Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN: 9781133939146
Author: Katz, Debora M.
Publisher: Cengage Learning
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Chapter 8, Problem 22PQ
To determine
The gravitational potential energy of car near the surface of Earth and in the geosynchronous orbit.
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Chapter 8 Solutions
Physics for Scientists and Engineers: Foundations and Connections
Ch. 8.1 - Comet Halleys Orbital Parameters Figure 8.1 shows...Ch. 8.2 - Prob. 8.2CECh. 8.2 - Prob. 8.3CECh. 8.3 - In Figure 8.11, a person launches a ball off of a...Ch. 8 - Case Study From Figure 8.1B for Comet Halley, is...Ch. 8 - Estimate the kinetic energy of the following: a....Ch. 8 - Prob. 3PQCh. 8 - Prob. 4PQCh. 8 - A 0.430-kg soccer ball is kicked at an initial...Ch. 8 - Prob. 6PQ
Ch. 8 - According to a scaled woman, a 67.7-kg man runs...Ch. 8 - Prob. 8PQCh. 8 - Prob. 9PQCh. 8 - Prob. 10PQCh. 8 - Prob. 11PQCh. 8 - Prob. 12PQCh. 8 - Prob. 13PQCh. 8 - In each situation shown in Figure P8.12, a ball...Ch. 8 - Prob. 15PQCh. 8 - Prob. 16PQCh. 8 - Prob. 17PQCh. 8 - Prob. 18PQCh. 8 - A ball of mass 0.40 kg hangs straight down on a...Ch. 8 - Prob. 20PQCh. 8 - Prob. 21PQCh. 8 - Prob. 22PQCh. 8 - One type of toy car contains a spring that is...Ch. 8 - A block is placed on top of a vertical spring, and...Ch. 8 - Rubber tends to be nonlinear as an elastic...Ch. 8 - A block is hung from a vertical spring. The spring...Ch. 8 - A spring of spring constant k lies along an...Ch. 8 - A block on a frictionless, horizontal surface is...Ch. 8 - A falcon is soaring over a prairie, flying at a...Ch. 8 - A stellar black hole may form when a massive star...Ch. 8 - A newly established colony on the Moon launches a...Ch. 8 - The Flybar high-tech pogo stick is advertised as...Ch. 8 - An uncrewed mission to the nearest star, Proxima...Ch. 8 - A small ball is tied to a string and hung as shown...Ch. 8 - Prob. 35PQCh. 8 - Prob. 36PQCh. 8 - Prob. 37PQCh. 8 - Prob. 38PQCh. 8 - Figure P8.39 shows two bar charts. In each, the...Ch. 8 - Prob. 40PQCh. 8 - If a spacecraft is launched from the Moon at the...Ch. 8 - A 1.50-kg box rests atop a massless vertical...Ch. 8 - A man unloads a 5.0-kg box from a moving van by...Ch. 8 - Starting at rest, Tina slides down a frictionless...Ch. 8 - Prob. 45PQCh. 8 - Karen and Randy are playing with a toy car and...Ch. 8 - An intrepid physics student decides to try bungee...Ch. 8 - A block of mass m = 1.50 kg attached to a...Ch. 8 - Prob. 49PQCh. 8 - A jack-in-the-box is actually a system that...Ch. 8 - A side view of a half-pipe at a skateboard park is...Ch. 8 - Prob. 52PQCh. 8 - Prob. 53PQCh. 8 - Prob. 54PQCh. 8 - A particle moves in one dimension under the action...Ch. 8 - Prob. 56PQCh. 8 - Prob. 57PQCh. 8 - Prob. 58PQCh. 8 - Prob. 59PQCh. 8 - Much of the mass of our Milky Way galaxy is...Ch. 8 - A stellar black hole may form when a massive star...Ch. 8 - Prob. 62PQCh. 8 - Prob. 63PQCh. 8 - FIGURE 8.38 Comparison of a circular and an...Ch. 8 - A 50.0-g toy car is released from rest on a...Ch. 8 - Prob. 66PQCh. 8 - The Earths perihelion distance (closest approach...Ch. 8 - After ripping the padding off a chair you are...Ch. 8 - A In a classic laboratory experiment, a cart of...Ch. 8 - A block is attached to a spring, and the block...Ch. 8 - At the start of a basketball game, a referee...Ch. 8 - At the start of a basketball game, a referee...Ch. 8 - Prob. 73PQCh. 8 - Prob. 74PQCh. 8 - At 220 m, the bungee jump at the Verzasca Dam in...Ch. 8 - Prob. 76PQCh. 8 - A block of mass m1 = 4.00 kg initially at rest on...Ch. 8 - A Eric is twirling a ball of mass m = 0.150 kg...Ch. 8 - Prob. 79PQCh. 8 - Prob. 80PQCh. 8 - Prob. 81PQCh. 8 - Prob. 82PQCh. 8 - Prob. 83PQCh. 8 - Prob. 84PQ
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- A small block of mass m = 200 g is released from rest at point along the horizontal diameter on the inside of a frictionless, hemispherical bowl of radius R = 30.0 cm (Fig. P8.43). Calculate (a) the gravitational potential energy of the block-Earth system when the block is at point relative to point . (b) the kinetic energy of the block at point . (c) its speed at point B, and (d) its kinetic energy and the potential energy when the block is at point . Figure P8.43 Problems 43 and 44.arrow_forwardIn each situation shown in Figure P8.12, a ball moves from point A to point B. Use the following data to find the change in the gravitational potential energy in each case. You can assume that the radius of the ball is negligible. a. h = 1.35 m, = 25, and m = 0.65 kg b. R = 33.5 m and m = 756 kg c. R = 33.5 m and m = 756 kg FIGURE P8.12 Problems 12, 13, and 14.arrow_forwardA jack-in-the-box is actually a system that consists of an object attached to the top of a vertical spring (Fig. P8.50). a. Sketch the energy graph for the potential energy and the total energy of the springobject system as a function of compression distance x from x = xmax to x = 0, where xmax is the maximum amount of compression of the spring. Ignore the change in gravitational potential energy. b. Sketch the kinetic energy of the system between these points the two distances in part (a)on the same graph (using a different color). FIGURE P8.50 Problems 50 and 79arrow_forward
- A 4.00-kg particle moves from the origin to position , having coordinates x = 5.00 m and y = 5.00 m (Fig. P7.31). One force on the particle is the gravitational force acting in the negative y direction. Using Equation 7.3, calculate the work done by the gravitational force on the particle as it goes from O to along (a) the purple path, (b) the red path, and (c) the blue path, (d) Your results should all be identical. Why? Figure P7.31arrow_forwardA nonconstant force is exerted on a particle as it moves in the positive direction along the x axis. Figure P9.26 shows a graph of this force Fx versus the particles position x. Find the work done by this force on the particle as the particle moves as follows. a. From xi = 0 to xf = 10.0 m b. From xi = 10.0 to xf = 20.0 m c. From xi = 0 to xf = 20.0 m FIGURE P9.26 Problems 26 and 27.arrow_forwardA particle moves in one dimension under the action of a conservative force. The potential energy of the system is given by the graph in Figure P8.55. Suppose the particle is given a total energy E, which is shown as a horizontal line on the graph. a. Sketch bar charts of the kinetic and potential energies at points x = 0, x = x1, and x = x2. b. At which location is the particle moving the fastest? c. What can be said about the speed of the particle at x = x3? FIGURE P8.55arrow_forward
- A block of mass m = 5.00 kg is released from point and slides on the frictionless track shown in Figure P8.3. Determine (a) the blocks speed at points and and (b) the net work done by the gravitational force on the block as it moves from point to point . Figure P8.3arrow_forwardThe Flybar high-tech pogo stick is advertised as being capable of launching jumpers up to 6 ft. The ad says that the minimum weight of a jumper is 120 lb and the maximum weight is 250 lb. It also says that the pogo stick uses a patented system of elastometric rubber springs that provides up to 1200 lbs of thrust, something common helical spring sticks simply cannot achieve (rubber has 10 times the energy storing capability of steel). a. Use Figure P8.32 to estimate the maximum compression of the pogo sticks spring. Include the uncertainty in your estimate. b. What is the effective spring constant of the elastometric rubber springs? Comment on the claim that rubber has 10 times the energy-storing capability of steel. c. Check the ads claim that the maximum height a jumper can achieve is 6 ft.arrow_forwardA block is placed on top of a vertical spring, and the spring compresses. Figure P8.24 depicts a moment in time when the spring is compressed by an amount h. a. To calculate the change in the gravitational and elastic potential energies, what must be included in the system? b. Find an expression for the change in the systems potential energy in terms of the parameters shown in Figure P8.24. c. If m = 0.865 kg and k = 125 N/m, find the change in the systems potential energy when the blocks displacement is h = 0.0650 m, relative to its initial position. FIGURE P8.24arrow_forward
