Concept explainers
To determine: Whether ∆G is zero, or have a positive value or a negative value in a reaction in which enthalpy decreases and entropy increases.
Introduction: Under conditions of a biochemical reaction, free energy (G) is defined as the amount of energy available to perform work. Entropy is defined as degree of randomness in a system and enthalpy is defined as the total potential energy of a system.
To determine: Whether the given reaction in which enthalpy decreases and entropy increases is endergonic or exergonic.
Introduction: The
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Biology (MindTap Course List)
- Calculate the value of AG, if the value of AH is +1200 Kcal/mol, AS is +60 Kcal/mol, and the reaction takes place at 300 K. Once you calculate the value of AG, you can predict the reaction is +16800 Kcal/mol, non-spontaneous/unfavorable - 16800 Kcal/mol, spontaneous/favorable -19200 Kcal/mol, spontaneous/favorable + 19200 Kcal/mol, non-spontaneous/unfavorablearrow_forwardConsider the following chemical equation whose delta(G) = 9kcal/mol: AC + BD ---> AB + CD what are the reactants and what are the products is this reaction spontaneous? How do you know? Is energy released or consumed by this reaction? If an enzyme, which catalyzes this reaction is added, what will happen to delta (G) If this reaction is coupled to another reaction, whose delta(G) is -12 kcal/mol, what will be the net delta(G) value? will the overall reaction be spontaneousarrow_forwardThe formation of maltose, a disaccharide, from two glucose molecules, is not energetically favorable. However, if this reaction is coupled with the hydrolysis of ATP, the reaction occurs more favorably. Maltose + H2O = 2 Glucose , ΔG'o = -15.5 KJ/mol or -3.7 kcal/mol a. Determine if the coupled reaction will occur spontaneously at standard state through calculating the Gibbs Free Energy of Reaction. b. Calculate the equilibrium constant for each individual reaction, and for the coupled reaction (using free energy of reaction). Show that the equilibrium constant for the coupled reaction equals the equilibrium constants for the individual reactions multiplied together. c. If the reaction medium contains the following chemical species at their given concentrations (298 K and 1.0 atm, pH = 7.0), will the reaction proceed in the forward or the reverse direction? [Maltose] = [Glucose] = 10.0 mM; [ATP] = 5.0 mM; [ADP] = [Pi] = 20 mMarrow_forward
- What are the benefits of measuring the initial rate of a reaction Vå for use in kinetic studies? (This is a multi-select question). [ES] can be measured accurately. changes in [S] are negligible, so the value of [S] is known. changes in Km are negligible, so Km can be treated as a constant. V₁ = Vmax. --> A negligible amount of product has formed, so that the back reaction P -- need not be considered. ESarrow_forwardOne enzyme-catalyzed reaction in a biochemical cycle has an equilibrium constant that is 10 times the equilibrium constant of a second reaction. If the standard Gibbs energy of the former reaction is -300 kJ/mol, what is the standard Gibbs energy of the second reaction? Ans: -294 kJ/molarrow_forwardConsider the analogy of the jiggling box containing coins that was described on page 85. The reaction, the flipping of coins that either face heads up (h) or tails up (T), is described by the equation h ↔ T, where the rate of the forward reaction equals the rate of the reverse reaction.a. What are ΔG and ΔG° in this analogy? b. What corresponds to the temperature at which the reaction proceeds? What corresponds to the activation energy of the reaction? assume you have an “enzyme,” called jigglase, which catalyzes this reaction. What would the effect of jigglase be and what, mechanically, might jigglase do in this analogy?arrow_forward
- Calculate the change in enthalpy and the change in entropy for the above reaction. Please indicate which number is entropy and which is enthalpy in your answer Please show your calculations so I can understand what you didarrow_forwardFor the reaction A → B at 298 K, the change in enthalpy is −7 kJ · mol−1and the change in entropy is −25 J · K−1 · mol−1. Is the reaction spontaneous? If not, should the temperature be increased or decreased to make the reaction spontaneous?arrow_forwardConsider the following reaction:ATP → AMP + 2 PiCalculate the equilibrium constant (Keq) given the following ΔG°′ values:ATP → AMP + PPi (−32.2 kJ/mol)PPi → 2Pi (−33.5 kJ/mol)arrow_forward
- Consider the following process: NaCl(s) water−→−−water→ Na+(aq) + Cl-(aq); ΔH = +4.2 kJ/mol Under what conditions (temperature) would you expect this process to be spontaneous? Select a relatively high temperature and a relatively low temperature, calculate (estimate) the relative values of ΔG to support your conclusion. The entropy increases in this process Please insert an image of your workarrow_forwardWhat do the following indicators tell you about whether a reaction can proceed as written? (a) The standard free-energy change is positive. (b) The free-energy change is positive. (c) The reaction is exergonicarrow_forwardThe decomposition of crystalline N2O5 N2O5(s) → 2NO2(g) + 1/2O2(g) is an example of a reaction that is thermodynamically favored, even though it absorbs heat. At 25 °C we have the following values for the standard state enthalpy and free energy changes of the reaction: ∆H° = +109.6 kJ/mol ∆G° = -30.5 kJ/mol (a) Calculate ∆S ° at 25 °C. (b) Why is the entropy change so favorable for this reaction?arrow_forward
- Biology 2eBiologyISBN:9781947172517Author:Matthew Douglas, Jung Choi, Mary Ann ClarkPublisher:OpenStax