The reason why the double bond of tetrachloroethene is undetectable in the bromine test for unsaturation is to be explained. Concept Introduction: Bromination leads to the addition reaction of alkenes or alkynes and also the formation of haloalkanes . This is used as a test for the detection of unsaturated compounds.

Question

When 30 cm3 of a gaseous hydrocarbon was exploded with 210cm3 of oxygen the residual gases occupied volume of 150cm3. After shaking the residual gases with excess aqueous sodium hydroxide, the final volume was 30cm3.(All volumes were measured at room temperature and pressure.) The hydrocarbon has a number of isomers. Draw the displayed formulae and name 2 of the isomers of the hydrocarbon that illustrate each of the following types of isomerism below (i.e. 2 isomers must be drawn for each type of isomerism) (i) chain (ii)functional group

Answer 1

Question

Chapter 8, Problem 41P

Interpretation Introduction

Interpretation:

The reason why the double bond of tetrachloroethene is undetectable in the bromine test for unsaturation is to be explained.

Concept Introduction:

Bromination leads to the addition reaction of alkenes or alkynes and also the formation of haloalkanes. This is used as a test for the detection of unsaturated compounds.

Expert Solution & Answer

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Students have asked these similar questions

When 30 cm3 of a gaseous hydrocarbon was exploded with 210cm3 of oxygen the residual gases occupied volume of 150cm3. After shaking the residual gases with excess aqueous sodium hydroxide, the final volume was 30cm3.(All volumes were measured at room temperature and pressure.) The hydrocarbon has a number of isomers. Draw the displayed formulae and name 2 of the isomers of the hydrocarbon that illustrate each of the following types of isomerism below (i.e. 2 isomers must be drawn for each type of isomerism) (i) chain (ii)functional group

b) i) Draw the different structural isomers of the 6-membered ring compound [GAAIBNPAS]H6 in which there are alternating Group 13 and 15 elements. ii) The isomers containing both B-N and AI-N bonding are the most stable. Explain why this is the case. ii) How would you expect the structure and reactivity of the heterocycles [GAAIBNPAS]H6 to compare with borazine? iv) While borazine exists as a planar ring compound, the [GAAIBNPAS]H6 ring compounds dimerize. Explain these observations. H -ЕН -E H-E НЕ ЕН E НЕ- ЕН H `E H. H É-H НЕ E = Heteroatom エー山、 w-I

Assuming that benzaldehyde is the limiting reagent for the synthesis of stilbene, that stilbene is the limiting reagent for the synthesis of stilbene dibromide, and that stilbene dibromide is the limiting reagent for the synthesis of diphenylacetylene; what is the overall % yield of diphenylacetylene from benzaldehyde given the percentage yield of each step of the reaction sequence as follows? Give only two significant digits. If the answer is a whole number with two digits, do not include the decimal. benza Idehy de Notes: 66% stil be ne 23% stilbene dibromi de 66% dipheny lacetyle ne