Classify each alkyl halide as 1 °, 2°, or 3°.

Question

Want to see more full solutions like this?

Answer 1

Textbook Question

Chapter 7, Problem 7.1P

Classify each alkyl halide as 1 °, 2°, or 3°.

Chapter 7, Problem 7.1P, Classify each alkyl halide as 1 , 2, or 3.

Expert Solution

Interpretation Introduction

(a)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

CH₃CH₂CH₂CH₂CH₂-Br---➜ primary (1°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

CH₃CH₂CH₂CH₂CH₂-Br---➜ in this structure only one carbon attached to carbon with halogen so primary (1°)

Conclusion

Thus the given structure is primary (1°)

Expert Solution

Interpretation Introduction

(b)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

Organic Chemistry, Chapter 7, Problem 7.1P , additional homework tip 1 ------------➜ tertiary (3°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

Organic Chemistry, Chapter 7, Problem 7.1P , additional homework tip 2 ---➜ in this structure three carbons attached to carbon with halogen so primary (1°)

Conclusion

Thus the given structure is tertiary (3°)

Expert Solution

Interpretation Introduction

(c)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

Organic Chemistry, Chapter 7, Problem 7.1P , additional homework tip 3 ------------➜ secondary (2°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

Organic Chemistry, Chapter 7, Problem 7.1P , additional homework tip 4

---➜ in this structure two carbons attached to carbon with halogen so secondary (2°)

Conclusion

Thus the given structure is secondary (2°)

Expert Solution

Interpretation Introduction

(d)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

------------➜ tertiary (3°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

---➜ in this structure three carbons attached to carbon with halogen so tertiary (3°)

Conclusion

Thus the given structure is tertiary (3°)

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

H3C. H3C CH3 Br 1-propanol

Organic Reaction Write an equation for the oxidation of each alcohol. Use [O] above the arrow to indicate an oxidizing agent. If no reaction occurs, write "no reaction" after the arrow. 1. CH3CH2CH2CH2CH2OH CH₂ CH₂CCH₂CH₂ ОН CH CHCH CH CH CH, ОН

1. Simple ketones, like acetone, are often used as industrial solvents for many organically based products such as adhesives and paints. They are considered "universal solvents," because they dissolve so many diverse materials. Explain why these chemicals are good solvents.

Answer 2

Textbook Question

Chapter 7, Problem 7.1P

Classify each alkyl halide as 1 °, 2°, or 3°.

Chapter 7, Problem 7.1P, Classify each alkyl halide as 1 , 2, or 3.

Expert Solution

Interpretation Introduction

(a)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

CH₃CH₂CH₂CH₂CH₂-Br---➜ primary (1°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

CH₃CH₂CH₂CH₂CH₂-Br---➜ in this structure only one carbon attached to carbon with halogen so primary (1°)

Conclusion

Thus the given structure is primary (1°)

Expert Solution

Interpretation Introduction

(b)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

Organic Chemistry, Chapter 7, Problem 7.1P , additional homework tip 1 ------------➜ tertiary (3°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

Organic Chemistry, Chapter 7, Problem 7.1P , additional homework tip 2 ---➜ in this structure three carbons attached to carbon with halogen so primary (1°)

Conclusion

Thus the given structure is tertiary (3°)

Expert Solution

Interpretation Introduction

(c)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

Organic Chemistry, Chapter 7, Problem 7.1P , additional homework tip 3 ------------➜ secondary (2°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

Organic Chemistry, Chapter 7, Problem 7.1P , additional homework tip 4

---➜ in this structure two carbons attached to carbon with halogen so secondary (2°)

Conclusion

Thus the given structure is secondary (2°)

Expert Solution

Interpretation Introduction

(d)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

------------➜ tertiary (3°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

---➜ in this structure three carbons attached to carbon with halogen so tertiary (3°)

Conclusion

Thus the given structure is tertiary (3°)

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Textbook Question

Chapter 7, Problem 7.1P

Classify each alkyl halide as 1 °, 2°, or 3°.

Chapter 7, Problem 7.1P, Classify each alkyl halide as 1 , 2, or 3.

Expert Solution

Interpretation Introduction

(a)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

CH₃CH₂CH₂CH₂CH₂-Br---➜ primary (1°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

CH₃CH₂CH₂CH₂CH₂-Br---➜ in this structure only one carbon attached to carbon with halogen so primary (1°)

Conclusion

Thus the given structure is primary (1°)

Expert Solution

Interpretation Introduction

(b)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

Organic Chemistry, Chapter 7, Problem 7.1P , additional homework tip 1 ------------➜ tertiary (3°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

Organic Chemistry, Chapter 7, Problem 7.1P , additional homework tip 2 ---➜ in this structure three carbons attached to carbon with halogen so primary (1°)

Conclusion

Thus the given structure is tertiary (3°)

Expert Solution

Interpretation Introduction

(c)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

Organic Chemistry, Chapter 7, Problem 7.1P , additional homework tip 3 ------------➜ secondary (2°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

Organic Chemistry, Chapter 7, Problem 7.1P , additional homework tip 4

---➜ in this structure two carbons attached to carbon with halogen so secondary (2°)

Conclusion

Thus the given structure is secondary (2°)

Expert Solution

Interpretation Introduction

(d)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

------------➜ tertiary (3°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

---➜ in this structure three carbons attached to carbon with halogen so tertiary (3°)

Conclusion

Thus the given structure is tertiary (3°)

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Textbook Question

Chapter 7, Problem 7.1P

Classify each alkyl halide as 1 °, 2°, or 3°.

Chapter 7, Problem 7.1P, Classify each alkyl halide as 1 , 2, or 3.

