Concept explainers
(a)
Interpretation:
The
Concept Introduction:
Gas law provides the mathematical terms and the relationships between the amount, pressure, temperature, and volume of a gas. According to gas law the units for above four terms can be given as follows,
- The unit for amount of a gas is generally represented in terms of moles of gas percent.
- The units for volume of a gas is generally represented in terms of liter and milliliter.
- The unit for temperature of a gas is generally represented in terms of Kelvin scale.
- The unit for pressure of a gas is generally represented in terms of torr.
(b)
Interpretation:
The gas law variable the given measurement 3.70L has to be identified.
Concept Introduction:
Gas law provides the mathematical terms and the relationships between the amount, pressure, temperature, and volume of a gas. According to gas law the units for above four terms can be given as follows,
- The unit for amount of a gas is generally represented in terms of moles of gas percent.
- The units for volume of a gas is generally represented in terms of liter and milliliter.
- The unit for temperature of a gas is generally represented in terms of Kelvin scale.
- The unit for pressure of a gas is generally represented in terms of torr.
(c)
Interpretation:
The gas law variable the given measurement 173mmHg has to be identified.
Concept Introduction:
Gas law provides the mathematical terms and the relationships between the amount, pressure, temperature, and volume of a gas. According to gas law the units for above four terms can be given as follows,
- The unit for amount of a gas is generally represented in terms of moles of gas percent.
- The units for volume of a gas is generally represented in terms of liter and milliliter.
- The unit for temperature of a gas is generally represented in terms of Kelvin scale.
- The unit for pressure of a gas is generally represented in terms of torr.
(d)
Interpretation:
The gas law variable the given measurement 32.3K has to be identified.
Concept Introduction:
Gas law provides the mathematical terms and the relationships between the amount, pressure, temperature, and volume of a gas. According to gas law the units for above four terms can be given as follows,
- The unit for amount of a gas is generally represented in terms of moles of gas percent.
- The units for volume of a gas is generally represented in terms of liter and milliliter.
- The unit for temperature of a gas is generally represented in terms of Kelvin scale.
- The unit for pressure of a gas is generally represented in terms of torr.
Want to see the full answer?
Check out a sample textbook solutionChapter 7 Solutions
General, Organic, and Biological Chemistry
- For the single step reaction: A + B → 2C + 25 kJ If the activation energy for this reaction is 35.8 kJ, sketch an energy vs. reaction coordinate diagram for this reaction. Be sure to label the following on your diagram: each of the axes, reactant compounds and product compounds, enthalpy of reaction, activation energy of the forward reaction with the correct value, activation energy of the backwards reaction with the correct value and the transition state. In the same sketch you drew, after the addition of a homogeneous catalyst, show how it would change the graph. Label any new line "catalyst" and label any new activation energy.arrow_forwardHow many grams of C are combined with 3.75 ✕ 1023 atoms of H in the compound C5H12?arrow_forwarde. f. CH3O. יון Br NaOCH3 OCH 3 Br H₂Oarrow_forward
- Don't used Ai solutionarrow_forwardDon't used Ai solutionarrow_forward5. A solution of sucrose is fermented in a vessel until the evolution of CO2 ceases. Then, the product solution is analyzed and found to contain, 45% ethanol; 5% acetic acid; and 15% glycerin by weight. If the original charge is 500 kg, evaluate; e. The ratio of sucrose to water in the original charge (wt/wt). f. Moles of CO2 evolved. g. Maximum possible amount of ethanol that could be formed. h. Conversion efficiency. i. Per cent excess of excess reactant. Reactions: Inversion reaction: C12H22O11 + H2O →2C6H12O6 Fermentation reaction: C6H12O6 →→2C2H5OH + 2CO2 Formation of acetic acid and glycerin: C6H12O6 + C2H5OH + H₂O→ CH3COOH + 2C3H8O3arrow_forward
- Chemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub CoIntroductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning
- Chemistry by OpenStax (2015-05-04)ChemistryISBN:9781938168390Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark BlaserPublisher:OpenStaxChemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning