The given ionization energy has to be matched with the given electronic configuration of atoms. Concept Introduction: An atom can be converted into an ion by removing an electron from its outermost shell or adding electron to the outermost shell. An amount of energy is required to remove an electron from the outermost shell of an atom to form a cation. The minimum energy required for removing an electron from an atom in gaseous phase is known as ionization energy . If one electron is removed from the atom to form a cation, the energy required is known as first ionization energy . If another electron is removed from the formed ion, the energy required is known as second ionization energy and this goes on. Second ionization energy is always higher than the first ionization energy because the effective nuclear charge increases. The trend followed in a periodic table for ionization energy is, it increases across the period and decreases down the group. This is because; across the period, the electrons are added to the same orbital and hence decrease in shielding. However, down the group, the electrons are added to a new sub-shell and hence increase in shielding. To compare: the ionization energies with the electronic configuration given

Question

Want to see the full answer?

Answer 1

Question

Chapter 8, Problem 8.54QP

Interpretation Introduction

Interpretation:

The given ionization energy has to be matched with the given electronic configuration of atoms.

Concept Introduction:

An atom can be converted into an ion by removing an electron from its outermost shell or adding electron to the outermost shell. An amount of energy is required to remove an electron from the outermost shell of an atom to form a cation. The minimum energy required for removing an electron from an atom in gaseous phase is known as ionization energy.

If one electron is removed from the atom to form a cation, the energy required is known as first ionization energy. If another electron is removed from the formed ion, the energy required is known as second ionization energy and this goes on. Second ionization energy is always higher than the first ionization energy because the effective nuclear charge increases.

The trend followed in a periodic table for ionization energy is, it increases across the period and decreases down the group. This is because; across the period, the electrons are added to the same orbital and hence decrease in shielding. However, down the group, the electrons are added to a new sub-shell and hence increase in shielding.

To compare: the ionization energies with the electronic configuration given

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

2. Draw the missing structure(s) in each of the following reactions. The missing structure(s) can be a starting material or the major reaction product(s). C5H10 H-CI CH2Cl2 CI

Draw the products of the stronger acid protonating the other reactant. དའི་སྐད”“ H3C OH H3C CH CH3 KEq Product acid Product base

Draw the products of the stronger acid protonating the other reactant. H3C NH2 NH2 KEq H3C-CH₂ 1. Product acid Product base

Answer 2

Question

Chapter 8, Problem 8.54QP

Interpretation Introduction

Interpretation:

The given ionization energy has to be matched with the given electronic configuration of atoms.

Concept Introduction:

An atom can be converted into an ion by removing an electron from its outermost shell or adding electron to the outermost shell. An amount of energy is required to remove an electron from the outermost shell of an atom to form a cation. The minimum energy required for removing an electron from an atom in gaseous phase is known as ionization energy.

If one electron is removed from the atom to form a cation, the energy required is known as first ionization energy. If another electron is removed from the formed ion, the energy required is known as second ionization energy and this goes on. Second ionization energy is always higher than the first ionization energy because the effective nuclear charge increases.

The trend followed in a periodic table for ionization energy is, it increases across the period and decreases down the group. This is because; across the period, the electrons are added to the same orbital and hence decrease in shielding. However, down the group, the electrons are added to a new sub-shell and hence increase in shielding.

To compare: the ionization energies with the electronic configuration given

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 8, Problem 8.54QP

Interpretation Introduction

Interpretation:

The given ionization energy has to be matched with the given electronic configuration of atoms.

Concept Introduction:

An atom can be converted into an ion by removing an electron from its outermost shell or adding electron to the outermost shell. An amount of energy is required to remove an electron from the outermost shell of an atom to form a cation. The minimum energy required for removing an electron from an atom in gaseous phase is known as ionization energy.

If one electron is removed from the atom to form a cation, the energy required is known as first ionization energy. If another electron is removed from the formed ion, the energy required is known as second ionization energy and this goes on. Second ionization energy is always higher than the first ionization energy because the effective nuclear charge increases.

The trend followed in a periodic table for ionization energy is, it increases across the period and decreases down the group. This is because; across the period, the electrons are added to the same orbital and hence decrease in shielding. However, down the group, the electrons are added to a new sub-shell and hence increase in shielding.

To compare: the ionization energies with the electronic configuration given

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 8, Problem 8.54QP

Interpretation Introduction

Interpretation:

The given ionization energy has to be matched with the given electronic configuration of atoms.