Expert Solution

Interpretation Introduction

(a)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

CH₃CH₂CH₂CH₂CH₂-Br---➜ primary (1°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

CH₃CH₂CH₂CH₂CH₂-Br---➜ in this structure only one carbon attached to carbon with halogen so primary (1°)

Conclusion

Thus the given structure is primary (1°)

Expert Solution

Interpretation Introduction

(b)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

Organic Chemistry, Chapter 7, Problem 7.1P , additional homework tip 1 ------------➜ tertiary (3°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

Organic Chemistry, Chapter 7, Problem 7.1P , additional homework tip 2 ---➜ in this structure three carbons attached to carbon with halogen so primary (1°)

Conclusion

Thus the given structure is tertiary (3°)

Expert Solution

Interpretation Introduction

(c)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

Organic Chemistry, Chapter 7, Problem 7.1P , additional homework tip 3 ------------➜ secondary (2°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

Organic Chemistry, Chapter 7, Problem 7.1P , additional homework tip 4

---➜ in this structure two carbons attached to carbon with halogen so secondary (2°)

Conclusion

Thus the given structure is secondary (2°)

Expert Solution

Interpretation Introduction

(d)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

------------➜ tertiary (3°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

---➜ in this structure three carbons attached to carbon with halogen so tertiary (3°)

Conclusion

Thus the given structure is tertiary (3°)

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

Expert Solution

Interpretation Introduction

(a)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

CH₃CH₂CH₂CH₂CH₂-Br---➜ primary (1°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

CH₃CH₂CH₂CH₂CH₂-Br---➜ in this structure only one carbon attached to carbon with halogen so primary (1°)

Conclusion

Thus the given structure is primary (1°)

Expert Solution

Interpretation Introduction

(b)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

Organic Chemistry, Chapter 7, Problem 7.1P , additional homework tip 1 ------------➜ tertiary (3°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

Organic Chemistry, Chapter 7, Problem 7.1P , additional homework tip 2 ---➜ in this structure three carbons attached to carbon with halogen so primary (1°)

Conclusion

Thus the given structure is tertiary (3°)

Expert Solution

Interpretation Introduction

(c)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

Organic Chemistry, Chapter 7, Problem 7.1P , additional homework tip 3 ------------➜ secondary (2°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

Organic Chemistry, Chapter 7, Problem 7.1P , additional homework tip 4

---➜ in this structure two carbons attached to carbon with halogen so secondary (2°)

Conclusion

Thus the given structure is secondary (2°)

Expert Solution

Interpretation Introduction

(d)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

------------➜ tertiary (3°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

---➜ in this structure three carbons attached to carbon with halogen so tertiary (3°)

Conclusion

Thus the given structure is tertiary (3°)

Answer 8

Expert Solution

Interpretation Introduction

(a)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

CH₃CH₂CH₂CH₂CH₂-Br---➜ primary (1°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

CH₃CH₂CH₂CH₂CH₂-Br---➜ in this structure only one carbon attached to carbon with halogen so primary (1°)

Conclusion

Thus the given structure is primary (1°)

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Interpretation Introduction

(a)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer 13

Answer to Problem 7.1P

CH₃CH₂CH₂CH₂CH₂-Br---➜ primary (1°)

Answer 14

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

CH₃CH₂CH₂CH₂CH₂-Br---➜ in this structure only one carbon attached to carbon with halogen so primary (1°)

Answer 15

Conclusion

Thus the given structure is primary (1°)

Answer 16

Expert Solution

Interpretation Introduction

(b)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

Organic Chemistry, Chapter 7, Problem 7.1P , additional homework tip 1 ------------➜ tertiary (3°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

Organic Chemistry, Chapter 7, Problem 7.1P , additional homework tip 2 ---➜ in this structure three carbons attached to carbon with halogen so primary (1°)

Conclusion

Thus the given structure is tertiary (3°)

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

Expert Solution

Answer 20

Interpretation Introduction

(b)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer 21

Answer to Problem 7.1P

Organic Chemistry, Chapter 7, Problem 7.1P , additional homework tip 1 ------------➜ tertiary (3°)

Answer 22

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

Organic Chemistry, Chapter 7, Problem 7.1P , additional homework tip 2 ---➜ in this structure three carbons attached to carbon with halogen so primary (1°)

Answer 23

Conclusion

Thus the given structure is tertiary (3°)

Answer 24

Expert Solution

Interpretation Introduction

(c)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

Organic Chemistry, Chapter 7, Problem 7.1P , additional homework tip 3 ------------➜ secondary (2°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

Organic Chemistry, Chapter 7, Problem 7.1P , additional homework tip 4

---➜ in this structure two carbons attached to carbon with halogen so secondary (2°)

Conclusion

Thus the given structure is secondary (2°)

Answer 25

Expert Solution

Answer 26

Expert Solution

Answer 27

Expert Solution

Answer 28

Interpretation Introduction

(c)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer 29

Answer to Problem 7.1P

Organic Chemistry, Chapter 7, Problem 7.1P , additional homework tip 3 ------------➜ secondary (2°)

Answer 30

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

Organic Chemistry, Chapter 7, Problem 7.1P , additional homework tip 4

---➜ in this structure two carbons attached to carbon with halogen so secondary (2°)

Answer 31

Conclusion

Thus the given structure is secondary (2°)

Answer 32

Expert Solution

Interpretation Introduction

(d)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

------------➜ tertiary (3°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

---➜ in this structure three carbons attached to carbon with halogen so tertiary (3°)

Conclusion

Thus the given structure is tertiary (3°)

Answer 33

Expert Solution

Answer 34

Expert Solution

Answer 35

Expert Solution

Answer 36

Interpretation Introduction

(d)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer 37

Answer to Problem 7.1P

------------➜ tertiary (3°)

Answer 38

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

---➜ in this structure three carbons attached to carbon with halogen so tertiary (3°)