period, electron affinity increases from left to right expect for Group 2A, Group 8A and Group 5A.

In the case of Group 2A and Group 8A elements, the subshells are completed so the electron has to be added to a subshell with higher energy.

In the case of Group 5A elements, the p subshell is half–fill hence has high electron–electron repulsion.

Down the group, the electron affinity values vary a little.

(b)

Interpretation Introduction

Interpretation: The atoms F, Cl, Br and I has to be arranged in order of increasing positive electron affinity.

Concept Introduction:

Electron Affinity: It is energy change taking place when one electron is added to an atom which is neutral in its gaseous state forming an anion.

Along the period, electron affinity increases from left to right expect for Group 2A, Group 8A and Group 5A.

In the case of Group 2A and Group 8A elements, the subshells are complete so the electron has to be added to a subshell with higher energy.

In the case of Group 5A elements, the p subshell is half–fill hence has high electron–electron repulsion.

Down the group, the electron affinity values vary a little.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Shown below are five NMR spectra for five different C6H10O2 compounds. For each spectrum, draw the structure of the compound, and assign the spectrum by labeling H's in your structure (or in a second drawing of the structure) with the chemical shifts of the corresponding signals (which can be estimated to nearest 0.1 ppm). IR information is also provided. As a reminder, a peak near 1700 cm-1 is consistent with the presence of a carbonyl (C=O), and a peak near 3300 cm-1 is consistent with the presence of an O–H. Extra information: For C6H10O2 , there must be either 2 double bonds, or 1 triple bond, or two rings to account for the unsaturation. There is no two rings for this problem. A strong band was observed in the IR at 1717 cm-1

Predict the major products of the organic reaction below. : ☐ + Х ك OH 1. NaH 2. CH₂Br Click and drag to start drawing a structure.

NG NC 15Show all the steps you would use to synthesize the following products shown below using benzene and any organic reagent 4 carbons or less as your starting material in addition to any inorganic reagents that you have learned. NO 2 NC SO3H NO2 OH