Principles of Instrumental Analysis
7th Edition
ISBN: 9781305577213
Author: Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher: Cengage Learning
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Chapter 7, Problem 7.3QAP
The Wien displacement law states that the wavelength maximum in micrometers for blackbody radiation isgiven by the relationship
where T is the temperature in kelvins. Calculate the wavelength maximum for a blackbody that has been heated to (a) 4500 K, (b) 250 K, and (c) 1250 K.
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The maximum kinetic energy of photoelectrons ejected from a tungsten metal surface by monochromatic light of wavelength 248nm was found to be 8.6 × 10-20 J. Calculate:(i.) The work function of tungsten in electron volt (eV),
(ii.) the threshold frequency of tungsten.
(c) The kinetic energy, K, of electrons emitted from a metal surface after irradiation
with UV light of wavelength is given by:
Kg =
hc
$
where h is Planck's constant (6.626 x 10-4 Js), c is the speed of light in a vacuum
(2.99 × 108 m s¹), and is the work function of the metal surface.
In a specific experiment, light with a wavelength of 266 nm was used to irradiate a
cadmium (Cd) metal surface.
(1)
Calculate the photon energy of the light used in the experiment, in Joules.
(II) The work function for cadmium is 4.08 eV. Calculate the kinetic energy of the
emitted electrons.
[Note: 1 eV = 1.60 × 10-19 J.)
(iii) The work function for scandium is 5.61 x 10-19 J. Calculate the wavelength of
the lowest energy photon that would cause emission of electrons from a
scandium surface.
(iv) Irradiation of scandium with 335 nm light results in electrons emitted with a
kinetic energy of 3.20 x 10-19 J. Calculate the de Broglie wavelength of the
emitted electrons.
The work function of metallic caesium is 2.14 eV. Calculate the kinetic energy and the speed of the electrons ejected by light of wavelength (i) 700 nm, (ii) 300 nm.
Chapter 7 Solutions
Principles of Instrumental Analysis
Ch. 7 - Prob. 7.1QAPCh. 7 - Prob. 7.2QAPCh. 7 - The Wien displacement law states that the...Ch. 7 - Prob. 7.4QAPCh. 7 - Prob. 7.5QAPCh. 7 - Describe the differences and similarities between...Ch. 7 - Prob. 7.7QAPCh. 7 - Prob. 7.8QAPCh. 7 - Prob. 7.9QAPCh. 7 - Prob. 7.10QAP
Ch. 7 - Why is glass better than fused silica as a prism...Ch. 7 - Prob. 7.12QAPCh. 7 - Prob. 7.13QAPCh. 7 - Prob. 7.14QAPCh. 7 - Prob. 7.15QAPCh. 7 - Prob. 7.16QAPCh. 7 - Prob. 7.17QAPCh. 7 - Prob. 7.18QAPCh. 7 - Prob. 7.19QAPCh. 7 - Prob. 7.20QAPCh. 7 - Prob. 7.21QAPCh. 7 - Prob. 7.22QAPCh. 7 - Prob. 7.23QAPCh. 7 - Prob. 7.24QAP
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