General, Organic, and Biological Chemistry
General, Organic, and Biological Chemistry
7th Edition
ISBN: 9781285853918
Author: H. Stephen Stoker
Publisher: Cengage Learning
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Chapter 7, Problem 7.45EP
Interpretation Introduction

Interpretation:

The blanks in the each row of the table by using ideal gas law at given set of conditions has to be filled.

Concept Introduction:

Ideal gas law provides the relationship between the four gas variables temperature, pressure, volume, and molar amount of a gaseous substance at specified set of conditions.  The mathematical expression for ideal gas law can be shown below,

PV=nRTWhere,P=PressureofgasV=VolumeofgasT=Temperatureofgasn=NumberofmolesofgasR=Idealgasconstant

Expert Solution & Answer
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Answer to Problem 7.45EP

At given conditions the blanks in the table is filled by using ideal gas law is,

PVnT
24.6 atm1.00 L1.00mole27oC
 a 32.8 atm2.00 L2.00 mole127oC
 b6.00 atm10.9 L4.00 mole-73oC
 c3.75 atm3.75 L0.459 mole100oC
 d1.22 atm2.00 L0.500 mole-214oC

Explanation of Solution

(a)

Record the given data,

P = ?V =2.00 Ln = 2.00 moleT = 127°C converted to 400K

Now, substitute these values in ideal gas law and do some mathematical calculation as shown in below,

PV=nRT

P=nRTV

P=(2.00mole)(0.0821atm.L/mole.K)(400K)(2.00L)=32.8atm

Therefore, the new pressure is 32.8atm.

(b)

Record the given data,

P = 6.00 atmV =?n = 4.00 moleT = -73°C converted to 200K

Now, substitute these values in ideal gas law and do some mathematical calculation as shown in below,

PV=nRT

V=nRTP

V=(4.00mole)(0.0821atm.L/mole.K)(200K)(6.00atm)=10.9L

Therefore, the new volume is 10.9L.

(c)

Record the given data,

P = 3.75atmV =3.75 Ln = ?T = 100°C converted to 373K

Now, substitute these values in ideal gas law and do some mathematical calculation as shown in below,

PV=nRT

n=PVRT

n=(3.75atm)(3.75L)(0.0821atm.L/mole.K)(373K)=0.459mole

Therefore, the number of moles is 0.459mole.

(d)

Record the given data,

P = 1.22atmV =2.00 Ln = 0.500 moleT = ?

Now, substitute these values in ideal gas law and do some mathematical calculation as shown in below,

PV=nRT

T=PVnR

T=(1.22atm)(2.00L)(0.0821atm.L/mole.K)(0.500mole)=59.43K

Now, convert the obtained Kelvin temperature into degree Celsius temperature by using the following equation,

T273

59273=214°C

Therefore, the new temperature is 214°C.

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Chapter 7 Solutions

General, Organic, and Biological Chemistry

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