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Physical Chemistry
2nd Edition
ISBN: 9781133958437
Author: Ball, David W. (david Warren), BAER, Tomas
Publisher: Wadsworth Cengage Learning,
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Chapter 8, Problem 8.58E
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A certain liquid X has a normal freezing point of 7.00°C and a freezing point depression constant =Kf 7.41·°C·kgmol−1. A solution is prepared by dissolving some iron(III) chloride (FeCl3) in 700.g of X. This solution freezes at 3.5°C. Calculate the mass of FeCl3 that was dissolved. Be sure your answer is rounded to the correct number of significiant digits.
The partial molar volumes of two liquids A and B in a mixture in which the mole fraction of A is 0.3713 are 188.2 cm3 mol−1 and 176.14 cm3 mol−1, respectively. The molar masses of the A and B are 241.1 g mol−1 and 198.2 g mol−1. What is the volume of a solution of mass 1.000 kg?
10D. Colligative property measurements are instrumental
in understanding the nature of ionic solutions. The
osmotic pressure of a 0.010 mol/L solution of NaBr was
found to be 0.45 bar.
(a) What concentration of solute particles is consistent
with this osmotic pressure at 25°C?
(b) Why does this value differ from the stated molarity?
Assume that no errors were made in the measurements.
(Hint: Remember that colligative properties reflect the
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Chapter 8 Solutions
Physical Chemistry
Ch. 8 - 8.1. What is the charge on a small sphere that is...Ch. 8 - 8.2. The force of attraction due to gravity...Ch. 8 - 8.3. Two small metallic bodies are given opposite...Ch. 8 - Prob. 8.4ECh. 8 - What is the force of attraction between a...Ch. 8 - Prob. 8.6ECh. 8 - 8.7. How much work is required to move a single...Ch. 8 - 8.8. Explain why an electromotive force is not, in...Ch. 8 - Prob. 8.9ECh. 8 - For each of the following reactions, determine the...
Ch. 8 - Prob. 8.11ECh. 8 - Prob. 8.12ECh. 8 - 8.13. Is the disproportionation reaction...Ch. 8 - Prob. 8.14ECh. 8 - Prob. 8.15ECh. 8 - Prob. 8.16ECh. 8 - Prob. 8.17ECh. 8 - 8.18. Determine and for each of the following...Ch. 8 - Prob. 8.19ECh. 8 - Prob. 8.20ECh. 8 - Prob. 8.21ECh. 8 - Prob. 8.22ECh. 8 - Prob. 8.23ECh. 8 - Prob. 8.24ECh. 8 - Prob. 8.25ECh. 8 - Prob. 8.26ECh. 8 - Prob. 8.27ECh. 8 - What is the Zn2+:Cu2+ ratio on a Daniell cell that...Ch. 8 - Prob. 8.29ECh. 8 - Determine the voltage of this reaction with the...Ch. 8 - The thermite reaction can act as the basis of an...Ch. 8 - A concentration cell has different concentrations...Ch. 8 - Prob. 8.34ECh. 8 - Prob. 8.35ECh. 8 - a What is the equilibrium constant for the...Ch. 8 - Prob. 8.37ECh. 8 - Prob. 8.38ECh. 8 - Prob. 8.39ECh. 8 - Prob. 8.40ECh. 8 - Prob. 8.41ECh. 8 - Consider the following formation reaction for HI:...Ch. 8 - Prob. 8.43ECh. 8 - 8.44. Determine an expression for , the change in...Ch. 8 - Prob. 8.45ECh. 8 - Prob. 8.46ECh. 8 - Determine the equilibrium constant for the...Ch. 8 - Prob. 8.48ECh. 8 - Prob. 8.49ECh. 8 - What is the solubility product constant of Hg2Cl2,...Ch. 8 - Prob. 8.51ECh. 8 - Prob. 8.52ECh. 8 - Prob. 8.53ECh. 8 - Prob. 8.54ECh. 8 - Prob. 8.55ECh. 8 - Prob. 8.56ECh. 8 - Prob. 8.57ECh. 8 - Show that a can be written as n+mnn+n+nn, where m...Ch. 8 - Prob. 8.59ECh. 8 - Prob. 8.60ECh. 8 - What molality of NaCl is necessary to have the...Ch. 8 - Prob. 8.62ECh. 8 - Prob. 8.63ECh. 8 - Calculate the molar enthalpy of formation of I(aq)...Ch. 8 - Prob. 8.65ECh. 8 - Hydrofluoric acid, HF(aq), is a weak acid that is...Ch. 8 - Prob. 8.68ECh. 8 - Prob. 8.69ECh. 8 - Prob. 8.70ECh. 8 - Prob. 8.71ECh. 8 - Prob. 8.72ECh. 8 - The mean activity coefficient for an aqueous...Ch. 8 - Human blood plasma is approximately 0.9NaCl. What...Ch. 8 - Under what conditions does the extended...Ch. 8 - Prob. 8.76ECh. 8 - Approximate the expected voltage for the following...Ch. 8 - Prob. 8.78ECh. 8 - Prob. 8.79ECh. 8 - Prob. 8.80ECh. 8 - a The salt NaNO3 can be thought of as...Ch. 8 - Prob. 8.82ECh. 8 - What is the estimated velocity for Cu2+ ions...Ch. 8 - Prob. 8.84ECh. 8 - Prob. 8.85ECh. 8 - Prob. 8.86ECh. 8 - Calculate a the solubility product constant for...
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Solutions: Crash Course Chemistry #27; Author: Crash Course;https://www.youtube.com/watch?v=9h2f1Bjr0p4;License: Standard YouTube License, CC-BY