Interpretation:
The structure of codling moth sex pheromone is to be given with the help of given information.
Concept Introduction:
Electrophiles are electron deficient species which has positive or partially positive charge. Lewis acids are electrophiles which accept electron pair.
Nucleophiles are electron rich species which has negative or partially negative charge. Lewis bases are nucleophiles which donate electron pair.
Free radical is an atom, molecule or ion that has unpaired electrons which makes it highly chemically reactive.
Substitution reaction: A reaction in which one of the hydrogen atoms of a hydrocarbon or a
Elimination reaction: A reaction in which two substituent groups are detached and a double bond is formed is called elimination reaction.
Addition reaction: It is the reaction in which unsaturated bonds are converted to saturated molecules by the addition of molecules.
The reaction in which hydrogen is added to the compound in the presence of catalyst is known as hydrogenation.
The number of moles of hydrogen absorbed will be equal to the number of double bonds.
Reduction is a process in which hydrogen atoms are added to a compound. Usual reagents used in the reduction process are
The reaction in which the
Reduction is a process in which the addition of hydrogen atoms to a compound takes place.
During an addition reaction unsaturated bonds are converted into saturated molecules by the addition of molecules
Ozonolysis is a process in which the given alkene is cleaved with ozone
The
First, give priority according to Cahn-Ingold-Prelog convention rules:
The higher the
If priority cannot be assigned according to atomic mass, then assign the priority according to the first point of difference.
If both the priority groups are on the same side of a double-bonded carbon atom, then it is known as
But if both the priority groups are diagonal to each other, then it is
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Organic Chemistry
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- Calculate the packing factor of CaTiO3. It has a perovskite structure. Data: ionic radii Co²+ = 0.106 nm, Ti4+ = 0.064 nm, O² = 0.132 nm; lattice constant is a = 2(rTi4+ + ro2-). Ca2+ 02- T14+ Consider the ions as rigid spheres. 1. 0.581 or 58.1% 2. -0.581 or -58.1 % 3. 0.254 or 25.4%arrow_forwardGeneral formula etherarrow_forwardPlease provide the retrosynthetic analysis and forward synthesis of the molecule on the left from the starting material on the right. Please include hand-drawn structures! will upvote! Please correct answer and don't used hand raitingarrow_forward
- Please provide the retrosynthetic analysis and forward synthesis of the molecule on the left from the starting material on the right. Please include hand-drawn structures! will upvote!arrow_forward(please correct answer and don't used hand raiting) Please provide the retrosynthetic analysis and forward synthesis of the molecule on the left from the starting material on the right. Please include hand-drawn structures! will upvote!arrow_forwardCaTiO3 has a perovskite structure. Calculate the packing factor.Data: ionic radii Co+2 = 0.106 nm, Ti+4 = 0.064 nm, O-2 = 0.132 nm; lattice constant is a = 2(rTi4+ + rO-2).(a) 0.581(b) -0.581(c) 0.254(d) -0.254arrow_forward
- In the initial linear section of the stress-strain curve of a metal or alloy. Explain from the point of view of atomic structure?(a) No, the atomic level properties of the material can never be related to the linear section.(b) The elastic zone is influenced by the strength of the bonds between atoms.(c) The stronger the bond, the less rigid and the lower the Young's Modulus of the material tested.(d) The stronger the bond, the less stress is necessary to apply to the material to deform it elastically.arrow_forwardThe degree of polymerization of polytetrafluoroethylene (Teflon) is 7500 (mers/mol). If all polymer chains have equal length, state the molecular weight of the polymer and the total number of chains in 1000 g of the polymer(a) 50 000 g/mol; 0.03·1020 chains(b) 100 000 g/mol; 1.03·1020 chains(c) 750 000 g/mol; 8.03·1020 chainsarrow_forwardIn natural rubber or polyisoprene, the trans isomer leads to a higher degree of crystallinity and density than the cis isomer of the same polymer, because(a) it is more symmetrical and regular.(b) it is less symmetrical.(c) it is irregular.arrow_forward
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