Concept Introduction:

An atom can be converted into an ion by removing an electron from its outermost shell or adding electron to the outermost shell. An amount of energy is required to remove an electron from the outermost shell of an atom to form a cation. The minimum energy required for removing an electron from an atom in gaseous phase is known as ionization energy.

If one electron is removed from the atom to form a cation, the energy required is known as first ionization energy. If another electron is removed from the formed ion, the energy required is known as second ionization energy and this goes on. Second ionization energy is always higher than the first ionization energy because the effective nuclear charge increases.

The trend followed in a periodic table for ionization energy is, it increases across the period and decreases down the group. This is because; across the period, the electrons are added to the same orbital and hence decrease in shielding. However, down the group, the electrons are added to a new sub-shell and hence increase in shielding.

To compare: the ionization energies with the electronic configuration given

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 8, Problem 8.54QP

Interpretation Introduction

Interpretation:

The given ionization energy has to be matched with the given electronic configuration of atoms.

Concept Introduction:

An atom can be converted into an ion by removing an electron from its outermost shell or adding electron to the outermost shell. An amount of energy is required to remove an electron from the outermost shell of an atom to form a cation. The minimum energy required for removing an electron from an atom in gaseous phase is known as ionization energy.

If one electron is removed from the atom to form a cation, the energy required is known as first ionization energy. If another electron is removed from the formed ion, the energy required is known as second ionization energy and this goes on. Second ionization energy is always higher than the first ionization energy because the effective nuclear charge increases.

The trend followed in a periodic table for ionization energy is, it increases across the period and decreases down the group. This is because; across the period, the electrons are added to the same orbital and hence decrease in shielding. However, down the group, the electrons are added to a new sub-shell and hence increase in shielding.

To compare: the ionization energies with the electronic configuration given

Answer 6

Chapter 8, Problem 8.54QP

Interpretation Introduction

Interpretation:

The given ionization energy has to be matched with the given electronic configuration of atoms.

Concept Introduction:

An atom can be converted into an ion by removing an electron from its outermost shell or adding electron to the outermost shell. An amount of energy is required to remove an electron from the outermost shell of an atom to form a cation. The minimum energy required for removing an electron from an atom in gaseous phase is known as ionization energy.

If one electron is removed from the atom to form a cation, the energy required is known as first ionization energy. If another electron is removed from the formed ion, the energy required is known as second ionization energy and this goes on. Second ionization energy is always higher than the first ionization energy because the effective nuclear charge increases.

The trend followed in a periodic table for ionization energy is, it increases across the period and decreases down the group. This is because; across the period, the electrons are added to the same orbital and hence decrease in shielding. However, down the group, the electrons are added to a new sub-shell and hence increase in shielding.

To compare: the ionization energies with the electronic configuration given

Answer 7

Chapter 8, Problem 8.54QP

Interpretation Introduction

Interpretation:

The given ionization energy has to be matched with the given electronic configuration of atoms.

Concept Introduction:

An atom can be converted into an ion by removing an electron from its outermost shell or adding electron to the outermost shell. An amount of energy is required to remove an electron from the outermost shell of an atom to form a cation. The minimum energy required for removing an electron from an atom in gaseous phase is known as ionization energy.

If one electron is removed from the atom to form a cation, the energy required is known as first ionization energy. If another electron is removed from the formed ion, the energy required is known as second ionization energy and this goes on. Second ionization energy is always higher than the first ionization energy because the effective nuclear charge increases.

The trend followed in a periodic table for ionization energy is, it increases across the period and decreases down the group. This is because; across the period, the electrons are added to the same orbital and hence decrease in shielding. However, down the group, the electrons are added to a new sub-shell and hence increase in shielding.

To compare: the ionization energies with the electronic configuration given

Answer 8

Expert Solution & Answer

Answer 9

Expert Solution & Answer

Answer 10

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 11

Ch. 8.2 - Practice Exercise An atom of a certain element has...Ch. 8.2 - Review of concepts Identify the elements whose...Ch. 8.3 - Practice Exercise Arrange the following atoms in...Ch. 8.3 - Prob. 1RC Ch. 8.3 - Prob. 2PE Ch. 8.3 - Prob. 2RC Ch. 8.4 - Prob. 1PE Ch. 8.4 - Prob. 1RC Ch. 8.5 - Prob. 1PE Ch. 8.5 - Prob. 1RC

Videos

Want to see the full answer?

Chapter 8 Solutions