- A block of mass 200 g is attached at the end of a massless spring of spring constant 50 N/m. The other end of the spring is attached to the ceiling and the mass is released at a height considered to be where the gravitational potential energy is zero. (a) What is the net potential energy of the block at the instant the block is at the lowest point? (b) What is the net potential energy of the block at the midpoint of its descent? (c) What is the speed of the block at the midpoint of its descent?arrow_forwardA block of mass m = 2.50 kg is pushed a distance d = 2.20 m along a frictionless, horizontal table by a constant applied force of magnitude F = 16.0 N directed at an angle = 25.0 below the horizontal as shown in Figure P6.3. Determine the work done on the block by (a) the applied force, (b) the normal force exerted by the table, (c) the gravitational force, and (d) the net force on the block. Figure P6.3arrow_forwardA particle moves in the xy plane (Fig. P9.30) from the origin to a point having coordinates x = 7.00 m and y = 4.00 m under the influence of a force given by F=3y2+x. a. What is the work done on the particle by the force F if it moves along path 1 (shown in red)? b. What is the work done on the particle by the force F if it moves along path 2 (shown in blue)? c. What is the work done on the particle by the force F if it moves along path 3 (shown in green)? d. Is the force F conservative or nonconservative? Explain. FIGURE P9.30 In each case, the work is found using the integral of Fdr along the path (Equation 9.21). W=rtrfFdr=rtrf(Fxdx+Fydy+Fzdz) (a) The work done along path 1, we first need to integrate along dr=dxi from (0,0) to (7,0) and then along dr=dyj from (7,0) to (7,4): W1=x=0;y=0x=7;y=0(3y2i+xj)(dxi)+x=7;y=0x=7;y=4(3y2i+xj)(dyj) Performing the dot products, we get W1=x=0;y=0x=7;y=03y2dx+x=7;y=0x=7;y=4xdy Along the first part of this path, y = 0 therefore the first integral equals zero. For the second integral, x is constant and can be pulled out of the integral, and we can evaluate dy. W1=0+x=7;y=0x=7;y=4xdy=xy|x=7;y=0x=7;y=4=28J (b) The work done along path 2 is along dr=dyj from (0,0) to (0,4) and then along dr=dxi from (0,4) to (7,4): W2=x=0;y=0x=0;y=4(3y2i+xj)(dyj)+x=0;y=4x=7;y=4(3y2i+xj)(dyi) Performing the dot product, we get: W2=x=0;y=0x=0;y=4xdy+x=0;y=4x=7;y=43y2dx Along the first part of this path, x = 0. Therefore, the first integral equals zero. For the second integral, y is constant and can be pulled out of the integral, and we can evaluate dx. W2=0+3y2x|x=0;y=4x=7;y=4=336J (c) To find the work along the third path, we first write the expression for the work integral. W=rtrfFdr=rtrf(Fxdx+Fydy+Fzdz)W=rtrf(3y2dx+xdy)(1) At first glance, this appears quite simple, but we cant integrate xdy=xy like we might have above because the value of x changes as we vary y (i.e., x is a function of y.) [In parts (a) and (b), on a straight horizontal or vertical line, only x or y changes]. One approach is to parameterize both x and y as a function of another variable, say t, and write each integral in terms of only x or y. Constraining dr to be along the desired line, we can relate dx and dy: tan=dydxdy=tandxanddx=dytan(2) Now, use equation (2) in (1) to express each integral in terms of only one variable. W=x=0;y=0x=7;y=43y2dx+x=0;y=0x=7;y=4xdyW=y=0y=43y2dytan+x=0x=7xtandx We can determine the tangent of the angle, which is constant (the angle is the angle of the line with respect to the horizontal). tan=4.007.00=0.570 Insert the value of the tangent and solve the integrals. W=30.570y33|y=0y=4+0.570x22|x=0x=7W=112+14=126J (d) Since the work done is not path-independent, this is non-conservative force. Figure P9.30ANSarrow_forward
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Kinetic Energy and Potential Energy; Author: Professor Dave explains;https://www.youtube.com/watch?v=g7u6pIfUVy4;License: Standard YouTube License, CC-BY